PROBLEM SET 0: TIP CALCULATOR | SOLUTION (CS50 PYTHON) 

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This is how did it. def main(): dollars = dollars_to_float(input("How much was the meal? ")) percent = percent_to_float(input("What percentage would you like to tip? ")) tip = dollars * percent print(f"Leave ${tip:.2f}") def dollars_to_float(d): # TODO a = float(d.removeprefix('$')) return a def percent_to_float(p): # TODO b = float(p.removesuffix('%'))*float('0.01') return b main()

this problem literally made me want to cry because i tried *everything* i could think of and it wasn't working. turns out i was missing "return".

I was still confused about the structure of functions and parameters as well as how to start the first line, so giving me only that hint from your video helped me a lot. I was struggling for quite a while until I finally decided to get a hint on how to solve this. Thanks!

Thanks! Nice to get a review after doing it. Feels like having a TA.

Love the way you explain step by step. Thank you very much!

Really great descriptive video! The step-by-step walkthrough with examples was so helpful!

def tip(): use = (input("how much was ur meal? ")) user = float(use.replace('$', '')) top = (input("how much would u like to tip? ")) tp = float(top.replace("%", "")) a = user * tp/100 print(f"leave ${a:.2f}") tip()

Thanks for the solution. Here is the code I wrote and worked for me. def main(): dollars = dollars_to_float(input("How much was the meal? ")) percent = percent_to_float(input("What percentage would you like to tip? ")) tip = dollars * percent print(f"Leave ${tip:.2f}") def dollars_to_float(dollars): dollars = dollars.replace("$","") dollars = float(dollars) return dollars def percent_to_float(percent): percent = percent.replace("%","") percent = float(percent) percent = percent / 100 return percent main()

I'm loving it! Very Helpful

Beautifully explained. Thank you for the explanation

Thank you so much, very clear and coincise explanation.

This is how I did it. I realize I should have did p = float(p)/100 instead of int :( def main(): dollars = dollars_to_float(input("How much was the meal? ")) percent = percent_to_float(input("What percentage would you like to tip? ")) tip = dollars * percent print(f"Leave ${tip:.2f}") def dollars_to_float(d): d = d.strip("$") return float(d) def percent_to_float(p): p = p.strip("%") p = int(p)/100 return float(p)

I was struggling with the return , thank you for the guidance

couldnt thought of that return... thanks for the help!

i knew that i needed to use return i couldnt figure it out how to use so igot made

Thankyou so much!

return funtion was pretty tricky for me, thanks

lstrip & rstrip works for me 👌👍

thank you so much this videos is so usefull

Good to see how others have solved it. Its Week 0 and I often find it hard and have to re-watch the lectures and look for clues in his examples. My approach was: def main(): dollars = dollars_to_float(input("How much was the meal? ").replace("$","")) percent = percent_to_float(input("What percentage would you like to tip? ").replace("%","")) tip = dollars * percent print(f"Leave ${tip:.2f}") def dollars_to_float(d): return float(d) def percent_to_float(p): return float(p) / 100 main()

Mi error solo fue no ponerle luego del float el parentesis :/

Thanks for the video! Good content, keep it up! If I may, I'd like to give you a correction regarding your English - the use of word Replace - we replace something with something else. E.g. Replace A with B. or, Change A to B. :) Hope I didn't sound rude - just wanted to help a tiny bit to make your content even better!

was really struggling when the only thing that i missed was p2 = float(p1) / 100 my version was with parentheses around the 100 also...

Here's my answer. # define main() def main(): # call a function and assign var and ask user for input dollars = dollars_to_float(input("How much was the meal? ")) percent = percent_to_float(input("What percentage would you like to tip? ")) # calculate a var called tip by multiplying dollar with percentage tip = dollars * percent # print var called tip as f str with .00 print(f"Leave ${tip:.2f}") # because we haven't defined the two functions above, we need to define them first def dollars_to_float(d): #remove $ from str and turn x into a float x = d.replace("$" , "") return float(x) # define percent_to_float() def percent_to_float(p): # remove % from str and turn it into a float and divide by 100 y = p.replace("%" , "") y1 = float(y) return y1/100 main() I couldn't solve it for hours and left it for three days. I came back and solved in 15 mins! I was overcomplicating things and overlooking the fact that input() can only take str and two different str cannot be multiplied. When I realized that, viola! I start asking the questions! How do I remove $ % from the str and turn them into float. I think the biggest challenge and fun part of being a programmer is knowing what how to ask the right questions. For me, I break them down with # and start my logical thinking step by step. I know no better; I'm just a rookie.

Thank you so much for this

was totally stuck on percent_to_float... was trying to cramp everything into a singline line of code. this is what i had ===> return float(p//100.replace('%', ' ')) and i kept getting TypeError: unsupported operand type(s) for /: 'str' and 'int'... your video saved me. thx

Does lstrip and rstrip not work for this problem?

i couldnt for the life of me understand how to replace the $ and % signs. i didnt realize we had to use a function ive never heard of lol, i tried to stick to the lectures only. at least i understood how to return the float. i also thought it was silly to just not add the "/100" to the original equation of dollar * percent. i feel like that makes the calculator easier to understand than defining it with the percent function, but i suppose thats a part of the assignment. just in case i added /100 to the end of the return percent function and it worked.

you are a wizard!

How she pass d and p while both were not defined?

I used the remove prefix and remove sufix instead replace, it worked hahaa so i did not toch it

Thanks for your teaching. I just have a simple question that dollar_to_float(d): the (d) is a varible refering whatever user input in this case?

Why is there a variable in the defining function? For example, "def dollars_to_float(d): " Where did the "(d)" come from? Why is it there?

Can someone explain to me what this means? print(f"Leave ${tip:.2f}") I understand the print function and the"Leave $" and somewhat the {tip} but I don't understand the {:. 2f} ??? I know it's a f string but I have zero idea why this is in there, could someone help me please?

I think David Malan should take the backseat and let you drive. I learn more from you!

Good to see what solutions other people came up with. I for example, used strip instead of replace: def dollars_to_float(d): without_dollar = d.strip("$") return float(without_dollar) def percent_to_float(p): without_percentage = p.strip("%") return float(without_percentage) / 100

is this allowed? i feel like im cheating.. cant help but search for guide lol

Can i ask you something? there is one thing that confuses me , why are you inserting the "(d)" in the def function, instead of just dollars. because both of them works. so i am a little bit confused about that by the way i love you content you make it look so easy! :)

Plz post project 1 also🙏🏻

I executed your instructions completely correctly, but in the 4th line, it gives an error that the tip is not float where is the problem from ?

Here's the code that I wrote but for some reason an error pops up saying couldn't convert string to float. I would like your help and also an explanation on why this error keeps on showing up, if it's not to much to ask. Thanks def main(): dollars = dollars_to_float(input("How much was the meal? ")) percent = percent_to_float(input("What percentage would you like to tip? ")) tip = dollars * percent print(f"Leave ${tip:.2f}") def dollars_to_float(d): # TODO d = d.replace("$","") float(d) return d def percent_to_float(p): # TODO p = float(p.replace("%","")) p = p / 100 return p main()

but the dollar sign was not removed?

def dollars_to_float(d): return float(d.replace('$', '')) def percent_to_float(p): return float(p.replace('%', '')) def main(): dollars = dollars_to_float(input("How much was the meal? ")) percent = percent_to_float(input("What percentage would you like to tip? ")) tip = dollars * percent / 100 print(f"Leave ${tip:.2f}") main() this has worked so far. The only thing i did differently, is NOT dividing by 100 in float, but at end in the main

My code: def main(): dollars = dollars_to_float(input("How much was the meal? ")) percent = percent_to_float(input("What percentage would you like to tip? ")) tip = dollars * percent print(f"Leave ${tip:.2f}") def dollars_to_float(d): return float(d[1:]) def percent_to_float(p): return float(p[:-1]) / 100 main()

Ahh. Nice. Pretty clean. Didn't think about .replace() method. Instead used .removeprefix() and .removesuffix() accordingly. I was wondering how can you implement the same functionality but if the user enteers other currency symbols like yen or euro . I mean you cant type all these signs in parameters.. At the top of my head, I can only think of a loop with a list of all the symbols to check and remove if in list

Boa , aqui no meu eu utilizei o .strip() pra retirar o "$" e o "%" ! Alguma preferencia ?

Nice I used .strip() method for this as it was the fastest

Ahh. Nice. Pretty clean. Didn't think about .replace() method. Instead used .removeprefix() and .removesuffix() accordingly. I was wondering how can you implement the same functionality but if the user enteers other currency symbols like yen or euro . I mean you cant type all these signs in parameters.. At the top of my head, I can only think of a loop with a list of all the symbols to check and remove if in list