Correction in Q. no 9, Option a and c are made same by mistake (both structures are interconvertible by C2 axis) so if you have chosen any one, either of them are correct.
Sir in question no 5 at 38:48 when you are explaining F attached with TBS then Si with negative charge repels incoming nBu NH2 so that negative charge generated far from Si, then how that F can be removed so that we get TBS intact in the final pdt?
Good morning sir... i have doubt in the q no. 9 that if we rotate upper half and then cyclize we get option c and why a and c are not same ( as if we rotate a along c2 we get c) please ......
Tertiary cation no doubt is formed by Me Shift, but if you count no. of α H and possible hyperconjugative structures, they come out to be 5, while for Ring contracted one they are 7. Migratory aptitude too follows the order as more electron dense group will migrate (Alkyl with more no. of C attached). [Ref: Reactive intermediates in Organic Chemistry by Maya Shankar Singh, Pg 43].
Sir vese sb kuch thik h......aapke concept bhi smjh aate h.......pr teaching method thoda acha nhi lgta...........aapko dekh kr mere college ki ma'am yad aati h. 😊
