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Precipitation Reactions - Using the Solubility Rules 

Ben's Chem Videos
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Basic idea of precipitation reactions. NOTE: when working with precipitation reactions, the solubility rules for ionic compounds are used to determine if a precipitate forms or not.
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15 окт 2024

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Комментарии : 170   
@Sledge_369
@Sledge_369 10 лет назад
My left ear really enjoyed this
@payamsobhanian1616
@payamsobhanian1616 5 лет назад
?
@grenashihatake5643
@grenashihatake5643 3 года назад
lmao relatable (only if u wear headphones)
@adeladadoll
@adeladadoll 7 месяцев назад
LMAO
@lucasthethird
@lucasthethird 7 лет назад
Ben--I have watched about two hours' worth of videos explaining precipitation reactions, aqueous solutions, net ionic equations, and so on. Yours is by far--and I mean by FAR!--the clearest and easiest to understand, with the most well-laid out and clarified examples. Thank you so much!
@BensChemVideos
@BensChemVideos 7 лет назад
Thanks Luke. Means the world to read such a kind comment!
@wholcikedme
@wholcikedme 10 лет назад
its so awkward how much better this guy is than my actual teacher who has way more resources 10/10
@paisley4092
@paisley4092 9 лет назад
In response to you your name: i did
@wholcikedme
@wholcikedme 9 лет назад
Liam Copich dammit liam!!XD
@phodacbitch
@phodacbitch 9 лет назад
do u give ur teacher handies in the closet
@rachellaizprua-sanchez9017
@rachellaizprua-sanchez9017 9 лет назад
without your videos i would not be passing chem! thank you!
@johngraham2186
@johngraham2186 4 года назад
Thanks Ben! You're still helping students 9 years later! Very helpful!
@BensChemVideos
@BensChemVideos 4 года назад
Thank you for your kind words, and thanks for watching! 😀
@AJay121096
@AJay121096 10 лет назад
Thanks so much! I'm having the hardest time in Chemistry, and I've been having to look up a lot of "How to" videos. Thanks for making things simple and easy to understand! :]
@anaruthalfaro4101
@anaruthalfaro4101 9 лет назад
Bless your soul, soooo helpful!!
@Finnbrack
@Finnbrack 9 лет назад
I had no idea how precipitation reactions worked before watching this video, pretty darn confident now, god bless you, sir.
@anekashah7210
@anekashah7210 2 года назад
Thank you so much!!! Had to identify precipitates on my test without even being taught the solubility rules! Looked up a ton of videos and was losing hope until I stumbled across yours. By far, the absolute best!!!! Thanks so much from India!!!
@BensChemVideos
@BensChemVideos 2 года назад
You're very welcome! Thanks so much for your kind words 😀
@wholcikedme
@wholcikedme 10 лет назад
THANK GOD FOR THIS VIDEO
@demonchild11m
@demonchild11m 9 лет назад
you mean to say thank ben. and his chem videos
@wholcikedme
@wholcikedme 9 лет назад
***** hahaha true
@orangejuice6956
@orangejuice6956 9 лет назад
+Marco Hernandez ben is god
@Marcopolo_02
@Marcopolo_02 6 лет назад
Its now 2018 and this video has still proven to be useful thanks
@diiianalu
@diiianalu 12 лет назад
Thank you soooooo much. DO NOT stop making these videos.
@Tech-sci89109
@Tech-sci89109 6 дней назад
It is incredibly helpful to my carrier 😂😂😂😂😂😂😂😂😂😂😂😂😂
@TheCrazyStats
@TheCrazyStats 11 лет назад
Thank you. I finally understand precipitate much better
@zaingodinagh572
@zaingodinagh572 10 лет назад
Thanks so much better than my science teacher
@JC-eb1pv
@JC-eb1pv 12 лет назад
I really appreciate these study aids. Thank you for investing your time to make this!
@Pratyus_C
@Pratyus_C 3 года назад
Are you there ?
@georginahassell3487
@georginahassell3487 9 лет назад
Oh my gosh thank you thank you thank you 4 teachers and multiple friends have tried to explain this to me and didn't succeed but in a short 10m you did!
@28princesst
@28princesst 11 лет назад
Thanku so much, you make it seem so easy, and yes our teacher is making us memorize that hold chart, along with limiting reactant problems, and finding the emperical formulas from the limiting reactant, and oxidation-reduction rules, not to mention all of the Gas Laws. Some body please pray for me and my classmates!!! But i thankyou for helping me with a clear understanding of precipitaion reactions. Sorry for the paragraph but i had to vent to someone lol
@naomibodner8658
@naomibodner8658 5 лет назад
Great video. You made what seemed a very complex part of the chapter very straightforward, easy, and fun. Thank you.
@tropicallymixed.
@tropicallymixed. 3 года назад
THANK YOU!!!!!!!!!! Anyone reading this, WATCH THIS VIDEO, he explains it well!
@BensChemVideos
@BensChemVideos 3 года назад
You're very welcome! Thanks for watching 😀
@janettomeally3377
@janettomeally3377 10 лет назад
OMGOSH YOU ARE AMAZING, I HAVE A TEXT ON TUESDAY AND THANKS TO YOU I AM SO CONFIDENT! !!!! THANKS 👍👍👍
@Hshidmzajdmz
@Hshidmzajdmz 11 лет назад
Test tomorrow and don't even need to read notes on this..... U explained in 10
@chipnwafersticks
@chipnwafersticks 6 лет назад
Thanks for this. It helped me. I have a reporting in our chem. class tomorrow and I need to discuss this and double displacement reaction. If not for this video, I wouldn't understand precipitation reaction.
@LittleMixOf1D
@LittleMixOf1D 9 лет назад
thank you :) hopefully on the day of my exam(which is tomorrow) I won't forget!!
@SlendermenGames
@SlendermenGames 9 лет назад
+LittleMixOf1D DId you pass lol?
@misty348
@misty348 11 лет назад
that was a huge help !!
@vaniasegura8360
@vaniasegura8360 8 лет назад
Thank you so much! Your explanation is so clear.
@Salama7856
@Salama7856 2 года назад
Thanks a lot, I would say you did better than my teacher that toke two class to explain all of that.
@BensChemVideos
@BensChemVideos 2 года назад
You're very welcome 😃
@barcalover2988
@barcalover2988 9 лет назад
Thank you sir! You saved my exam :))
@Rogerrabbit007rb
@Rogerrabbit007rb 10 лет назад
Best explanation!
@sparklyyredshoes
@sparklyyredshoes 12 лет назад
your videos are very helpful for my chemistry midterm tomorrow. thanks, bud :)
@lorasingun2651
@lorasingun2651 8 лет назад
Thanks very much for uploading this video. It helped me with my take home exam.
@bactwostudying
@bactwostudying 12 лет назад
Thank you. Greatly appreciate the clear explanations and colors. Finally Got!!!
@alisonhendrix
@alisonhendrix 11 лет назад
Awesome, thanks! Taking chem online and have to learn on my own from the book (tests are done in person on campus but everything else is on our own) and was having a lot of trouble understanding what I was reading. This has helped clear up a lot of my confusion.
@minixdee
@minixdee 6 лет назад
Thanks for throwing me this life jacket...
@trayzzay85
@trayzzay85 13 лет назад
QUESTION!!!!! doesn't the last equation 9:55 have to balance yet? Since it isn't balanced will that affect the outcome? I don't see how it would. IDK
@YoshiHDify
@YoshiHDify 12 лет назад
Is there an easy way to remember the rules. Because in an exam they won't be giving you a clue or any rule sheet. Or do we just have to dead set remember them?
@xkarnx2355
@xkarnx2355 3 года назад
I wanted to ask from that last question that's Na2SO4 + KCl. When switching how come that so4 doesn't come first and having to determine if it is aqueous or not. Should it be So4K(aq)?
@CandaceRain
@CandaceRain 11 лет назад
MAN YOU ARE THE BEST!!! THANKS!!
@drpthemc
@drpthemc 12 лет назад
you're the best. thanks so much for these videos.
@karapaige9072
@karapaige9072 10 лет назад
This was such a big help! Thank you!
@freepalestine1062
@freepalestine1062 3 года назад
Thanks man Great video Amazing explanation Examples were very helpful
@BensChemVideos
@BensChemVideos 3 года назад
You're very welcome! Thank you for your kind words! 😀
@freepalestine1062
@freepalestine1062 3 года назад
@@BensChemVideos wouldn't have said it if I didn't mean it Seriously helped a lot Thank you
@ManuelMaciasHouTex
@ManuelMaciasHouTex 9 лет назад
why did you swap the NO3 and the Br and how do we know whether it is to be swapped or not?
@BensChemVideos
@BensChemVideos 13 лет назад
Water is a liquid, so we use (l). Soluble ionic compounds dissociate in water, so we use (aq) for aqueous. Insoluble ionic compounds do not dissociate in water, so we use (s) for solid. Even if an ionic compound is soluble, if it's not in water then it's usually a solid at room temperature, in which case (s) would be appropriate.
@ArtgirlRusher776
@ArtgirlRusher776 11 лет назад
This makes so much sense! Thank you.
@lovedog49507
@lovedog49507 12 лет назад
If the compound has a group 1 element is it automatically soluble ?
@simphiweciliza4727
@simphiweciliza4727 10 лет назад
Thanks man. Helped me BIG TIME!
@hallcory1993
@hallcory1993 11 лет назад
If you look at the periodic table of the elements, whatever column that the element is in correlates if it is positive or negative.
@mehreenroyker1361
@mehreenroyker1361 7 лет назад
thank the lord i uderstood since im writing chem tomorro
@arularasu1333
@arularasu1333 7 лет назад
Super .... Your voice is bold.
@JustrandomvideosIlik
@JustrandomvideosIlik 12 лет назад
Thanks for being a cool dude and uploading this.
@shiitake9468
@shiitake9468 8 лет назад
you just saved me. Thank you!
@molly1376
@molly1376 8 лет назад
Why do the pairs switch in the reactions? As in, why are the cations of the reactants paired with the anions they weren't with initially, for the products? Sorry if my question is unclear but this is something I am having trouble understanding.
@elishasantos582
@elishasantos582 7 лет назад
Molly Koch Its a chemical reaction called Double Displacement.
@harman2267
@harman2267 12 лет назад
This video is the exact video i am looking for! :D
@ALananhR
@ALananhR 12 лет назад
Would it be possible for you to do a video(if you have not already) on writing a balanced formula equation, complete ionic equation, and writing a net ionic equation? I am learning it in class, and I am totally and completely lost
@parveenshaikh4136
@parveenshaikh4136 Год назад
Why the concentrations of the two solution in a precipitation reactions are different?
@pauldargan8995
@pauldargan8995 6 лет назад
But the main question that none of these videos address is why the new compounds form - rather than reforming the original compounds? Is it an enthalpic or entropic reason?
@wildhogz000
@wildhogz000 11 лет назад
thankyou so much.. i actually understand now
@roykilof5204
@roykilof5204 8 лет назад
This helped a lot! Thank you!!!
@ComandaKronikk
@ComandaKronikk 7 лет назад
Thanks Ben, u are the man
@Dan-gc3ke
@Dan-gc3ke 7 лет назад
If one of them is insoluble, then no reaction would occur right?
@TheVegasMatt
@TheVegasMatt 12 лет назад
Thank you thank you thank you!
@GoodNewsForStrangers
@GoodNewsForStrangers 8 лет назад
This is excellent. thank you
@gidielle13
@gidielle13 12 лет назад
thanks a lot.. ive seen your other videos and they're really helpful!
@ryanramlogan6512
@ryanramlogan6512 7 лет назад
In the last example no precipitate was formed but the cations and anions still switched, why is that considered no reaction?
@elishasantos582
@elishasantos582 7 лет назад
Ryan Ramlogan I think its not right to say that they dont have reaction. They have reaction but not precipitation reaction because you do not produce a solid precipitate.
@RicardoKaka01
@RicardoKaka01 12 лет назад
Just a small mistake, for the final equation on 10:27, there should be 2 moles of KCl and 2 moles of NaCl so that it balances out the equation. You need to have 2 K, 2 Cl, and 2 Na on both sides for it to be balanced.
@renee7880
@renee7880 9 лет назад
Sorry, I am new to this. Where did the the 2 go from Na in the last example?
@Icecube88
@Icecube88 9 лет назад
+LZLZLZ ZEE it's because you want it to be in its simplest form. you can reduce Na2Cl2 to NaCl if you divide both by 2. it's in empirical form. I'm guessing you want the compounds in that form when you do this stuff. N2Cl2 is in molecular form.
@Icecube88
@Icecube88 9 лет назад
+Icecube88 yeah, make sure you balance the compounds when you put the elements together. if they can be reduced, then you reduce. Pb(C2H3O2)2 + Na2SO4 for example. You pair up Pb and SO4. They are balanced, so move on. You pair Na2 and (C2H3O2)2. Acetate (C2H3O2) has a charge of 1-, and there are two of them. Na has a charge of 1+, and there are two of them, so they are balanced. Since they can be simplified though, you simplify them. You can divide both by 2, and that will give you Na(C2H3O2). That's the compound that you will use. So the whole thing together is PbSO4 + Na(C2H3O2). Then you go from there (if they are soluble or not and so on. Well I want to add that when you do go on from there, you will find that it is a precipitation reaction.
@Icecube88
@Icecube88 9 лет назад
also, you can't reduce polyatomic ions. only if they are in parenthesis (indicating that there are more than one) can you reduce a polyatomic ion..if you get something like Na2SO4 paired up together, then you keep it like that. that's sodium sulfate. sulfate is SO4 with a 2- charge and sodium is Na with a 2+ charge. If you get Na4(SO4)2, then you can reduce it to Na2SO4. notice that the polyatomic ion hasn't changed, so you're good.
@bobdan103
@bobdan103 12 лет назад
If I pass my chem 103 test today I'm subscribing.
@JustBeFancy
@JustBeFancy 11 лет назад
Great video. Very helpful!
@oanaghiban6896
@oanaghiban6896 12 лет назад
awesome! I understood EVERYTHING so CLEAR!! I wish you were my teacher:)!
@Pratyus_C
@Pratyus_C 3 года назад
Hey ! You there still now ?
@ipaad
@ipaad 13 лет назад
Thanks for the help.
@myst4216
@myst4216 11 лет назад
Very helpful! Thanks!
@marineboy71
@marineboy71 11 лет назад
This helped me soo much thank you
@richmonsapitula5618
@richmonsapitula5618 5 лет назад
Thank a lot ser!
@aawazkipyaas3079
@aawazkipyaas3079 3 года назад
very informative
@aru1796
@aru1796 5 месяцев назад
finally understood something tnx
@BensChemVideos
@BensChemVideos 5 месяцев назад
You're very welcome 😀
@charlielewis5893
@charlielewis5893 9 лет назад
what if both solutions produced are insoluble?
@rixon3984
@rixon3984 5 лет назад
Then both are precipitates
@Sarah-ch5vw
@Sarah-ch5vw 4 года назад
@@rixon3984 I love how you answered despite being 5 yrs late lmao
@naadirahbrewster2121
@naadirahbrewster2121 4 года назад
Thank you!
@jamoltrevor
@jamoltrevor 9 лет назад
THANK YOU SIRRR !
@MagentaFerret
@MagentaFerret 9 лет назад
OMG I GET IT!!!!! MIND BLOOWWWNNNNNNNNNNN
@abbassyed0
@abbassyed0 11 лет назад
Appreciate it. Very helpful.
@wadehamilton5084
@wadehamilton5084 11 лет назад
Great video
@elizabethherzl3671
@elizabethherzl3671 5 лет назад
YOU ARE AWESOME
@TheMsg911
@TheMsg911 12 лет назад
Many thanks, my parents included.
@sugreevsran766
@sugreevsran766 5 лет назад
thanks ben
@gdkloxius
@gdkloxius 7 месяцев назад
Lifesaver!
@hebakafina6538
@hebakafina6538 8 лет назад
so do i have to memorize the rules for my exams?
@jessy3038
@jessy3038 8 лет назад
If you're in AP chemistry you have to (I only know about AP because i'm taking it right now)
@hebakafina6538
@hebakafina6538 8 лет назад
thank you :)
@eve_love22
@eve_love22 10 лет назад
Thank you!!!
@perfect204
@perfect204 11 лет назад
Awesome vid
@gabbyytname
@gabbyytname 11 лет назад
THANK YOU!!!!!!!!
@juliuscaesar3988
@juliuscaesar3988 9 лет назад
THANkS SO MUCH!!!!!
@mattv11900
@mattv11900 11 лет назад
No, because Na is a 1+ charge and there's two of them, and Cl is ALWAYS diatomic (which means it exists in two) and also has a 1+ charge. So Na2Cl2 is just NaCl. :)
@johnnyappleseed4020
@johnnyappleseed4020 8 лет назад
thank you!
@mdsarwar4985
@mdsarwar4985 5 лет назад
Very good 👍 👍 txxx
@shinsekai1
@shinsekai1 8 лет назад
thank you
@breadgenie1232
@breadgenie1232 2 года назад
8:33 Wait why is there a 2 next to the sodium
@dylanjohnson2395
@dylanjohnson2395 8 лет назад
How come in Example 3, you don't need the equation to be balanced?
@elishasantos582
@elishasantos582 7 лет назад
Dylan Johnson There's no need to balance the equation for that case because we are just trying to figure out if those reactants would produce a solid precipitate or not. We need to balance equation if we are solving stoichiometry problems..
@sydney101luigi
@sydney101luigi 12 лет назад
Don't you have to balance the last equation?
@toshikosatoru8483
@toshikosatoru8483 9 лет назад
At 3:47 Ag+Cl=AgCl, because of "AG" it is insoluble, than in AG + CL why is AG classified as Soluble?
@MsMondaymornings
@MsMondaymornings 9 лет назад
Toshiko Satoru On the reactants side, Ag and Cl are seperate, when they combine on the product side the solid is formed because compounds containing Cl Br and I are soluble except when they are combined with Ag, Hg or Pb.
@toshikosatoru8483
@toshikosatoru8483 9 лет назад
Serena Mallavarapu So Silver alone is Soluble?
@MsMondaymornings
@MsMondaymornings 9 лет назад
Yeah, silver alone is soluble. It's not in a compound on the reactants side.
@toshikosatoru8483
@toshikosatoru8483 9 лет назад
Cheers
@instaminox
@instaminox 8 лет назад
excellent
@anthonyheppr
@anthonyheppr 11 лет назад
Top man
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