thank you madam, you explanation was very easy to understand. but i am afraid that at 12:05 'f' should be connected with 'e', you said that exactly though.
I have tomorrow exam and I searched for prims algorithm in many videos and still was confusing, this video opened accidentally but its the best pakka 7 marks 😅 thanks ma'am 😊
Prim's algorithm yields the minimum spanning tree only when there are unique edge weights. The way she explained is correct. However, for this graph (where there are 2 edges with the same weight bd and ac), Kruskal's algorithm is the efficient one. She could have chosen to use unique edge weights. Kruskal's would give you 22 as you mentioned 👍
Yes but you have to see from visited vertice and after visiting f to g only one path remains to e , thatwhy we have to visit g to e .. because in prims we can't go back after visiting any vertice...I hope so ...
remove this video please , its not correct 1. teaching the wrong code 2. uploading the lecture video 3. not removing the video coz of views 4. result : dislike the video and unsubscribe
Algorithm bolta hai select unvisited vertex which is adjacent of visited vertices isiye g to e hoga kyuki f se to g tak visited ho chuka hain phir f kaise hoga
## Attention guys: sorry ma'am but what u have demonstrated is not totally right. u said edges with minimum weight can be taken only from the latest visited vertex. but it can be taken from any visited vertex. I request u to recheck it. thank u
Guys - Prim's algorithm yields the minimum spanning tree only when there are unique edge weights. The way she explained is correct. However, for this graph (where there are 2 pairs of edges with the same weights bd, ac and bc,df), Kruskal's algorithm is the efficient one. She could have chosen to use unique edge weights. Kruskal's would give you 22 as many of you mentioned
we will get 22 in this method as well .In the last step the edges should be {f,e) and not {g,e}, because {f,e} has weight 5 which is less than 6 of {g,e}
Thanks for posting this video, please check your answer as I also got 22 here are my chosen edges - ab(4), ac(8),cd(2),cf(1),ef(5) , fg(2); why choose eg instead of ef? ef has the lesser weight by 1.
No it is correct what she said in this there should be least no if u have said Thai it for should be connected to e and g but first we have to check least value i.e f to e it has 5 and f to g it has 2 minimum so we have to take f to g so what she said is right
