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What a nice way of teaching and letting us imagining the whole scenario sir ...... commendable efforts .... thank you for making concepts so clear as crystals .....
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Since then I came from Africa to India I didn't know any single word of Engineering graphic designing but through you sir I'm now not to compare with others... thanks you so much
awesome sir i am from iit kgp earlier i used to hate this subject but now due to you only i have started understanding its concepts The way you teach is such that i have started imagining Things in 3D thanks a lot Keep making new videos :)
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Thank you so much sir.......... I don't know what is projections of planes by seeing this tutorial I able to write my exam. Once again thank you sir......😊😇😇😇
+Pavan Tej Thanks a lot Pawan..... Do watch all the content both from drawing and mechanics..... And do recommend this channel to your friends, classmates and juniors so that they can also benefit......
Hi Manas........ I am sure these videos are helping you learn the concepts... All the best and do let your friends know about this channel so that they can also benefit.....
You are the great sir, when i am seeing your videos, it seems like you put your all efforts, and i also gets more energy to understand your concepts,,, really hardworking sir... thank you sir..
1.Draw projections of a rhombus, ABCD, with AC = 80 mm and BD = 50 mm if: a. BD is parallel to both HP and VP, and AC is inclined 30º to VP 2.A pentagonal plane rests on VP on one of its corners, inclined 30º to it. The diagonal through that corner is inclined 30º to HP. Draw its projections, if it lies in the 4th quadrant. SIR CAN YOU PLEASE SOLVE THESE TWO QUESTIONS???
Hi Sai..… Thanks for appreciating my work…and all the best for your exam I am sure this channel is helping you learn…You can support my channel by donating and do watch this video: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-WfyUEhxhjZU.html Have a Nice day
I used shiver when ever I hear about EG , but after watching ur lectures am pretty interested in EG and more life saver for many of the students Thank you for wonderful videos And amazing explanation
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A circular plate of diameter 80 mm is resting on a point of its periphery on H.P. such that it makes an angle of 400 to the H.P. The diameter passing through the point of its resting on H.P. makes an angle of 600 with V.P. Draw the projections of it.
I had a doubt, when we say the diameter's TV is inclined to VP at 30 degree. Is it necessary to take points a and b as the the diameter on the 30 degree line or can we take any two points?
Superb explanation sir I had learned very well and I have no words to express as it is very helpful and I too had shared with my friends sir and they too got helped from you tutorial sir “THANKS A LOT SIR”
Hi Bilal.. I am sure that these videos are helping u learn... Keep watching and do let your friends know about this channel so that they can also benefit................
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You said that the edge which is going to be inclined in the third step is placed perpendicular to line XY in the first step.. No edge type thing is here but we have a line(diameter), can't we coordinate circle in the way that line AB is perpendicular to line XY
shows a thin plate of negligible thickness. It rests on its PQ edge with its plane perpendicular to V.P. and inclined 40° to the H.P. Draw its projections. Sir can you plz explain this question.....
Sir my projection of plane chapter is going on my class but I was unable to understand because of my teacher is teaching very fast ,,,,, that's why I couldn't understand but now I am new for watching your video on RU-vid and now I'm even better understanding ED,,,,,,,but sir I'm with a confusion that where to first locate the object (Circle, Pentagon , Hexagon) - Above the xy line or below the xy line.... - ,,,,,,,,,,,,,,,Sir plz provide a video on this basic
Sir u always asked us to take the line perpendicular to XY which is going to inclined in 3rd step then in this question why did u kept AB parallel to XY, why didn't we took point A at point 5 in fig. Thankyou
Yes edges which will be inclined in final step has to be kept perpendicular to xy line..... But this is diameter ok...... Edge is different from a diameter
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7. A circular lamina of diameter 40 mm rests on one of its circumference point on H.P. the diameter containing the point inclined 45° to V.P. The surface of the lamina is inclined 40° to H.P. Draw its projection
Thanks for commenting PRatibha.. All the best.... And do let your friends know about this channel on drawing and mechanics so that they can also benefit.....
Sir, In the step 3 we have a line of inclination 30° from VP and we have taken a point 'a' randomly on it . Now the question comes how can we have the points 6,5&4 between point 'a & b' ? Sir pls do answer I am waiting for your response?? Thank u ...😊
I have same problem if you have known that thing then please tell please , don't treat me like other just tell that if you know , again please tomorrow is my exam ...!!!