Roman to Integer | Leetcode -13 | Algorithms Made Easy 

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None of my code run in my leetcode

Best explanation for this problem on RU-vid. Thanks.

wow! I never thought of going reverse. I like your explanation a lot! I was using a switch case with repetitive code.

Good Editing, Clear Voice and clean solution. I've subscribed

This channel provides the best solutions. Keep up the good work.

Just wow. I coded this solution from left to right, but it becomes complicated and lots of conditional statements. Right to left is awesome. Thanks.

thanks! I have been stuck on this problem for a while now. you made it make a lot of sense!

The perfect Channel name for the perfect Video. Algorithms made easy.....❤❤❤❤❤

Very easy and simple approach and well explained crystal clear i used to watch this channel for more videos .Thank you 🌟🌟

Just watched the video. This is the kind of explanation I was looking for. Subscribed.

Really a great video, we need more such Leetcode video solutions! Thank you very much for this one.

Your presentation visuals are amazing. Thanks for the content

we can go forward to it also takes O(n) time complexity Ping me if u need the code or a Hint

AMAZING CONTENT!! SIMPLE AND PERFECT!!!!

I have a question, in LeetCode all code should be inside the function? Even the const Map that will be use multiple times? Can I put this map in the Solution class instead?

the perfect explanation and in just 5 minutes!! Thank you.

What's better to use in this case, a hashmap or a switch statement?

you made it easier to understand..really great

Clean, Crisp, to the point code

Thanks for creating this presentation and explanation.

it shows error like this : Line 4: Char 13: error: use of undeclared identifier 'Character' Map map = new HashMap();

thanks for this!! One query , how can we handle -ve cases like below? ("IV", "IIII") ("IX", "VIIII") ("XL", "XXXX") ("XC", "LXXXX") ("CD", "CCCC") ("CM", "DCCCC")

C++ code: class Solution { public: int romanToInt(string s) { map map; map['I']=1; map['V']=5; map['X']=10; map['L']=50; map['C']=100; map['D']=500; map['M']=1000; int result = map[s[s.length()-1]]; for(int i =s.length()-2;i>=0;i--){ if(map[s[i]]

Perfect explanation mam👏

Mam u kept the solution clean and easy.

right to left approach makes it very easy ,thanks

I don't know why but your code is giving wrong output on geeksforgeeks ide

it is really hard to cope pls how do you guys get so good at understanding stuff like this, how does one even learn programming to understand better.

Better than other explanation videos :) Thank you

Explanation is good 👍but help me for program not working showing this Line 4: Char 13: error: use of undeclared identifier 'character' Mapmap=new HashMap();

you just gave me the new perespective to the question Thank you

what if i pass IIX as there is no validation can you please explain

Great explanation. Thankyou so much.😊

Bravo!!! Am clapping.

I don't know why but your code is giving wrong output on geeksforgeeks ide. And one more thing why you are taking s.length()-1 why not s.length() ?

great simple and perfect

easy to understand explanation. Thank you

nicely explained

Explanation and everything was good. But next time please dont cover up your mistakes. We all are humans (Proof: Check 3rd line of the code at 4:36 and 4:38)

Is it possible ? without using Map ?

how can we solve it, without using auxillary space?

very well explained!

Hi mam, i am facing this issue while programming the roman to integer (Syntax Error: invalid syntax ^ Class Solution { Line 1 (Solution.py)) full program I was did:- Class Solution { public int romanToInt(string, s){ Map map = new Hashmap(); map.put("I" , 1); map.put("V" , 5); map.put("X" , 10); map.put("L" , 50); map.put("C" , 10); map.put("D" , 500); map.put("M" , 1000); int res = map.get(s.charAt(s.length()-1)); for (int i = s.length()-2; i >=0; i--) { if (map.get(s.chartAt(i)) < map.get (s.charAt(i+1))){ res-=map.get(s.charAt(i)); } else{ res+=map.get(s.charAt(i)); } } return res; } } Do we have a any method to resolve it?

very nice and easy solution thank you

Thanks a lot mam, this really helped for me !

why we traverse the string from the end???

Super explained mam.

mam y we have to perform only friom right to left why nit from startin g index

why should we go from right to left?plzz

thank you.....

why we are applying a map .why can't put the values in a single line? like (I=1,V=5,C=100,M=1000) LIKE THIS

how that mcmxciv come?

how can we convert roman numbers into numbers(counting 1,2,3) in word document, I tried but not found solution if u have plz share

Your solution is 5 ms. This solution is 4 ms. Which one is better to choose? public int romanToInt(String s) { int sum = 0; for (int i = 0; i < s.length(); i++) { if (s.charAt(i) == 'I') sum += 1; if (s.charAt(i) == 'V') sum += 5; if (s.charAt(i) == 'X') sum += 10; if (s.charAt(i) == 'L') sum += 50; if (s.charAt(i) == 'C') sum += 100; if (s.charAt(i) == 'D') sum += 500; if (s.charAt(i) == 'M') sum += 1000; if ( i != 0) { if (s.charAt(i) == 'V' && s.charAt(i - 1) == 'I') sum -=2; if (s.charAt(i) == 'X' && s.charAt(i - 1) == 'I') sum -=2; if (s.charAt(i) == 'L' && s.charAt(i - 1) == 'X') sum -=20; if (s.charAt(i) == 'C' && s.charAt(i - 1) == 'X') sum -=20; if (s.charAt(i) == 'D' && s.charAt(i - 1) == 'C') sum -=200; if (s.charAt(i) == 'M' && s.charAt(i - 1) == 'C') sum -=200; } } return sum; }

Nice explanation

Thank you very much

Thanks !

Solid Explanation!

Very useful 🙂

best explanation

May anyone please tell me why does my code always ignore the last element? HashMap map = new HashMap(); map.put('I', 1); map.put('V', 5); map.put('X', 10); map.put('L', 50); map.put('C', 100); map.put('D', 500); map.put('M', 1000); int total =0; for(int i=0; i

Thanks di!!

Bro, plz tell me how do I become good at solving these like you? 😭 I Suck more than my life!

thank you

I am your 1000th like, haha!

is this an easy ques? oh ma god

Thanks❤🌹🙏 a lot😊

awesome

Understood :-)

just wow

C++ code pls

Thank you so much

nice explanation