Тёмный

Quantifying efficiency: O( ), Omega( ), Theta( ) 

Design and Analysis of Algorithms
Подписаться 10 тыс.
Просмотров 89 тыс.
50% 1

Опубликовано:

 

15 сен 2024

Поделиться:

Ссылка:

Скачать:

Готовим ссылку...

Добавить в:

Мой плейлист
Посмотреть позже
Комментарии : 16   
@jsridhar72
@jsridhar72 7 лет назад
Cannot understand 100n+5 is O(n2). Could have been explained better. Also the entire lecture assumes many things. Its not suitable for beginners.
@christopherwallace893
@christopherwallace893 7 лет назад
did you find any better videos?
@raghav.73
@raghav.73 6 лет назад
it can be O(n^2) and after that he also clarifies that it could be O(n) also.It was just an example.
@balakrishnanr648
@balakrishnanr648 2 года назад
@@raghav.73 ​why cant for c = 101 n0 = 2 itself?? it stays true all the constraints. So why not ? and that's best na - as what I say is LEAST UPPER BOUND.
@stephennehemiah
@stephennehemiah 5 лет назад
Clearly CMI/IITs and all those institutes can't have sound proof cabins for those who develop MOOCs argh
@teja.4
@teja.4 5 лет назад
How much I learned from college O(logn) And here is O(n)
@PythonisLove
@PythonisLove 4 года назад
I don't understand why this has been marked for beginners, it was better to be mentioned that, you need to have some previous knowledge on Algorithms before doing this course!
@shashanks8453
@shashanks8453 3 года назад
It has been mentioned in the first lecture that the course takers should know basics of programming and data structures. And usually a first course on ds and progg. talks about basic ideas of algorithms and its analysis
@balakrishnanr648
@balakrishnanr648 2 года назад
​@@shashanks8453 why cant for c = 101 n0 = 2 itself?? it stays true all the constraints. So why not ? and that's best na - as what I say is LEAST UPPER BOUND.
@Rishi11
@Rishi11 8 лет назад
can you make these videos public
@vijaydesai9983
@vijaydesai9983 6 лет назад
background noise is very disturbing
@rprustagi
@rprustagi 4 года назад
for n^3 Ω n^2, n0 =1, and not n0=1 This is because, for n=0.9, (.9)^3 < (.9)^2 this is true for any n
@rprustagi
@rprustagi 4 года назад
This is especially when n is non-integer. But when n is integer, above is true.
@princeraiyani3468
@princeraiyani3468 7 месяцев назад
Where to find presentation?
@NiltraGaming
@NiltraGaming 3 месяца назад
improve the explanation to be more beginner friendly
@ShyamalDas-kd5vt
@ShyamalDas-kd5vt 4 года назад
Video and the person isn't interesting 😂