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Proof that if two events are independent, so are their complements. 

jbstatistics
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23 окт 2024

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Комментарии : 26   
@andyl.5998
@andyl.5998 5 лет назад
"More probability and statistics videos will follow." Hell yeah!
@AlexandreLopez1999
@AlexandreLopez1999 4 года назад
Maybe worth noting that the backward implication also holds! So if the complements are independent, then so are the events themselves. If we let A = Xᶜ and B = Yᶜ be independent, then (by this vid) Aᶜ = Xᶜᶜ=X and Bᶜ=Yᶜᶜ = Y are also indpendent
@rajatshukla2605
@rajatshukla2605 3 года назад
Very very explained . Thanks for the video!
@SimchaWaldman
@SimchaWaldman Год назад
This is beautiful! 😍🥰❤💚💙
@prabhleenreen3594
@prabhleenreen3594 4 года назад
thank u king just what I was looking for
@sanchoysamriddharanchi5753
@sanchoysamriddharanchi5753 5 лет назад
welcome back.I am so happy.
@chizuru971
@chizuru971 2 года назад
Thank you 😇
@sergiohenriqueandradedeaze9304
@sergiohenriqueandradedeaze9304 3 года назад
Great channel!
@lpm7656
@lpm7656 Год назад
Can we generalize this result with n set ?
@marimkrtchyan2588
@marimkrtchyan2588 2 года назад
Thanks!!!
@andrealupascu295
@andrealupascu295 Год назад
is it also true that if Ac and B are indepedent, A and Bc also are? (without knowing if A and B are indepedent)
@jbstatistics
@jbstatistics Год назад
Yes. If Ac and B are independent, so are A and B, A and Bc, and Ac and Bc. Independence of any one of those pairs implies independence of the others. Loosely, independence means that knowing that one event happened (or didn't happen) doesn't change the probability of the other event.
@andrealupascu295
@andrealupascu295 Год назад
@@jbstatistics thank you
3 года назад
Let A and B be independent events. Let C = A ∪ B. Conditional on C, are A and B independent?
@HaineGratuite
@HaineGratuite 5 лет назад
welcome back!!
@jbstatistics
@jbstatistics 5 лет назад
Thanks!
@elizaldodesousajunior9077
@elizaldodesousajunior9077 4 года назад
Excellent video! 10 10 10!!!
@nasser-eddinebendaoud6783
@nasser-eddinebendaoud6783 4 года назад
Thanks Very Helpful
@shaycohen622
@shaycohen622 2 года назад
THX!
@chikeconcepta2245
@chikeconcepta2245 5 лет назад
keep them videos coming
@F1U7R2Y9
@F1U7R2Y9 4 года назад
Thumbnail looks Grant's video But its close
@dfghj241
@dfghj241 5 лет назад
isn't that David Hume's?
@jbstatistics
@jbstatistics 5 лет назад
I confess to not being well versed in the full historical context (and I'm sure the knowledge that "not (A or B)" and "not A and not B" are the same thing goes *way* back, long before De Morgan), but in probability that notion is typically referred to as one of De Morgan's Laws.
@senselessnothing
@senselessnothing 5 лет назад
These were tough times to do probability.
@rozebeef7427
@rozebeef7427 4 года назад
@wilma rumscheißen
@haomiaoyu9813
@haomiaoyu9813 4 года назад
Thank you!
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