Sir, I would be glad to get inputs about this... In counting, the way we calculate the permutations for n balls (distinct), m places (urns) with replacement is n^m (each urn can be filled in n ways). But when we employ the twelvefold way, for no restrictions both balls and urns distinct conditions the permutation is shown as m^n (each ball has m ways to go). How so?
CAN YOU PLEASE TELL HOW TO UNDER STAND THE DIFFERENCE BETWEEN PERMUTATION AND COMBINATION? I AM GET ING TOTALLY CONFUSED WHAT TO USE COMBINATION OR PERMUTATION? THANKS IN ADVANCE...
For example, if n=4 and we want 3, we write permutation=4*3*2 and genaralize it as n(n-1)(n-2). Here for n-2, its value is 2. Calculate n-k+1 by inserting n and k. Hope this understands.
