Setting the operating point in a FET amplifier 

You should have more subscribers. You have some of the best electronics content on RU-vid.

Here I find the most advanced topics discussed! Congrats!! Greetings from Brazil!

Videos should be required watching for all 1st year EE students!

I was serching this Topic, and my favorite channel made videa about It!

Excellent content as always, Fesz! 👌

Very useful informations as usual.

Hey man, always love your videos! I recommend them to all my EE friends. Ever planned on doing anything to do with control theory? Like PID controllers and stuff related to that? I think your natural style of video REALLY helps me. Only regret is that it took me so long to find you haha - would have helped a lot in college!

Good videos! Can't wait for the next topic.

You could also run a "DC sweep" analysis in LTspice instead of varying the gate voltage source with time - the advantage is that you immediately get the correct x-axis.

Thank you 😊😊😊😊 very nice topics

Simply excellent, thanks

Great video.

Hey, great video! Just one question. When do you say saturation mode is the Fet working in linear/ohmic region it isn't? Thanks!

Why did you use ".op 1" at 5:45 and in other simulations, what is the meaning of the "1" argument? I get the same results with just ".op" command without the extra argument.

Again, it's possible to improve on the dc stability against variation of threshold voltage and temperature by using a combination of feedback biasing and source resistor. You can do this by allowing more voltage drop across the source resistor and biasing the gate above ground by a resistor divider from drain to gate and gate to ground. For example, set a drain current of 10mA and allow 4V across the source resistor. So Rs=400R. Then split the remaining 6V equally between the transistor and the drain resistor. So each drops 3V and Rd=300R. The target quiescent bias point is 7V. Since the source is at 4V, the gate will need to be at 4V - 1.8V = 2.2V. Using a current of 0.1mA through the bias resistors gives Rg (from gate to ground) = 22K. Because the drain is at 7V, the feedback resistor Rf (from drain to gate) = (7V - 2.2V) /0.01mA = 48K. Running the simulation with the same extreme models gives a change of quiescent drain voltage from 7.7V to 6.0V as Vth changes from -2 to -6.5V. The change over temperature is 0.1V across the temperature range -20°C to 80°C. The corresponding drain current change is from 7.5mA to 13mA and 0.3mA across temperature.

an active way...... so some current mirror ( i hope this is how it translates)? or maybe some zener ?

Dunno how to write it without being rude, but here it goes anyway: please stop smoking. I started watching your videos from the very first ones, and could not help but notice the detrimental effect. To be on topic, I really liked your project videos, from the every day problem until the finished project. The light sensor, microphone, current probe just to name a few. Do you not do any hobby projects anymore? I mean the theory videos are good and fine (and necessary! you are basically the only youtuber covering eletronics so deeply and methodically). But some lightweight videos would be a breeze of fresh air. Keep up the good work.

"Well that's not good." - FesZ

Man, you have to take some sleep... Take care!

at just before 11:00 the text was white on a white paper background, maybe not the best choice

😃😄😁😆😅 5 Smile's. You have to love negative gain in a circuit like a 555 on a negative and if you put a director to it on the in supply it just will not turn on???? strange no😁you could try light to drain to a negative use one to balance a relay line from flicking due to signal on negative but unlike the relay flyback put that director in and it doesn't work!! again strange no!😁.