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Thanks for ur explanation Sir.Please evaluate my answers once. 1.private key (77,119) , cipher 41 2.private key (11,24) , cipher 18 3.private key (23,187), cipher 146 4,as plain test which is in binary is greater than n value This can't be done. 5.private key (91,221) cipher 181
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When finding the value of e wch is between 1 and phi(n) and gcd(e,phi(n))=1, are you not suppose to select the lowest or the smallest prime number wch satisfy the condition ...... why you choose 13 if the gdc(7,120)=1 coz 7 is prime and is the lowest prime number we can use as the encryption key
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exercise 2 my public key is (11,35) and my private key is (11,35). C=18 which is 2^11mod 35(where 35 is gotten from 7*5) and D=2 (which is gotten from 18^11mod35)
No its wrong. Public key is 11 given in question and private key d = 11. Your cipher text is true. C = 18. This video share with others and subscribe my channel...Thank you in advanced...
@@ChiragBhalodia Sir, thank you for your explanation. In this case, it seems the encryption can be reversed with the same key. 2^11 ≡ 18 (mod 35), 18^11 ≡ 2 (mod 35). In fact choosing others (like 17) also have same effect, 2^17 ≡ 32 (mod 35), 32^17 ≡ 2 (mod 35). I'm bit confused with this.
@@nirasmann : Sorry for late reply..... In small prime numbers it happen most of time, but during large prime numbers its few chances to remain same.... But now a days there are lot of other algorithms are better than RSA....Please share with others and subscribe my channel... Follow my blog: edu-resources1.blogspot.com/2021/07/rsa-algorithm-rsa-algorithm-explain.html
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exercise 1 my public key is (5,199) and my private key is (77,199). i went into calculating my cipher text with the plain text which was given as 6 so it gave me 15 as my cipher text(C=15). and lastly my D=37
If the sender uses RSS algorithm. So he gets two keys Public and Private. If I want to send someone to public key . By What Method . How will I reach that public key.
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@@ChiragBhalodia but we saw that in rsa algorithm genrate to type key one is public and second is pravite and in this algorithm public key does exchange it's means in this algorithm we use also deffi hell mam algorithm please make video on it in which explain this thing when we use rsa that time how will exchange public key
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How can I thanj you? I study the course, same textbook. You save my time and effort + better understanding. God bless you. Your effort is so appreciated. I am reading all your blog and watching your RU-vid videos.
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I think exercise 2 is wrong. You said that for finding d, you need to do ϕ(n)+1/ e until you get two integer numbers. So how d is 11? Because the ϕ(n) is 24. so if we get like with decimal, we times ϕ(n) which is 24 by 2, until the answer is integer. So i am really confused on how you find d, please help me.
There are 3 method of finding "d", one method is explain here.... remaining 2 methods video will be posted soon... mostly in next week... if you want to check the answer of exercise, blog link is given in description
Advantage os RSA are: It is very easy to implement RSA algorithm. RSA algorithm is safe and secure for transmitting confidential data. Cracking RSA algorithm is very difficult as it involves complex mathematics. Sharing public key to users is easy. Disadvntage of RSA are: It may fail sometimes because for complete encryption both symmetric and asymmetric encryption is required and RSA uses symmetric encryption only. It has slow data transfer rate due to large numbers involved. It requires third party to verify the reliability of public keys sometimes. High processing is required at receiver’s end for decryption. Please share with others..... keep supporting..... Please subscribe my channel.... Please follow my blog: www.chiragbhalodia.com/2021/09/rsa-algorithm-with-example.html
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Thanks Sir 😊 My concept are clear like crystal. Sir I want to download these slides. If you feel comfortable please give link in the description for downloading.
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Sorry for late reply....!!! To find the private key d, the equation is modified you can check in step no 5 (in explanation).... Please share this video with others..... Please subscribe my channel.... Please follow my blog: www.chiragbhalodia.com/2021/09/rsa-algorithm-with-example.html
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Thank you so much sharing this video and also thanx to sharing answers of exercises.... I have try myself to find private key "d". But in small numbers I have get the key, but in large number I have confused and not getting key.... Please can you share how to find "d" for large numbers.... Thank you in advanced...
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I don't know if you will see my comment but i hope so. How did you calculate the mod.? I mean how do we calculate P^e mod n ? I don't know how to do it
Hello, Abou Nasma..... I am reading all the comments and also giving the answer of all the coments with in 24 hours. I will post this method on my blog on tomorrow and share link with you......How it actually works.....By the way.. Here I am writing answer directly because this is the methamatical process... I can't explain that process easily in ppts.... (Follow my blog) Please share this videos with oyur friends and subscribe my channel... Follow my blog: www.edu-resources1.com/2021/09/rsa-algorithm-with-example.html
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Thanks sir, I really understand you lecture, my question is this, can we choose any number for public key if the number is a prime number that fall between the range of p and q
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That was my typing mistake... It was actually (11 - 1) instead of (12-1). Because equation is like Ф(n) = (p-1) * (q-1). Follow my blog : edu-resources1.blogspot.com/
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Yeah because in some university exam, they ask to again find cipher text.... Because there is one condition for plain text, it must be fulfilled otherwise you will not get correct plain text from cipher text. Sorry for late reply... Please subscribe my channel.... Please follwo my blog: www.chiragbhalodia.com/p/network-security.html
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You can take any number...This is just example.... Subscribe my channel.... Follow my blog: www.chiragbhalodia.com/2021/09/rsa-algorithm-with-example.html
No dear, there is no solution. But you can try your own way to solve. Post answer here. If there is wrong then I will help you to solve out.... Follow my blog: edu-resources1.blogspot.com/
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For RSA algorithm, your plain text must be in numerical values only. For example, The plain text message (BHAI) encrypted with (RSA) algorithm, the characters of the message are encoded using the values 00 to 25 for letters A to Z. .. Here BHAI = 33. Follow my blog for more content : edu-resources1.blogspot.com/
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Hello Jonathan, 1. e is public key. (We known that as per public key cryptography, public key shared with each other in network by all users). You can encrypt with public key of any user A, then only user A is decrypt the message. No one else in network. Because private key will be calculated using user A's Public key.. 2. If you are think about examination purpose, which is already given in question. If you have any doubts you can ask me.. Share with others and subscribe my channel.... Follow my blog : edu-resources1.blogspot.com/2021/07/rsa-algorithm-rsa-algorithm-explain.html
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yes, whenever you try to find d (private key), always starting value of i=1... Please share this videos with others and *subscribe my channel* ... *Follow my blog:* www.chiragbhalodia.com/2021/09/rsa-algorithm-with-example.html
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You can check some of examples in my blog: www.chiragbhalodia.com/2021/09/rsa-algorithm-with-example.html Please follow my blog and share with others.... Please subscribe my channel....
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Formula is already given in algorithm... Please share this video with others and subscribe my channel... Follow my blog for solutions: www.edu-resources1.com/2021/09/rsa-algorithm-with-example.html
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I have find this mod using modular arithmetic theorem... Please subscribe my channel... Keep supporting... Follow my blog: www.chiragbhalodia.com/2021/09/rsa-algorithm-with-example.html
Hello Anand, I have solved using modular arithmetic method.... Please share this video with others.... Subscribe my channel.... Follow my blog: www.chiragbhalodia.com/2021/09/rsa-algorithm-with-example.html
As per example number 4, Given plain text P = 00111011 = 59 Public key E = 3. Answer : Private key D = 7 Cipher text C = 20 Again find plain text from cipher text is P = 26 (So, we cannot get origianl plain text from cipher text. Because as per algorithm C = P^e mod n where, P < n. But in this example Plain text is P > n, where P = 00111011 = 59 and n = p * q = 3 * 11 = 33 ) This video share with othes and subscribe my channel...
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Contents available on my blog... Thanks for watching..... Please share with others.... Please subscribe my channel... Please follow my blog: chiragbhalodia.com
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In examination Plain text will be given in question....refer questions given in videos......here I am explaining example...So, I have taken plain text = 13.
Most IMP for tomorrow examination : All cipher techniques,active and passive attack, des, aes, diffie Hellman, rsa, application of digital signature, kerberos, DSA, public key distribution, hmac, all block cipher modes, ssh, SSL
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Modulus is find using arithmetic modular method...... Please share this video with your friends... Follow my blog: www.chiragbhalodia.com/2021/09/rsa-algorithm-with-example.html
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