Sir, I attended your class today for the first time U have explained each and everything very patiently Thank you so much Sir Liked the class 👌 a lot 👌
Thanks a lot sir. Thanks for curating all the concepts of quadratic equations in one video using previous year. Very very useful for students who have completed their quad and coming here for practice. The best part of this video is sir have explained each and every concepts.
Bro it happened coincidently... Like if we take -b/a the the expression will become (-a-3)^2 right.Then when you will expand it, it will become (-a)^2 + (-3)^2 + 2(-a)(-3) which is same as (a+3)^2. i hope my explaination is good enough
Sir, at 1:56:12, if we substitute the options in the equations, we will get positive values for all right? Why don't we do it that way? Further, even in the new eq you had made afterwards, if we substitute 6, we will get 5 as the answer which is higher than what we got for 12
Kavith here we have to find the maximum value of n, aap overall function ki maximum value check kar rahe ho... hum function ko simplify karne ke baad n ki jitni maximum value lenge overall function ki value utni minimum ho jayegi, kyuki simplify karne ke baad n denominator me hai, that's why maine equal to 1 put karke solve kiya kyuki 1 is the lowest positive integer... and thereby we will get maximum value of n
nhi we can’t a tip is 6 ke pehle + hai to ese numbers lo jinka + hone pe middle value (5) aaye. 3+2 it is. This isn't a rule just a quick trick. 6 and -1 will not work.
Doubt: (1:39:40) The question says "must necessarily be" but there are points on the Y-axis nearby origin which do not give solution, so how can we consider set of "all" integers? I got the answer: empty set (must necessarily)
1.X axis is a part of domain, so we will check it through y axis... 2. Since here sign of a is not define.. So it could be upward or downward parabola... 3. In case the result is upward parabola then s will be empty and in case of downward S will contain integers that's why B option is correct
@@ramantiwari1205 i got this point of yours, sir. But my doubt is that the options mentioned "all" integers If it was mentioned set of integers, then definitely option B would have been the answer due to negative 'a' but in the option it mentions "all" integers
