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Prim's Minimum Spanning Tree Algorithm | Graph Theory 

WilliamFiset
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2 окт 2024

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Комментарии : 65   
@anindyasur5070
@anindyasur5070 2 года назад
Thanks for making it super easy to understand. I am super lucky that I found your channel among the pile.
@99progers
@99progers 4 года назад
Do you know what the scariest think in the world is >??
@astroash
@astroash 4 года назад
No, and I don't even know how to reverse a linked list.
@mechy6065
@mechy6065 4 года назад
not knowing how to invert a binary tree?
@dannyfogel9156
@dannyfogel9156 4 года назад
Thank you so much!!! learning algorithms from a book in the university is really hard and your videos are super helpful!!
@mechy6065
@mechy6065 4 года назад
don't use my display picture please
@user-wc1sm8cj8s
@user-wc1sm8cj8s 3 года назад
@@mechy6065 Is this a coincidence?? LOL
@gtab1268
@gtab1268 3 года назад
@Kohen Kaden hmmmmmmmm
@Akiruu_Sama
@Akiruu_Sama 2 года назад
exactly the same
@MykolaDolgalov
@MykolaDolgalov 4 года назад
I'm so glad I found your channel! Thank you so much for your hard work!
@captain-ramen
@captain-ramen 2 года назад
This explanation is so good! Understanding this algorithm is already hard, and coding the solution up is difficult on another level. I tried reading the code on different websites and in different videos, and I had a hard time understanding it. However, you example, visualization and clean code made me understand everything in less than 20 minutes. Thank you so much!!!
@yasharthgupta9002
@yasharthgupta9002 2 года назад
How will the complexity be E log E ? Is it for Adj list representation because for a matrix representation I am selecting a vertex then looping through all other vertices to add them in the queue, if an edge exists at all so I am doing the work V times right? So the complexity will still be O(V^2 )
@ragibhussain5257
@ragibhussain5257 4 года назад
Very Nice Bro. Keep on making videos on other topics. Your animations are really usefull.
@adist98
@adist98 5 лет назад
I have missed these videos so much. Awesome explanation.
@nmamano
@nmamano 4 года назад
3:27 to be more precise, the two versions (lazy and eager) have the same complexity of O(E*log V) because log(E) = O(log(V)). This is because E < V^2, so log(E) < log(V^2) = 2*log(V) = O(log V). In big-O notation, it never really makes sense to use log(E) instead of log(V) for graph algorithms.
@amey7064
@amey7064 4 года назад
What about when there are O(V^2) edges? For example a dense or complete graph.
@nmamano
@nmamano 4 года назад
@@amey7064 then both are O(V^2 log V).
@joker345172
@joker345172 3 года назад
This helped me a lot. Many thanks to you, my friend
@aliakseibadnarchuk
@aliakseibadnarchuk 8 месяцев назад
why am i hearing "oh hell nah" in the background 5:20
@aleksajovanovic5142
@aleksajovanovic5142 Год назад
2:12 when i started doing it, it looked kinda sus bro hahahaha almost a nazi sign
@sallaklamhayyen9876
@sallaklamhayyen9876 3 месяца назад
brilliant explanation = thank you so much
@OllytheOzzy
@OllytheOzzy 3 года назад
Hands down best channel for graph algorithms resource on youtube. Thanks mate
@joydeepdas8632
@joydeepdas8632 5 месяцев назад
Nope, Hands Up, You are under arrest😂😂 For saying the Truth..
@gusamr8266
@gusamr8266 Год назад
Hey awsome video but I don't understand what happens at 8:41 you say its stale because (2,1,3) but how did you get that should'n it have been (1,2,3) because you were starting from node 1?
@abijithbahuleyan785
@abijithbahuleyan785 4 года назад
This deserves more views.
@darthvader_
@darthvader_ 2 года назад
After watching people on the internet unnecessarily complicating this beautiful algorithm. I'm here!
@CodeCraftWithVinayak
@CodeCraftWithVinayak 5 лет назад
Thanks williams
@diwu7091
@diwu7091 2 года назад
I understand MST in 10 minutes while I spent long time in university book.
@baidya87
@baidya87 4 года назад
thank you so much !! Really helpful !
@HiteshSethiya
@HiteshSethiya 3 года назад
You're so good that i recommend your channel to every SWE i meet.
@1UniverseGames
@1UniverseGames 3 года назад
Is each minimum-heavy spanning tree of N also a minimum spanning tree of N vertices!
@ivansyabro7854
@ivansyabro7854 Месяц назад
Better explanation than Leetcode premium, thanks a lot!
@Chichichifan
@Chichichifan 6 месяцев назад
thank for your video ,it help me learn Tree algorithm !!!
@DanielSColao
@DanielSColao 3 года назад
This helped me a lot! Thanks!
@sepehrkhodadadi9403
@sepehrkhodadadi9403 3 года назад
Simple and helpful ✌🏻
@sk-nath
@sk-nath 5 лет назад
It's very helpful. Thanks
@CuriousAnonDev
@CuriousAnonDev 2 года назад
Thanks William! Understood the algo :)
@beens3865
@beens3865 10 месяцев назад
Thank you lots!!
@queenb3730
@queenb3730 Год назад
what does to poll mean? we just choose a node randomly?
@WilliamFiset-videos
@WilliamFiset-videos Год назад
Polling is the act of removing a node from the top of the priority queue. In the pseudocode in this video it's the equivalent of .dequeue()
@queenb3730
@queenb3730 Год назад
@@WilliamFiset-videos I see thank you
@vijethkashyap151
@vijethkashyap151 4 месяца назад
Beautiful! :)
@neshant89
@neshant89 2 года назад
Thank you @WilliamFiset for such an amazing explanation, I wish you were teaching while I was still in college.
@BullishBuddy
@BullishBuddy 4 года назад
great job!!
@rajkhoiwal4901
@rajkhoiwal4901 2 года назад
pls explain the time and space complexity as well
@vinayak6564
@vinayak6564 2 года назад
Why choose vertex which is connected by minimum adge? it works even if we traverse and choose vertex from an ordinary queue(not priority queue) Becoz the goal is to connect vertex with minimum edge only and we can archive this even by choosing elements randomly
@AtharvaRao0104
@AtharvaRao0104 11 дней назад
You are right, even if you use a queue, you get a MST. But it comes with unnecessary evaluation of non optimal edges
@mohammedsamir5142
@mohammedsamir5142 Год назад
Clean and excellent explanation Elegant & Beautiful
@TheDjarto
@TheDjarto 3 года назад
damn I thought 2:14 was about to be a swastika
@iam_kundan
@iam_kundan 3 года назад
Excellent Explanation. It was crystal clear. I got everything in one go.
@anyadavidovich1083
@anyadavidovich1083 4 года назад
where in the code do we select the cheapest edge from the PQ?
@WilliamFiset-videos
@WilliamFiset-videos 4 года назад
That's the line 'edge = pq.dequeue' at 13:14 which removes the next best edge from the priority queue.
@ikaros9727
@ikaros9727 4 года назад
@@WilliamFiset-videos Hey. What would happen if i had a node with 2 Edges. The first one has a cost of 0 and the second a cost of 2. I follow the Edge with cost 0 and end up at a Node with another 2 Edges which all have higher edge costs than 2. If i dequeue i'd get the Edge from the first Element with cost 2 right? Would that change anything in the workflow?
@Sapphiamur
@Sapphiamur 4 года назад
@@ikaros9727 You need to get to ALL the nodes in the graph anyway, so the workflow doesn't change. You always choose the cheapest edge and follow it to get the minimum spanning tree.
@lag2an
@lag2an 3 года назад
the pq sorts based on the minimum edge cost,so it always dequeue the minimum edge
@alihashemian3418
@alihashemian3418 4 года назад
U'r the best man u'r the best
@irulam4116
@irulam4116 3 года назад
Thanks for the explanation!
@MalachiBurke
@MalachiBurke Год назад
Well done!
@briannguyen5057
@briannguyen5057 3 года назад
very helpful!
@jagritbhupal5836
@jagritbhupal5836 4 года назад
Thank you, Sir.
@DeepakKumar-ox5ti
@DeepakKumar-ox5ti 5 лет назад
Yes, Prims is nice.
@chepaiytrath
@chepaiytrath 4 года назад
For someone in doubt like myself, wondering which node to start from to put into priorityqueue, you can start with nay node and will still get the same MINIMUM SPANNING TREE (which by definition contains all nodes joined via the minimum weighted edges)
@davidjiang7929
@davidjiang7929 3 года назад
Jatin Shashoo that’s right, except there may be multiple spanning trees
@barry8871
@barry8871 3 года назад
yes, and all the trees weight cost the same
@basse9914
@basse9914 Год назад
One minor thing: it seems mstEdges[0] stays null.
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