Rotational Kinematics Physics Problems, Basic Introduction, Equations & Formulas 

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Saved my ass in Calc yesterday, about to save my ass in Physics and will save my ass in Chem tomorrow.

Thank you!! I only got 3 questions wrong on my physics exam😎 49/56

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How your teacher explains it: ~~~~~~~ How the OCT explains it: --------------------

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I didn't get any help from my physics faculty, but I got you,and you helped me a lot to solve my problems in physics and made me understand better

Huge thanks for this video! Cleared up a lot of confusion I had prior to watching this.

Had an entire mechanics exercise on this as graded homework without having ever been introduced to the concepts during a lecture. Thanks for what you do

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This actually isnt that hard once its explained properly. Thanks.

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6:53 This had me confused and 18:26 this killed meeeee LMAO

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In question 2 part c you ask what the linear speed of a point at the edge of the rotating disk is and just multiply the angular velocity by r to find this. Correct me if I'm wrong but would this not depend on where we are assesing the speed of the point on the edge? If it's on the bottom of the wheel then it would be 0, if its at the top then it would be 2v. You have to specify where to solve that part

how about normal and tangential components of acceleration?

Thank you

Thank you so much I finally understand this... I'm so happy rn 18:54

This help me alot

i love u teacher

for the final question and final answer in revs, is it possible to find the time it is accelerating for?

thanks, very helpful. one thing tho, i try to solve the question on my own so when i pause the video (on pc) the title shows up on the top and i cant see the question so you could maybe move the question statement a bit in future videos :)

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Thanks my friend

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Many people wonder why radians do not appear when we have radians * meters. Here is an attempt at an explanation: Let s denote the length of an arc of a circle whose radius measures r. If the arc subtends an angle measuring β = n°, we can pose a rule of three: 360° _______ 2 • 𝜋 • r n° _______ s Then s = (n° / 360°) • 2 • 𝜋 • r If β = 180° (which means that n = 180), then s = (180° / 360°) • 2 • 𝜋 • r The units "degrees" cancel out and the result is s = (1 / 2) • 2 • 𝜋 • r that is, half of the circumference 2 • 𝜋 • r s = 𝜋 • r If the arc subtends an angle measuring β = θ rad, we can pose a rule of three: 2 • 𝜋 rad _______ 2 • 𝜋 • r θ rad _______ s Then s = (θ rad / 2 • 𝜋 rad) • 2 • 𝜋 • r If β = 𝜋 rad (which means that θ = 𝜋), then s = (𝜋 rad / 2 • 𝜋 rad) • 2 • 𝜋 • r The units "radians" cancel out and the result is s = (1 / 2) • 2 • 𝜋 • r that is, half of the circumference 2 • 𝜋 • r s = 𝜋 • r If we take the formula with the angles measured in radians, we can simplify s = (θ rad / 2 • 𝜋 rad) • 2 • 𝜋 • r s = θ • r where θ denotes the number of radians (it does not have the unit "rad"). θ = β / (1 rad) and θ is a dimensionless variable. However, many consider θ to denote the measure of the angle and for the example believe that θ = 𝜋 rad and radians * meter results in meters. Mathematics and Physics textbooks state that s = θ • r and then θ = s / r It seems that this formula leads to the error of believing that 1 rad = 1 m / m and that the radian is a dimensionless derived unit as it appears in the International System of Units (SI). In the formula s = θ • r the variable θ is a dimensionless variable, it is a number without units, it is the number of radians. When confusing what θ represents in the formula, some mistakes are made in Physics in the units of certain quantities, such as angular speed. My guess is that actually the angular speed ω is not measured in rad / s but in (rad / rad) / s = 1 / s, s^(-1).

10:48 isn’t that final linear velocity formula? Is linear speed the same? I thought it be thetha/t (18 sec) no?

awesome video, you're teaching me a lot lol. For that final question, i paused your video and noticed time wasn't in there. so i solved for time using the kinematic equation, got t then solved for theta using the other equation but i got something completely different. my question is, when im given enough variables to solve a question should i just solve it instead of trying to find EVERY variable? cause once i plugged in T to find theta i got some weird shit. And what i dont understand is why that didn't give me the same answer as the final answer.

In 10:50 isnt that the average angular acceleration? Even though the answer is the same when you find the average linear acceleration it is still wrong to use omega...you should use velocity in finding average linear acceleration

Hello everyone , if somebody could help... as i have learned that we can't apply kinematics motion equations when acceleration is not constant. here in circular motion ,acceleration is not constant as of changing direction so how come we are applying those equations to find the answer, ,kindly advise please. thank you..

3:12 isn't average notated with a line over it?

For part a) of the first question, could u basically just use the equation for period(T), as this is 5 mins and rearrange for 2pi radians, then divide your answer by 2pi?

For final angular speed we suppose to find Wf as we have W0, Alpha and Time. And you found Angular displacement instead.

So whenever Im converting from radians to revolutions my calculator always gives me something different from yours. My calculator is in radians but idk if thats the issue. For example when you converted 150 radians to revolutions I got 235.62 revolutions as opposed to your 23.87 revolutions. Pls help

10:02 why no of Rev coming out wrong if we calculate it through wf omega final 45 rad/s

you find theta by using W*T and anther times you used theta = W*t+1/2 omega *t^2 what is the difference?

My guess is that actually the angular speed ω is not measured in rad / s but in (rad / rad) / s = 1 / s. If we say that the measure β of the angle is θ radians, we mean β = θ rad, and θ is the number of radians (it does not have the unit "rad"). For emphasis we can say that θ is measured in rad / rad, since θ = β / (1 rad) and θ is a dimensionless variable. When we use mathematical formulas to obtain formulas in Physics, we have to know what the variables represent. What I consider a mistake, is present in the literature, it is not only in this video. Therefore, I will leave another comment with the detailed information to be examined.

Lub u Sir

for question 2 part b cannot i just have used theta=angular velocity * time??

The goat

Omega... I mean Theta...... (haha seriously tho love your videos)

i have a physics exam tomorrow ill update depending on how well it goes

9:13 Using the definition of Angular acceleration, Angular acceleration = delta omega/ delta time. Which means it's (2,5) = delta omega/18. Which means Delta omega = (2,5)(18) = 45. Since omega initial is zero, then 45 is omega final. Which to be fair, the video also said that omega final is 45. However, for part b, the video uses an equation that are not explained how it come about. If i didn't square the time and didn't divide it by 2, then the answer for part b would be different (this shouldn't work like this). Any explanation?

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instead of d =vot + 1/2at^2 my book says x=Xo+Uot+1/2at^2

How come for 1b you have to concert back to radians? Is theta not in degrees? And is revolutions always in degrees versus radians?

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Why did you assume the radius on the first question

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in question 3c where did the radians go 4rad/s^2 x .3m = 1.2m/s^2

Ugh I always forget changing the units....

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Why did you use ¢= (Wo+Wf)t/2 instead of ¢ = Wot + (at²)/2

11:35, why is it 0,5 over a radian?

why didn't we use theta=omega t in 2nd problem to find revolutions>?????

Noice!!!

Sorry but where did you get the radius for example 2 @(11:33-34)

3:17 3:54

I would like to point out at 9:17 you didn't input time in WoT, so it came out wrong. So if you put in the correct formula, 0(18)+1/2(2.5)(18)^2 = 423 rad

Instead of 'd' my books says 'X-Xo'

my teacher is making me watch this

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❤

For question 2, my formula sheet says theta=initial theta + omega t + 1/2 alpha t^2. Yours didn't have omega t. Someone explain please :)

9:10 Wait why not use w×t instead ... The answer comes out to 810 so it is wrong but why Someone help...

anyone else stay the extra 30 seconds at the end to see if there was a post-credit scene like a marvel movie :(

Did everyone get 64 revolutions for 2b?

Saving my ass again.

Hi, ineed your help, how were you able to get 23.87 on question number 3 letter a? I've tried it on many calculators now yet I can't het the same answers as yours...help please

vevolution

I guess you missed the t from ex.2

My physics teacher is the worst

I am very sorry to complain like this, I love your videos, but please if you ever make more, do something about the amount of compression or whatever that is on your voice. I literally have a hard time listening to it.