first time i saw the syllabus i was like what is this physics or maths but now u clear my confusions!! your videos are superb love it!! Thank you so much!! keep it up!!!! (Y)
find this method so much easier than another way we were told, to kind of tilt the whole system so you get a horizontal or vertical component haha, thank you !
If you drew the rusultant line of 11.421 at an angle of 40.95 degrees as the presenter sugests...this would be above the 5N force......but it is clear that the R force should be down and to the right ..... should the answer -40.95 degrees?
That force would have no components vertically then. You would not have to split it into components if you were resolving horizontally as all of it acts in that direction.
I am Suparna, a student of a Techno Syllabus, an aspirant of Engineering Entrance Exam in Bangalore. I like your video. I have a query and it wolud be great if you could help me. This is my query- 2. Three forces of magnitude 1N, 2N and 3N are applied on a body in unknown directions. Then, the magnitude of resultant force F (A) shall not be more than 5N (B) shall not be less than 4N (C) shall move the body in direction of 3N force (D) can be 2.5 N Can you explain the solution for this question?