can I ask you a question? I solved this problem by making supermesh with loop 1 and 2. My question is how loop 3 can also combined as supermesh? I tried both way, yours and mine. These two ways both can make the correct answer but how is this possible? btw thank you for the excellent videos
Question for node B. If the 1 ohm resistor between the 4 amp souce and node B was something else like a 5 ohm resistor for example, would that affect anything? Would it still be i1 - i2 = 4 ?
First thank you for the video second, I have a question : the super loop u took passed from the 2 ohm resistor path not the other path with the resistors 2 ohm then 4 ohm is not that contradict with the definition of super mesh?
I have the doubt, according to what the book explains, the super tie should be formed by the union of the ties that contain i1 and i2, but not i3, could you explain?
@@ArdiSatriawan Branh current method results loop current : I1 = 4.4 A, I2 = 0.4 A and I3 = 2.4 A and those fulfill exactly the value of source voltage. But it is considered wrong. Why ? Because KVL doesn't work.on branch which contains current source.
@@remigiustandioga7774 KVL works on any circuits, we just can't determine the voltage when it is current source. Btw, bapak dosen juga kan ya? Kita kolega kalau begitu. Saya di Teknik Elektro ITB Pak..
Now I’m practising yr nodal analysis exercises. Some passive sign is different as what I conceived but anyway it’s ok..main thing is yr step is quite easy to follow