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Real Analysis #4 - Fields 

BriTheMathGuy
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24 окт 2024

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Комментарии : 19   
@BriTheMathGuy
@BriTheMathGuy 4 года назад
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@jasonmcclatchie6877
@jasonmcclatchie6877 4 года назад
Thank you for your content. I did an undergrad in electronics many years ago and I hated the maths parts of it, but over the past year or so I have been flirting with it again and thanks to content like yours I am really starting to engage in a way that I didn't think was possible thirty years ago! Keep up the great work.
@BriTheMathGuy
@BriTheMathGuy 4 года назад
Very glad to hear that! Thanks and best of luck!
@Anna-jy7cj
@Anna-jy7cj 4 года назад
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@BriTheMathGuy
@BriTheMathGuy 4 года назад
Very glad to hear it! Thanks very much for watching and commenting!
@sonalkeswani
@sonalkeswani 4 года назад
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@BriTheMathGuy
@BriTheMathGuy 4 года назад
I appreciate that!
@sonalkeswani
@sonalkeswani 4 года назад
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@SamairaXA
@SamairaXA 19 дней назад
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@mahmoudalbahar1641
@mahmoudalbahar1641 3 года назад
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@ahanasharma6947
@ahanasharma6947 4 года назад
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@BriTheMathGuy
@BriTheMathGuy 4 года назад
I'll do my best!
@ahanasharma6947
@ahanasharma6947 4 года назад
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@smoosq9501
@smoosq9501 3 года назад
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@BriTheMathGuy
@BriTheMathGuy 3 года назад
Very glad to hear it! Have a great day!
@pykeselslayer
@pykeselslayer 4 года назад
Given the axioms are the same, what's the difference between a field and a group?
@ajthemagi2913
@ajthemagi2913 4 года назад
Well for starters a group has one binary operation and a field has two, so they definitely don't share the same axioms. For example, the integers are a group because we can add any two integers together and get another integer. However, what is the multiplicative inverse of 2 in the integers?
@leeyoung1112
@leeyoung1112 3 года назад
A group (G,○) has exactly 1 binary operation, while a field (F,●,★) has exactly 2 binary operations. A group does not have to be abelian, but a field is always commutative. A field is always a group, but a group is not necessarily a field.
@leeyoung1112
@leeyoung1112 3 года назад
(F,●,★) is a field if (F,●,★) is a commutative ring such that every elements in F\{0_F} is a unit. Since ●,★ are both binary operations, checking for clouser is absolutly unnecessary.