Probability When Rolling Two Dice Matrix Method 

i have a test of probability, and this 8 minutes video helped me sooo much, thank you so much mr. i really appreciate your effort :)

its a huge help for my acads sir! 😄 thanks a lot , God bless you

Probability has been disturbing me but this video has opened up my eyes Thank you so much

wow, this turned out to be so easy!

i never understood probabilities until now. this really helped

Thank you sir. Many people get the following question wrong, so please explain. [Question] Find the probabilities that the following events will occur when two dice are rolled. ①Both show odd numbers ②One shows odd number and another shows evenn number ③Both show even number P(E):the probability that event E occurs. 【Distinguishable dice A and B】 (the number that dice A shows,the number dice B shows):event If we only judge whether the numbers indicated by the dice are odd or even, the following four events will occur. 　　(odd,odd) (odd,even) 　　(even,odd) (even,even) If each event occurs with equal probability, the probability is 1/4. Therefore, P(①)=1/4, P(②)=1/2, P(③)=1/4 (1) If we judge the number(1,2,···,6) indicated by the dice ,the following 36 events will occur. (1,1), (1,3),(1,5) (1,2),(1,4),(1,6) (3,1), (3,3),(3,5) (3,2),(3,4),(3,6) (5,1), (5,3),(5,5) (5,2),(5,4),(5,6) (2,1), (2,3),(2,5) (2,2),(2,4),(2,6) (4,1), (4,3),(4,5) (4,2),(4,4),(4,6) (6,1), (6,3),(6,5) (6,2),(6,4),(6,6) If each event occurs with equal probability, the probability is 1/36. Therfore P(①)=9×(1/36)=1/4, P(②)=18×(1/36)=1/2, P(③)=9×(1/36)=1/4 (2) (2) matches (1). 【Indistinguishable two dice】 (odd,even)is the same event as(even,odd). Thererore, if we only judge whether the numbers indicated by the dice are odd or even, the following three events will occur. 　　(odd,odd) 　　(even,odd) (even,even) If each event occurs with equal probability, the probability is 1/3. Therefore P(①)=1/3, P(②)=1/3, P(③)=1/3 (3) (1,3) is the same event as (3,1). If we judge the number(1,2,···,6) indicated by the dice ,the following 21 events will occur. (1,1) (3,1), (3,3) (5,1), (5,3),(5,5) (2,1), (2,3),(2,5) (2,2) (4,1), (4,3),(4,5) (4,2),(4,4) (6,1), (6,3),(6,5) (6,2),(6,4),(6,6) If each event occurs with equal probability, the probability is 1/21. Therefore P(①)=6×(1/21)=2/7, P(②)=9×(1/21)=3/7, P(③)=6×(1/21)=2/7 (4) (4) contradicts (3).

Thank you 😊 you're video is of a great help for a student like me.

This 8minls video really helped me I've been battling with probability since I was in secondary school

This was really helpful! Thanks man!

Thank you! That's an amazing method!

Great video, simple as it could be.

finally a table that makes perfect sense!

Now I indrestrand... Thankyou 🙋💕 I thought it so hard to understand

It helps me a lot to my activity thank you

Great Job ! Thanks Appreciated 😘

Very clear explanation. !!

thank you so much, this helps a lot!

thank you so much!

This has helped me a lot. Thank you so much

Wow it's helpful

OMG!!! Thank you!!!! NOW I ALREADY ABOUT THE SUM OF 7

thanks a lot for the lesson, it is easy and so rationale for slow minded like me :)))

Thank you sir I have really understood that concept

This was very helpful. God bless you❤️✊

hy sir anil kumar kindly guide me about(probability of ace drawing when die thrown twice)

Thank you, very clear.

Great explanation!! Well done!

Thanks Ser. Anil Kumar it's help me a lot 👍👍👍👍💖💖💖👏👏👨‍🏫👨‍🏫👨‍🏫👨‍🏫👏 😍😍

This really helped me a lot! Thank you for sharing :)

great explanation

Shukriyaaaaa sir gg bhot bhot You're just an amazing teacher God bless you .Thankuee so muchhh .....

super, i need a solution for this problem, a pair of dice rolled once. let x be the random variable whose value for any out come is the sum of the two numbers on the dice, find P(3

why 6 raws and com for the table and if its 3 or more what should we do ?

this is so informative thanks

Very nice explanation sir

this helped me a lot thanks so much

Hey man I need help How to make a tree diagram of 2 dies rolled? Please help

Thank you so much sir nice lecture

thank you so much, keep making helpful videos like this :)

Thank you very much! The video was really helpful

Thank you sir

Thanks sir

thank you for your video lesson:)

wow, wonderful explanations. Thank you so much

Sir jo hmy parhya gya tha us mai at least 7 k keay prob=21/36 the

Thanks a lot sir 🙏

thank u sir :) very helpful video

Watching now

thamks soooo much, you made this soooo easy!

thank you so much, hope you keep doing videos

What is the probability of getting two odd numbers

Thanks man, would you mind solving a level stats past papers?

But 3, can also go into 15and36 Or there no need to divide . In number two question

Thankyou very much. Chennai.

It is useful for as thank you so much

Thanks so much ❤

Thanks a lot you really helped me study for my test

Thank you so much sir

thank you very much guru

Thank you so much

Thanks sir 🙏🏾

Thanks

Very nice

u just broke a mountain into soil particles in a blink of an eye

good lect

Wow bravo ,thanks sir

Thank you!!!

thank you so much!!

thank you ❤

awesome! Thanks

thanks baby bro

I slapped my dumb self for not realizing how easy it is Thanks a lot mr. now I can give my exam in peace 😇

Sir why dint you simplify 15/36 = 5/12

I don't know why it bothered me so badly that you didn't reduce 15/36, while the other ratios got that reduction love. I guess I am just easily bothered by unimportant things. Thanks for the video!

to sir ek bar Bina table ke bata digiye

Sir loveeee uuuu so much😍

What about if P(0)?

Thank you

Thank u sir..

Legends in 2022

Thanks. .....please sum of 7 I didn't get it. .... I thought it might be 42/36 But still please help me understand thanks again and again

Nice sir

Sir it's awesome... But what with three dice! is there any trick for it?

Nice

but Which totals have the highest and lowest probability of occurring

ager sir table nhi banay to keya nhi hal hoga

THANKS

Wtf is this .... U r just counting the elements in the set..... It is not gonna help if the set is not a perfect square or its very large

You made a mistake? You totally left out the probability of rolling a 6???? WHY????????????? Didn't you mean Probability of rolling a dice with a value of LESS THAN 7????????????

Its so easy

Thanks sir

Thank you