Rectangular to Polar Coordinate 

Thank you. I appreciate the positive commemt

Get a job and ask your manager to resolve this work issue.

@@ryanmahadeo3132 i figured it out you have to first covert x and y to their polar coordinates and it will make sense

Either with a calculator or using the unit circle.

Theta is equal to the arcotangent of the tangent of theta Having Tan Θ = a/b Just apply Tan^-1 to both sides Tan^-1 Tan Θ = Tan^-1 a/b Θ = Tan^-1 a/b

In 3D there’s just an extra angle phi. It’s called spherical coordinate system

Its the basic coordnates for 60 degrees ( pi /3) with radius 1. Look at a unit circle. Pi/3 is the arc length measure for 60 degrees on unit circle or conversely the angle measure in radians.

Also tanx=(sqrt3/2)/(1/2) = tanx= sqrt 3, to find x you then use arctan of sqrt 3 equaling pi/3

Draw an equilateral triangle with sides of length 1. Drop a vertical from the vertex (top) angle to the center of the base. By symmetry, this line segment cuts the original triangle into two congruent right triangles, each with hypotenuse of length 1, & short-leg of 1/2. Using the Pythagorean Theorem, the remaining long-leg is: √[(1)^2 - (1/2)^2] = √(1 - 1/4) = √(3/4) = √3 / √4 = √3 / 2. We notice that, relative to the larger, 60-degree angle, the long-leg is "opposite", and the short-leg is "adjacent", the ratio of which IS EXACTLY the tangent of 60 degrees. Since, from the problem, tan(theta) = √3 = √3 / 1 = (√3/2) / (1/2), we know that theta is 60 degrees, which is π/3 in radians.

Is it a correct way to think about it?

Only thing is, your method won't work if angle is greater than 180 degrees

@@mrhtutoring thank you

You're most welcome.

Thank you.

You're welcome!