Prove set G= {0, 1, 2, 3, 4, 5} is abelian group of order 6, addition modulo 6. | Jayesh Umr

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16 сен 2024

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Комментарии : 67

@RayDusk 4 года назад

Thank you so much ❤️😊 very nicely explained 🤗🙏

@ayushsoni3254 4 года назад

this question comes on my paper and now i am in toilet now i go nd just write down thanks

@AD-jj4vi 4 года назад

Super

@palvidevi8050 2 года назад

😆

@nikhilthaker7794 2 года назад

😂😂😂🤣

@Nithi904 Год назад

🤣😂

@vintagewrestling2234 Год назад

Legend 😂

@nishthagupta875 4 года назад

Thank u so much sir for this great explanation

@shineprincess9527 4 года назад

Thank you so much sir you are superb god bless you

@GT-wm6rd 2 года назад

Best explain sir thanku 👍👍

@Tareq--ri6qe 3 года назад

Great explanation

@div9809 5 лет назад

Thanks sir ; helpful video

@piykum7 3 года назад

Thank you so much. I was unable to understand this on my own.

@sandeepa_chaudhary7 Год назад

So helpful ⭐

@mstdcreation409 5 лет назад

ty so much bhai god bless you

@maheshsahu8960 2 года назад

Thank u sir🙏👍💯

@abhayagarwal5097 5 лет назад

Nice explanation,ty

@nikshithajain3254 5 лет назад

Thank you so much😊🙇

@ashishkumar24 5 лет назад

Thanks you saved me!!!!

@ChessKaChaskaa 5 лет назад

Very helpful sir

@MadhuriCreationsForyou 2 года назад

Great explanation 🤗

@mukulncertmathematics7696 5 лет назад

Nice explaintion and keep it up

@nishantyadav1540 2 года назад

well explained !!!

@rajeshbhandari418 5 лет назад

Thanks sir

@britadilpathak4975 Год назад

Explanation is very good

@EasyExamNotes Год назад

Thanks and welcome

@DurgeshSingh-ho7qe 9 месяцев назад

Thanks for explaining in hindi language

@abhishekahirwar4622 7 месяцев назад

Amazing sir

@anayap.r.k936 4 года назад

Thanku sir

@shakirfarooq4642 5 лет назад

Thank u

@shoaibkhan6134 2 года назад

Awesome bhai

@rajpalsingh3790 4 года назад

Thanks

@vasueva1856 3 года назад

thank you sir dil se

@EasyExamNotes 3 года назад

So nice of you

@levi-lb6dp 5 лет назад

Thankyou so much bhaiiiiiiiiiiiiiiii

@bhargavbhargav9431 2 года назад

Thank you sir

@zaidshaikh4493 4 года назад

Very nice

@binunk9647 4 года назад

Tnq so much sir

@EasyExamNotes 4 года назад

Most welcome

@maazajaz1944 Год назад

Waching 1hrs before exam, very ez explanation

@vasuchaudhary 5 лет назад

Bhaiya ismai order of each element of G batadijiye please...😇😇😇

@divyanshupurohit7 Год назад

Sir i confused in existence of identiy and commutative law because both are same property. 😳😳

@technokhan9316 5 лет назад

Jabbr guru gee

@322-pinkidhobi9 2 года назад

Determine which of the following are group justify (1) 2z, the set of even integers under multiplication. Sir how to solve this question please sir send me solution

@shivanirawat4073 5 лет назад

Thnq

@vijaysanwal9817 2 года назад

🙏🙏

@anjaneyasharma322 3 года назад

Take any two elements and add Then check whether their sum is 6. groups whose sum is 6 are abelian

@allrounderjerry8298 4 года назад

With out 0 in the set addition modulo is that possible?

@roshnithakur7129 2 года назад

Thank you bs exam m aa jaye

@Vipmoviehub 4 месяца назад

In this question why are not use of order 6 (In previous video of modulo multiplicative case u use 7 why please anyone clear my doubts)

@DhanDarpan 2 года назад

kon gavna se bhau

@himanshu8006 9 месяцев назад

Can you please explain why 0 is the identity element in this case, whereas in another video we did it with respect to multiplication module 7 the identity element was 1?

@dreamasossc 9 месяцев назад

addition me aur multipiliction me different hote hai

@dreamasossc 9 месяцев назад

identity element se mtlb hai ki aap jab koi no. identity element se operate karwaoge toh wahi no. milna chaiye ab aap multiplication me 0 se operate karoge toh 0 milega na ki same no., ish liye 1 se karate hai multipication me

@322-pinkidhobi9 2 года назад

Z is integer