Python HackerRank Solutions: Power - Mod Power 

Hey, let me explain to you more clearly. The pow() function in Python can take two or three arguments. With two arguments, say A and B, the statement pow(A, B) calculates A raised to the power of B. This is the same as writing A**B in Python. If you want to find A raised to the power of B, then take the result modulo C, you can use the three-argument version of the pow() function. The modulo operator (%) gives the remainder of a division. So, (A**B) % C first calculates A raised to the power of B and then finds the remainder when that result is divided by C. Instead of writing (A**B) % C, which can be slow for large numbers, you can use pow(A, B, C). This does the same calculation but more efficiently. Is it clearer now?