PYQs on CONTINUITY| CSIR NET 2011 to 2023 | Short Cut Tricks

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PYQs on CONTINUITY & its Properties CSIR NET 2011 to 2023 Short Cut Tricks
#csirnetmaths #csirnetmathematicalscience #csirnet

Опубликовано:

14 июн 2024

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Комментарии : 54

@sheemanitinsan7235 12 дней назад

I went to many institutions and invested a lot of money 💵 but no one ☝️ taught like you …..and you taught so very well 👌 without any fees thank you so much dear sir ❤

@Achukutty25 7 дней назад

My prayers and wishes are always for you sir 🙏

@steel679 12 дней назад

very helpful sir `thankyou so much sir .

@goutamjana1292 13 дней назад

Very helpful sir . Please upload more videos.

@pusplatasahu5738 12 дней назад

Superb session.....❤

@shaswata07 13 дней назад

Very helpful ❤

@rnithyaraj9498 13 дней назад

Tku sir Your videos very use full sir

@rashmimalik9769 13 дней назад

Bahut jyada helpful h sir ji

@SanchitMehra-mf3rh 13 дней назад

Thanks again ❤

@rajkumarmanna3855 12 дней назад

Thank you so much sir ❤

@shubhamkumartiwari2379 10 дней назад

@Dr.Harish garg , at 1:16:37 csir net June 2019 . Sir In this problem options (c) and (d) are also correct.

@anuragpandey4912 12 дней назад

Thank you so much sir 🙏🏻🙏🏻🙏🏻

@ranachanda2839 13 дней назад

Thanks sir...❤

@mathematicslovers2888 12 дней назад

Very nice explanation, thanks sir

@user-mk1gu4ug6p 13 дней назад

Thank you sir😊

@itsyourdev5143 13 дней назад

Thank you sir 🙏

@ChandanKumar-dn9lz 13 дней назад

Thanks a lot sir jee .

@ankitadangi1655 8 дней назад

Very helpful 🎉🎉🎉

@siddhusiddharthan161 13 дней назад

Thank you❤ sir

@user-ec3dq2bf1c 12 дней назад

Really, you are teaching Real analysis, sir; thank you so much for sharing such videos.

@imkunalkapoor 13 дней назад

Sir this is very helpful please upload next 2 lecture very soon please your trick very helpful in exam

@positivethoughts6419 12 дней назад

Really you are great sir ❤

@user-uw2gv7vc6i 7 дней назад

Thanku sir

@PIMMATHS 12 дней назад

Thanks sir ji

@professorragavan9783 13 дней назад

Thank you sir

@sumitsharma2926 13 дней назад

Thank u sir ❤️❤️❤️❤️

@steel679 12 дней назад

solid content sir

@BEGINNERMATHS 13 дней назад

Thankyou sir

@vikasmehta8027 13 дней назад

Thanku sir❤

@shreya2262 12 дней назад

Thankyou

@intelligencecorner609 12 дней назад

You are genius sir

@relaxingmusicvideo1298 12 дней назад

love you sir❤❤❤

@sheemanitinsan7235 12 дней назад

You are the best teacher 🧑‍🏫 in all the world 🌍 ❤ king of mathematics 🧮

@RadhaKrishna-uv5zx 13 дней назад

❤

@thibakarrasu1786 13 дней назад

🎉❤

@anamfatima3524 12 дней назад

Please upload the next lecture,

@SunitaPooran-bi8gj 5 дней назад

37:24 can anyone tell me..why sir had not taken compact subset A...why he has taken A=R

@Dearbhanusir 2 дня назад

Yes A can't take R because A is compact

@prabavathig462 13 дней назад

Sir... Please... Which software you are using for screen recording this video ?

@ASHISHKumar-zu7xo 10 дней назад

Please explain in bilingual. Your lecture is very useful for me. Thanks sir

@steel679 12 дней назад

😃😃

@saikatmalla7390 12 дней назад

sir last request..... please upload a video on pyqs of ring theory.... 🙏🙏

@theexpress85 11 дней назад

🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏

@professorragavan9783 11 дней назад

8:17 I have a doubt in selection of option c. We neglect [-1,1] because 0 belongs to it. Similarly option C also have 0. Then why we take as a correct answer?.... Please someone explain me 😢

@DrHarishGarg 11 дней назад

The given option is set not interval because 1/n, n€N given .. So we need to find the function corresponding to this set and then check it continuity.... For example, for a and b option, function is given , but for c and d , function is not defined.... That's why, first defined the function and then check... Hope it help you.

@professorragavan9783 11 дней назад

Yes sir thank you ❤