Rope Bed Construction 

+userunavailable3095 THis happens over time and a spacer board fixes the issue without 4x4 construction

Yeah, that would get it too.

+wildernessoutfitters Great video, Dave! Question - Where would you place a spacer board to avoid the classic "bar in the back" situation we get with most fold-outs and roll-aways? Do I guess correctly, one at the knees and one at the shoulders? Or, would one in the middle be best, since one could string it "banjo tight?" Thanks a ton!!! -tom

+Jack Mack easy peasy! Measure the outside width and length. You have 3 runs/lineal ft or 12"per foot. Therefore 48/4= 12 (both sides) the ends = 72/4=18. The formula looks like this: ((((W x R) + (4" x R)) + ((L x R) + (8" x R))) *1.10)/12)))) where 1.10 represents fudge factor and 12 converts inches to feet.. Where R=runs, W=width and L=length. (OD) represents outside measurement or dimension. There are 3 runs per 12" so a 48" wide bed (OD)would have 12 runs, with a length of 72" (OD) That represents 18 runs. ((((48x12)+(4x12))+((72x18)+(4x1)))*1.10)/12))))= (624)+(1368)= 1992" (1992x1.10) = 2191.2" or (2191/12) = 182.5feet.Seems like a lot don't it. The rule of thumb is to add a 10% margin of error, one could get away with a 5% because we are tightening things up (stretching), but I would rather air on the side of caution. You can always use the rope for something else. Algebra too complicated, used lined paper where each line represents a piece of cordage. number them 0, 4, 8, 12, 16 etc... join the lines top and bottom skipping one at each end. Add all your pieces of rope up :)

thanks

Jack Mack UR welcome :)

the size is whatever you want and the rope is as much you have... it's nice to make this rope bed out in the woods (I prefer it as a chair), because you only need to bring the rope. who doesn't like cordage.

I was wondering the amount of resources required, because I see other designs that have a larger spacing in the ropes and require about 100 ft of rope. Since video is deceiving about size comparison, I believe that the bed appears to be about 4 ft by 7 ft, and I would just like to know.

+Greyman Zink fair enough. lets say it is 4x7. count the runs. I'd calculate the edges as half runs bc they only have rope for half of them. so, 4(11+1/2×2) + 7(18+1/2×2)= 4×12 + 7×19= 48+133= 181ft. knots will consume some footage and tightening them after will give it back. I'd call it 190ft of rope and be safe.

Captain85 conventional