First multiply 8x² and 27 = then se divisible by which table whose numbers if added or subtract the answer will be 30. , split and write , then take common in first two and last two , the no.s in brackets will be same , and the the brackets numbers will be a factor and outside number will be a factor , we could only find two only, . Hope you understand, practice makes a man perfect , remember every time in life
@@loveroftaehyung2225 wn they do it's 2×2×2 wn we do 4×2😄 no sir explain in from the mistake coming point of way.. they only know right way .. and there are lot's of such teachers are there and unfortunately very few teach in different point of way that students think and clear all doubt without them need to ask the question . Others do blahaa blahaa.. that's why we also struggle from school level all we got bad teacher equal to bad result
That looks like several steps: 1) factoring two coefficients, 2) identifying which combination of factors provides the right difference, 3) reversing the signs, and 4) performing the final division
better than using the whole quadratic equation to find 2 answers and select one from that if not possible we should give the value of both answers so how is your question remotely connected to the quadratic formula...
It kinda works for every equation but in some equation you will have to use square root of numbers to get the sub equal to b and multiplication equal to ac. Use quadratic /shri dharamcharaya formula there
Nope there are some rare cases the way to check if it will work on the particular equation or not is by using b² - 4ac look that formula up and how to use it
@@shekhar81 This is a root whose answer isn't a whole number. You shouldn't confuse it as a wrong question. The method which the distinguished has provided in this video can only be used for roots which are whole numbers. If you want to find the roots directly, you can use the Sridharacharya's formula : (-b +_(b^2-4ac)^1/2)/2a.
ax² + bx + c = 0 It must be follow two conditions: 1). Product of factors = a * c 2). Sum or difference of factors = b 8x² + 30x - 27 = 0 18 * 12 ≠ 8 * (-27) So don't take 18 and 12.
It doesnt work in all quadratic equations What of equations like f²+25f+150=0 70y²+19y-27=0 This quadratic equations are very simple but trust me, the method you used cant work for this But your method is also good and short
But i think this won't work in exams as the question have a particular heading like "do it with factorisation method" Whatsoever so i guess it only works if you you want to check if the answer is correct or not
It is your choice,if the question has given you to find the zeroes by quadratic then do it by the quadratic formula and if it has given you to find it with MTS then find by MTS only,if neither nis states then you can use whatever you want
You can do thos problem with factorisation method mentioned in the video First take 4 common to do less calculation it will become 4(x^2 -4x+4) =0 Split the middle term such that multiplying it will result in 4 and adding it will result it in 4 so it will be x^2-2x-2x+4=0 Take x common from the first two terms and -2 common from the last two terms it will become x(x-2) -2(x-2) Next take x-2 common in the first bracket and then put the remaining terms in the second bracket It will be (x-2) (x-2) =0 Then by zero product rule X-2=0 x=2
Bro it's Y² - 37y +300 So, y×300=300 Then ,take common factors 2×2×3×5×5 Now make two parts whose addition is 37 and multiplication is 300 So 2×2×3 + 5×5 We got the mid term .now Y² - 12y - 25y + 300 Find common in in y²-12y and -25y + 300 So, Y(y-12)-25(y+12) Find the common Then, (y - 12) and the remaining, The ans is, (y - 12)(y - 25)😊😊 By the way my age is 15
