Thank you very much for this immense work, what is remarkable in all your videos is the clarity of the reasoning. I regularly watch electronics lessons and you are the best! Most teachers film their lesson board from a distance, which makes it unreadable. You have done a tremendous job because I imagine the time you must have spent. The fact that you are alone in front of the camera allows concentration. On the other hand, I don't really like electronic whiteboards because some colors stand out badly like green. The designers of the whiteboard could have put shortcuts on the edges or directly on the pencil to select the colors and the eraser. You have to pull down the whole menu to select a color which could be done with a button on the pencil. A huge thank you, I'll watch everything ;-)
i don't agree with you, electronic whiteboards are really helpful, like attaching pdf files, and when it comes to the color of the pen this is the choice of the professor and not the fault of the designer, the professor can chose the dark colors and light colors, also whiteboards have the feature of new page which is a big advantage than the classic whiteboards because of the time wasting in erasing the content that is written on the whiteboard
01:25 - Intro and Review 08:40 - Summery of Feed-Back Concepts >> Sacrifice the Loop-gain to Benefit from the Feed-Back >> The Feed-Back Signal (U) is a Good Copy/Replica of the Input Signal (X) >> The Output Signal (Y) is a Good Scaled Copy of the Input (X) >> Variations in Open-Loop Gain Effect Closed-Loop Gain Less: Temperature, Supply Voltage, Frequency, Load Impedance 23:52 - Example: Poor-Man's Op-Amp 32:50 - Calculating Closed-Loop Gain 38:00 - Breaking the Loop - Calculating Loop Gain 41:45 - Properties of Negative-Feedback >> Gain Desensitization >> Bandwidth Extension >> Modification of Input and output Impedances >> Higher Linearity (dictated by K)
Ravazi misssed out on this point note that that feedback signal from output to must subtracted from the input signal then difference of vin and k*vout is multiplied by gain to produce Vout vout=A*(vin-k*vout )this from just block diagram this equation tells you also that as vin increases vout must increases and as K*vout increases vout must decrease as drain(vout) of mosfet is out of phase with gate (feedback signal (k*vout)) this means as vout increase , k*vout must increase but drain and gate are outphase so vout must decrease you also apply same argument to vin and vout they must be in phase and source and drain of mosfet are phase
The MOS is configured in common gate configuration and thus its gain is gm*RD (not -gmRD) with the source as the positive terminal of the amplifier and the gate as the negative terminal.
