Probability using permutations and combinations : ExamSolutions

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Permutations and combinations probabilities.
In this tutorial I demonstrate how to calculate probabilities using permutations (arrangements) and combinations.
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Опубликовано:

17 окт 2024

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Комментарии : 175

@ali_zaid__786 2 года назад

I am shocked literally you post this video 10 years ago..... youtube give you award for the founder of educational content on youtube

@anassawas7423 2 года назад

I would recommend this playlist to anyone struggling with perms and combs. BEST EXPLAINATION EVER

@kenrock6136 Год назад

faxxx

@SomebodyThatIusedtoknow-zr8ci 7 дней назад

Searched this over the whole Indian RU-vid only to find a foreigner explain it, Thank you so much

@ZazzlesGS 7 лет назад

I've been struggling with perms and combs since the start my A levels, and finally now, after a year, I understand them, maybe now I'll pass my A level! Thank you so much!

@internetborn 2 года назад

I always wonder if you passed ur A levels

@ZazzlesGS 2 года назад

@@internetborn I did, I have my bachelor's now

@aymennimir7464 Год назад

@@ZazzlesGS shoutout

@loliking6628 Год назад

could i bag you

@loliking6628 Год назад

youre so cute @@ZazzlesGS

@justnorth7400 9 месяцев назад

I have been looking for a good hour now for a clear tutorial on probability with combinations, and I have finally found it here! Thank you so much

@anapecanape 10 лет назад

Thanks! You remind me of Ross from F.R.I.E.N.D.S.

@ExamSolutions_Maths 10 лет назад

Cheers - that's a new one.

@sylviachong5988 6 лет назад

I can't unhear his voice now

@naheenisapoet69 3 года назад

@Grady Rowen dunno if anyone told u but you are a lifesaver lmaoo

@aarti7136 3 года назад

@@ExamSolutions_Maths hey how you make these videos ?

@the_indomitablespirit Год назад

If he was British

@ExamSolutions_Maths 12 лет назад

Thank you and all the best for tomorrow.

@ExamSolutions_Maths 12 лет назад

Hope it goes well for you - Good luck.

@jamessaphu2163 3 года назад

1st 11C5 is wrong... It is 77..

@encly3881 5 лет назад

Thanks to u I just found the answer to a maths problem I spent the last half hour straining my mind over, thanks!

@gooddeedsleadto7499 3 года назад

You are one in a million or one in 100 years kind of a teacher. It is hard to find one like you, you deserve special mathematics society honor confirmed upon to teachers like you similar to fields medal. Always stay upbeat, you are blessed. Thanks a million. You should train and produce mathematics teachers like u.

@ExamSolutions_Maths 11 лет назад

No probs, pleased to hear they helped

@vijaychaurasia9603 5 лет назад

You are great . Many videos do not explain the same thing so well as you do. Thanks a lot.

@peterodhiambo9423 2 года назад

well elaborated.... I have got no problem at all... thank you very much🙏

@subhrasmitkar6304 3 года назад

Thanks a lot. I was really confused about the permutation and combination part. But you cleared it. Thanks!!!❤️

@ExamSolutions_Maths 3 года назад

Glad it was helpful!

@xVeltZ 2 года назад

Omg thank u soo muchhh i owe u big bits if it werent for i i wouldnt have graduated

@ksw2562 9 лет назад

AMAZING now at least I understand how the two are different and when to use them, thank you

@lanacassidy9060 8 лет назад

thank you v helpful, million times better than my teacher!

@niwagabaemmanuel4566 8 лет назад

You guys are good. This kind of explanations makes probability simple. Kudos!

@LogeshVishal 7 лет назад

I'm having my examination on Monday! I was still finding a way to solve this stuff but later when I got into this channel I understood nearly 90% of this Permutations and combinations in Probability

@aayaanashar9263 2 года назад

How was your examination bro.....?😄😄

@ceelocadhays5593 4 года назад

wow i did not understand even i took days but i understand in 5 minute on this thank u

@alsoarmani 8 месяцев назад

very understandable teacher.

@ExamSolutions_Maths 8 месяцев назад

Thank you

@Aiden_h9 2 года назад

Good day sir, I just want to ask quick question, where did you get the 120 and the 48 from? I tried to work it out where you actually get the 120 and 48 from, can you explain on the comment box please!

@Paulineee_v 8 лет назад

thank you so much! it's our finals today and I really needed this I love you!

@ExamSolutions_Maths 8 лет назад

+pauline valdez I wish you every success.

@starbeeleung 7 лет назад

Your explaination is great and clear,thank you so much.

@ChennypieX12 7 лет назад

Omg thank you so much, exams are coming up and I just realised that I do not understand how to do probability worded questions

@badjaeaux 8 лет назад

you are an excellent teacher ... may the King reward you

@Jordie389 12 лет назад

thanks man! I have an exam today on combinations and permutations and this really helped!

@anjaguldemond6234 8 лет назад

you explain so much better than my teacher!! Thank you so much!!

@bryantay862 8 лет назад

You really deserve more subscription. Keep up the hard work! Really understood and would really be blessed if you are my lecturer.

@An_ony_mous 8 месяцев назад

Thanks alot. I wamted this last one bit to do questions with both P and C and Probability mixed.

@kuldeeplohe3902 11 лет назад

It is most wonderful series of lectures i have ever seen on Utube for aforesaid topic do u have few more lectures on the same pls do upload the lec for circular permutation & pls do inform me i very much greatful to u for ur lectures

@ammarchen8850 3 года назад

Bro thank you so much. You helped me out so much. I wish i could give you a warm hug. Keep up the great work broo!👍

@akatsukisempai422 4 года назад

Got stuck with this subject during online classes. TY

@ExamSolutions_Maths 4 года назад

Pleased it helped. Best wishes.

@DarkDungeon-ux6rz 5 лет назад

In the second example, when finding the no of arrangements where A and B are together, shouldn't we divide by 2! instead of multiplying? Also, thank you very much your videos explain the concepts very well!

@0mfgitzramzi 5 лет назад

no you should multiply. since a and b can swapped and still be grouped together (b before a), that effectively doubles the number of possible arrangements that have a and b being beside each other which is why you multiply the 4! by 2.

@ExamSolutions_Maths 11 лет назад

i) 29C6 is correct and (ii) 29C7

@ambrishsudhanandan7098 4 года назад

that was a really awesome series very well explained

@realdragon Год назад

If I roll 2 dice and the only thing I care about is sum of these dice should I use permutation or combination?

@ExamSolutions_Maths 11 лет назад

Cool. Keep at it and I am sure you will get there.

@swaguilar_ 7 лет назад

You are helping me more than my teachers. I finally have a grasp on it! Thank you! :)

@ExamSolutions_Maths 7 лет назад

Well done.

@شيماءصلاح-و1خ 3 года назад

thank you very much from oman. You have helped me a lot

@klaus9687 19 дней назад

so why are you keeping the rearrangmenet in denominator in 1st example and multiplying it in 2nd example

@ashrafibrahim4934 5 лет назад

A multiple-choice question on an economics quiz contains 10 questions with five possible answers each. Compute the probability of randomly guessing the answers and getting exactly 9 questions correct. I figured the answer should be 10C9*((1/5)^9)*(4/5). But a website says it is 9*4/(5^10). I will be grateful if you can clear the confusion.

@alexandrajones8696 11 лет назад

Found this the night before my statistics exam, thank you so much! I may have a chance now!

@hydershariff5737 3 года назад

did you pass?

@aishaalshawafi2599 8 лет назад

Your videos are outstanding! and I really appreciate it, thank you.

@Mbye-t3c Год назад

Thanks. Well explained 👏

@aryadamle8772 4 года назад

really helpful series, pls make 1 on geometric and binomial distribution

@ExamSolutions_Maths 3 года назад

ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-NaDZ0zVTyXQ.html&ab_channel=ExamSolutions Please check out our series on the binomial distribution.

@matthewsmiley7742 4 года назад

Oh so helpful! Thanks

@ExamSolutions_Maths 4 года назад

Good to hear, thank you

@sitasma3339 5 лет назад

Omg you're a lifesaver and a really awesome teacher ❤️❤️

@RachelZhang 8 лет назад

Thank you for saving my life.

@SilentEagle2029 12 лет назад

@ExamSolutions hey im in 7th grade and learning this and this was helpful a lot but how did u know wether or not it was combination or permutation? If u have a trick with this it would help a lot and i am now going to use these videos for future reference all of the time get it or not. Thanks for being such a smart person and being able to do this stuff. To me this is difficult

@rajdipshah9225 2 года назад

if the quesrion is asking to arrange, then permutation, if ir's asking to SELECT/CHOOSE, it's combination

@kayte5804 2 месяца назад

@@rajdipshah9225a bit late, this person is probably working a 9 to 5 now

@ExamSolutions_Maths 12 лет назад

@anglican09 Pleased to hear you found it helpful.

@dontbeserious5153 5 лет назад

Sir may you clarify? In the second example did you mean 4!/2! Or 4! × 4! ?

@ExamSolutions_Maths 5 лет назад

Neither. 4! x 2!

@nandinibansal3983 8 лет назад

This was amazing! Thank you so much.. your way of explaining is awesome! :)

@ExamSolutions_Maths 8 лет назад

Flattery will get you everywhere!

@thehrchannel8983 8 лет назад

You explain better than my professor. I can't even read half my professor's handwriting.

@TheBlazefire33 11 лет назад

this is an easy question....do one where the letters of a word have to be in an order and we need that probability

@SarkySk8inGuitarist 11 лет назад

Thank You! Your videos are so clear, and are really helping me get through my AS! Thanks!!! :)

@shamoil4444 12 лет назад

This is the easy stuff........ I need more advanced examples.

@DisguisedEnzo 11 лет назад

saw this questions on a cambridg statistics as level past paper, very usefull thanks!

@oneinabillion654 6 лет назад

Rly? I wished Im gonna have questions like this this coming OCT NOV AS test

@stupermanana 12 лет назад

can u use the notation (permutation) for the ABCDE question, as in 4 permute 2 (eg) because I dont understand how to show it.

@jamesivan24 11 лет назад

In how many ways can seven students from a class of 30 be chosen for a field trip if Jack must go on the field trip. I'm assuming this is the same equation as 6 out of 29 students being chosen (29 nCr 6 on a graphing calculator). Is that correct? I'm assuming on the next question (what if Jack can't go on the trip) is the same formula. I just want to make sure I'm doing it right. Thanks, guys! You rock!

@radaradaitsbob 11 лет назад

Thank you! This helped me out a lot.

@ayamgorengspicy3x 8 лет назад

Im actually dont understand how and when I gonna use P and C. Thanks, now Im understand. Tomorrow I have quiz about Statistics. zzz

@ExamSolutions_Maths 8 лет назад

+NurFarrah Soda Good Luck - I hope it goes well for you.

@ayamgorengspicy3x 8 лет назад

+ExamSolutions Thanks again. 😊

@KeijiJohnLibadisos 8 лет назад

me too

@gran7773 3 года назад

what if by any chance cards with letter A and B refuses to be together what would the solution be?

@OriaPlay 10 дней назад

A billion thanks

@jameslucas6754 4 года назад

how come for the second video the nPr=n!/(n-r)! wasn't used?

@matinhewing1 6 лет назад

Excellent video! Really helped! Thanks a lot!

@ExamSolutions_Maths 6 лет назад

Thanks for watching.

@shanurathore9515 Год назад

Thank you so much 💖

@tbilisi45 12 лет назад

I didn't quite follow you on the ABCDE problem. How exactly did you come up with 4! ways of A and B being together? There are only 5 places for an A; out of those 5 places, for 2 of them - first and last, there's only one place a 'B' can be put, to be next to A, and out of remaining 3 middle places for 'A', there are only two neighboring places for 'B' to be next to 'A'. Which gives us total of 1+1+2+2+2 = 8 combinations for A and B to be next to each other. thanks.

@rajeshkalakoti2434 5 лет назад

Andy has 5 toy ships and 6 toy planes. He wants to make an exhibition showing 3 models of one kind and 4 models of the other kind. How many ways there are to pick the exhibition set from his collection?

@shozebkohari9593 4 года назад

october exams are close and thank god your videos are so damn helpful keeo up the good work

@ExamSolutions_Maths 4 года назад

Thanks and good luck.

@kathleenolivier1588 3 года назад

@@ExamSolutions_Maths Hi sir can you tell me the answer for this question. A coach has 16 players and can pick from 11 players for a match. it consist of 7 specialist batsmen, 4 fast bowlers, 3 spinner and 2 wicketkeeper. how many different teams can be formed if it must comprised of 6 specialist batsmen, 3 fast bowlers , 1 spinner and a wicketkeeper.

@isi6402 3 года назад

@@kathleenolivier1588 7C6 * 4C3 * 3C1 * 2C1 Dude use combinations.

@suryamanjunathang4947 2 года назад

@@isi6402 divided by 16C11

@chesterbennington3741 3 года назад

Thanks Gordon

@bumboy8736 3 года назад

7 years later, thank you

@SilentEagle2029 12 лет назад

@stupermanana thanks I passed it....with a 65...now I'm in 8th grade so yea thanks again only 2 months too late tho...

@f2t2r37 Год назад

thank you sir !!!

@MsHeartBreaker16 13 лет назад

Now I understand better! =D Thank you! ^^

@sean_tristan31 8 лет назад

Why do we multiply the combinations instead of adding them up? Can someone explain?

@Sh4wnTzy 7 лет назад

Sean Tristan Francisco principles of counting...multiplication rule

@shafiahmed8103 7 лет назад

Sean Tristan Francisco

@ninanime21 6 лет назад

Sean Tristan Francisco...because there are different sets... So we have to use the multiplication operation. However, if we have the same set then we can use adition.

@biski800 2 года назад

Thank you! I don’t live in an English speaking country, but your videos make much more sense than my professor (˃̵ᴗ˂̵)

@yoyoyoc3po 7 лет назад

Thanks a lot mate.

@ExamSolutions_Maths 11 лет назад

Good luck

@jainikajeda3448 12 лет назад

is this for o level add math?

@sea5205 6 лет назад

This was a great video thanks a lot!

@ExamSolutions_Maths 6 лет назад

Cheers - thanks for watching

@ExamSolutions_Maths 11 лет назад

Good

@Sh4wnTzy 7 лет назад

thank you sir 😊

@elijahprice5174 5 лет назад

thanks man that was awesome

@ExamSolutions_Maths 5 лет назад

Thanks

@ramanshrivastava1407 6 месяцев назад

watching from 2024 amazing video really 🫡🫡

@antoinepoisson4791 3 года назад

thanks a LOT

@sirhc1999 12 лет назад

is it OCR?

@billiondollarbeast 10 лет назад

thanks super helpful

@kreinsch100 11 лет назад

Amazing Thank You !!!!!

@ExamSolutions_Maths 12 лет назад

Yes it can be

@Sergiopt96 11 лет назад

thank you very much for the video :)

@stupermanana 12 лет назад

dont worry ur stil in grade 7^^ permutations: order matters (how many ways can 5 books be arranged on a shelf) the way you order the books. Combinations: order doesn't matter. eg (how many ways can 3 groups be formed from 7 ppl, the order doesn't matter)

@donicesneed8514 11 лет назад

Okay you multiplied 11*10*9*8*7 why didn't you multiply 6 also when multiplying the number of committees?

@dealwiththebob3877 7 лет назад

Donice Sneed because the committee needed 5 people out of 11. Once 1 person is picked, they can't be re-picked. So the 'pool' to choose from goes from 11 to 10. And goes down 5 times. So it's 11x10x9x8x7

@movischoy3388 11 лет назад

Thank you very much!!!:)

@bonchasilark 10 лет назад

good luck on fri guys

@omyyer 12 лет назад

thank you, friend :D

@ExamSolutions_Maths 11 лет назад

There were 5 gaps to fill not 6

@ashrafibrahim4934 5 лет назад

You have made a small mistake, note that in the last math, it's written "shuffled". So you have to deduce 1 from the number of ways "A and B can remain together" or "ABCDE can be arranged"

@ExamSolutions_Maths 5 лет назад

There is no mistake. Please check out the video where items remain together. ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-yZ_0HmTn0oI.html

@tbilisi45 11 лет назад

Care to elaborate any further?