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Rate Law 

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Need help preparing for the General Chemistry section of the MCAT? MedSchoolCoach expert, Ken Tao, will teach you what you need to know about Rate Law for kinetics. Watch this video to get all the mcat study tips you need to do well on this section of the exam!
Rate laws are equations that relate reaction rate to the concentration of reactants. The generic form of the rate law is the rate constant “k” of a reaction multiplied by the concentration of reactants raised to an exponent.
Rate constants, discussed in another video, are proportional to the temperature of a reaction and inversely proportional to the activation energy of a reaction. The exponent of reactant concentration, “x”, is the reaction order, a number which specifies how the reaction rate responds to a change in reactant concentration. The rate order can be one, two, or any number. If the rate order is 1, doubling reactant concentration will double the rate (21 = 2). If the rate order is 2, doubling reactant concentration will quadruple the rate (22 = 4). The rate order of a reactant can be determined in one of two ways: either via experimental data or by analyzing the elementary steps of a reaction.
Determining Rate Order with Experimental Data
An example reaction from which to determine rate order experimentally is shown.
Experimenters will run a number of trials of the reaction, in each trial varying the concentration of a subset of the reactants, while measuring the rate of product formation. For instance, see the data below:
1. Step one of determining the rate law is remembering that rate is equal to the rate constant, k, multiplied by the concentration of the reactants, A, B, and C. The experimental data is used to find the exponent of each reactant.
2. Step 2 is to analyze the experimental data. The best approach is to determine the exponents one at a time. Pick two trials where the concentration of all but one of the reactants stays the same. By manipulating only the concentration of one reactant over two trials, we know that any differences in product formation are due to that one change. For instance, note that over trials 1 and 2, only the concentration of reactant B changes, from 0.2 to 0.1.
3. Step 3 is to analyze how the rate of product formation changes between the two selected trials. We can see that the rate of product formation didn’t change from trial 1 to 2. Therefore, the term [B]y did not change from trial 1 to 2. The only way this could be possible is if changing the concentration of [B] has no effect on rate. The term [B]y has no effect on rate if and only if it’s exponent is 0, because any number raised to the zeroth power is one. Therefore, y = 1. Similarly, by comparing trials 2 and 3, the value of x can be determined to be 1. Comparing trials 3 and 4, the value of z can be determined to be 2. The final rate law is therefore:
Rate Law from Elementary Steps
The rate law of a reaction can also be found by using elementary steps. Elementary steps describe the individual steps that are actually occurring during the reaction. You are only able to tell if a step is elementary if the MCAT provides each step of the reaction mechanism. Elementary steps cannot be determined if you’re given only the overall reaction for a multistep reaction. For instance, see the reaction below, broken down into two steps.
The step indicated as the slowest step is the rate determining step. However, a rate law can be written for each step of the reaction. For each step, the rate law is written as k multiplied by reactant concentration raised to some exponent. Here’s what’s different: using elementary steps, stoichiometric coefficients become exponents. For step 1, the coefficient of A is 1 so it’s exponent in the rate law is 1. The coefficient of C is 2 so it’s exponent in the rate law is 2:
Looking at the rate law for the second step, keep in mind that only aqueous and gaseous substances are included in the rate law, which means solids and liquids are excluded. The molecule I, a solid, is not included in the rate law for the second step.
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7 сен 2024

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Комментарии : 21   
@mup1537
@mup1537 2 года назад
This video was excellent. Provided in the context of mcat Q's and clear, procedural, and succinct. Deserves far more views.
@seanoconnor311
@seanoconnor311 2 года назад
This was fire. When's the merch dropping?
@e-2758
@e-2758 3 месяца назад
Lifesaver. You are so concise and clear in the way you teach. Thank you!
@tristenmelvin1855
@tristenmelvin1855 3 месяца назад
This freaking video is awesome. Was so confused on this topic and came back to relearn it!! Gonna be returning to this playlist
@AlishaSlomers
@AlishaSlomers 21 день назад
such a great explanation! thank you
@getitdone0010
@getitdone0010 8 месяцев назад
Deserves far more views
@LindseyDeaver
@LindseyDeaver Месяц назад
Thank you!!
@ANNALERCH
@ANNALERCH 2 месяца назад
Do you combine the rate laws of steps 1 and 2 to get an overall rate law for the entire reaction?
@dreamchaser5173
@dreamchaser5173 5 месяцев назад
This was excellent. Thank you so much!!
@MedSchoolCoachMCATPrep
@MedSchoolCoachMCATPrep 5 месяцев назад
Glad it was helpful!
@emilybernal4736
@emilybernal4736 7 месяцев назад
thank you! this was incredible!
@MedSchoolCoachMCATPrep
@MedSchoolCoachMCATPrep 7 месяцев назад
Glad you liked it!
@Obamnaz
@Obamnaz 2 года назад
Can you do a video on the integrated rate laws please?
@dikigurung2222
@dikigurung2222 11 месяцев назад
thank you for saving my life
@dwl2601
@dwl2601 6 месяцев назад
When determining rate law from experiment data, do we also only use gaseous and aqueous reactants in the rate law?
@denissemedina4619
@denissemedina4619 5 месяцев назад
In that case it does not matter.
@rachel39321
@rachel39321 Год назад
At the end you wrote/said that reaction order is the stoiciometric coefficients but that is not actually the case. even it happens to be the same number occasionally, they are not related.
@diannenewcomb9781
@diannenewcomb9781 Год назад
Yes. The rate order usually isn't the coefficients. Rate order aka exponents need to be determined experimentally.
@carinaashcraft1627
@carinaashcraft1627 2 года назад
Best explanation
@misaestudiando
@misaestudiando 2 года назад
Do the trials you pick to determine rate always have to be next each other? For e.g. lets say Trial A has x2 change between trial 1 & 3, and Trial B & C remain unchanged. Because there was a "jump" would it still be okay to calculate reaction order with those values?
@MedSchoolCoachMCATPrep
@MedSchoolCoachMCATPrep 2 года назад
Nope, you can always pick any two trials to work with!
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