Glad I could help! I know it is easy for me to say that you shouldn't be intimidated to ask questions but from the perspective of a teacher I can tell you and be 100% certain that the questions you ask in class make our lives easier, not more difficult. Trust me, you're doing your teacher and your classmates a favour by asking questions. Keep it up, physics is hard but the problems are super satisfying when you are able to solve them :)
One question. How would I know if the initial speed is 0 or it starts at 69.4 m/s? I was confused that how you counted that as 0 as a plane can't start at 0 on air. So every time I got wrong answers have both initial and final v as the same answer.
Great question. Because the question says that the plane is travelling horizontally we can say that the vertical component of it's velocity is zero when the package is dropped. The horizontal component of the package's velocity (if we dont consider air resistance) is constant throughout the package's journey towards the ground and is equal to the velocity of the plane. Only the vertical component of the package's velocity will be affected by the force of gravity. We use the vertical component of the packages motion to determine the total time of the package's journey and the horizontal component of the package's velocity to determine the total horizontal distance it travels after it is released from the plane. I hope that explanation helps. :)
Well the initial velocity (u) is zero and it is being accelerated over a distance (s) of 235m as it travels towards the ground. The acceleration due to gravity (a) is 9.81m/s^2. As a result, the final velocity just before it hits the ground can be found by: v^2 = u^2 + 2as v^2 = 0^2 + 2(9.81)(235) v^2 = 4610.7 v = sqrt(4610.7) Final Vertical Velocity = 67.9m/s (just before the package hits the ground) I hope this helps :)
Homework 1: Consider the following one-dimensional motions: (a) A ball thrown directly upward rises to a highest point and falls back into the thrower’s hand. (b) A spacecraft drifts through space at constant velocity. Are there any points in the motion of these objects at which the velocity is the same as the average velocity over the entire motion? If so, identify the point(s) ((((((( sir please solve this problem please )))))))
@@HaroldWalden thank you haha i commented this at the start of the video then realised that the final calculation was just the constant speed divided by time. so the speed had to be the same the entire time
And here I am.... Not trying to pass a physics exam - but trying to win a pumpkin drop contest and calculate what airspeed, height and distance I need to be at to toss a pumpkin out of my plane to hit the spot on the ground! Anyway, surely mass of the object being dropped comes into this somewhere as well since the height will give it potential energy as it accelerates with gravity?
Sorry about the delay. Attached is the way that I would go about answering your problem: drive.google.com/file/d/1O_wD_Ygn7NLx_nVFRBfkldjFijM-5Mkq/view?usp=sharing Hope it helps :)
Have a look at this, it should explain everything you need. www.google.com/search?rlz=1CDGOYI_enAU916AU916&hl=en-GB&sxsrf=APq-WBsKpW6buCIdn5Nb5c65Oav_oEPYFg:1648061360423&q=Gravitational+acceleration+constant&stick=H4sIAAAAAAAAAOPgE-LUz9U3SIrPskhS4tVP1zc0zDBKKzK2qDLUsshOttJPTSlNTizJzM_TL0ksSk8tic9Pi09OzEkuzQGLWqXlF-UC2QqZuYnpqQqJecXlqUWPGC24BV7-uCcspT9pzclrjJpcXMEZ-eWueSWZJZVC0lxsUJagFD8Xqp08i1iV3YsSyzJLwKYn5igkJien5qQWgbkKyfl5xSWJeSUAQI7_IbcAAAA&sa=X&ved=2ahUKEwie0tL_8tz2AhXB3mEKHcoPCKsQ3IYFegQIDxAC&biw=375&bih=748&dpr=3
Good question, I think it will slow the vertical acceleration caused by gravity which will have the effect of increasing the time of the projectile’s fall and, if the parachute has no effect on horizontal velocity will cause the object to go a greater horizontal distance.
Yeah that changes everything. You’ll have to initially work out the horizontal and vertical components of the plane’s velocity and use those numbers in your equations of motion. From there the problem is essentially the same. Hope that helps 🤓
((((((( sir please solve this problem please ))))))) ((((((( sir please solve this problem please ))))))) Homework 1: Consider the following one-dimensional motions: (a) A ball thrown directly upward rises to a highest point and falls back into the thrower’s hand. (b) A spacecraft drifts through space at constant velocity. Are there any points in the motion of these objects at which the velocity is the same as the average velocity over the entire motion? If so, identify the point(s)
a) at its highest point the instantaneous velocity = average velocity = 0 b) the instantaneous velocity = average velocity for the entire duration because velocity is not changing.
can u calculate range of projectile, projected at an angle 45 with intial velocity 170m/s having masses (1)1340gm & (2) 1380 gm... plz give mathematical formulas also..
@hassan sharif I didn't explain that very well at all, thanks for pointing that out and sorry if it has confused you at all. What I should have said is that initially the vertical component of the package's velocity is equal to zero and the horizontal component is equal the the velocity of the plane; 64m/s. All you really have to remember is that it is the vertical calculations that will tell you how long the object is falling for and once you have figured that out multiply it by the horizontal component of the initial velocity to find the range. I hope that clears a few things up for you :)
Thank you. Not going far from your example, what if the aircraft dives in a 15º degree instead of going forward in a degree of 0º, how to find the distance to drop suplies to that same island? Here's an image from your example with the degree in the aircraft: postimg.cc/image/s4v4dkfbp/ Cheers!
