You prolly dont give a damn but does anyone know a method to get back into an Instagram account..? I somehow lost the password. I love any tips you can offer me.
Thank you so much!! That was a wonderful breakdown of concept and the math process. The dude in the jacket showing up was hilarious too, broke the tension of all that math for a bit lol.
So man, First question, I wonder can we do convolution to more than two functions? Second, I have a project, for now, I want to put a chirp inside of a song and detect this chirp in the song in the matlab. Should I use anything involved with convolution? Or should I use Fourier format? Please let me know!
at 16:15 when you give the answer to the integral, should it not be 2(e^(-t) +t -1) instead? exponent of e would be -t as opposed to -tau edit: I see this small slip has been addressed a few times already. Excellent video over all that I'm grateful to have for free.
the "slip" is not so "small". The whole time, he is supposedly trying to find y(t), the output of the system as a function of time. Then he gives an answer containing τ and t. This is not a calculation error, which can happen sometimes -- it does not even make sense.
Why do the taus that are part of the solutions to the individual integrals (like for t between 0 to 1) change to ts when we are presented with the final piecewise solution?
Am having issues on how to break up the integration into multiple parts, like where do i start where do I finish, if someone illustrate that part for me it will be very helpful.
We wanted to show the process more than the result. A graph of the output may be nice, but in this example I believe it would not show any intuitive representation of the convolution process. Also, the graph is a bit difficult to draw accurately as it is not a standard function. For these reasons, we thought it best to not graph the output. - Andrew
What? He confused the shit out of me when he's explaining how to find the convolution of h(t)=2e^-2x and the x(t) he came up with. When t is less than zero, h(t) will go to infinity, not zero, how can the convolution give zero for values of t less than zero?
It is the product of h(tau) and x(tau) that is zero. Not h(tau) itself. I see why it might be confusing, but I also think he forgot to mention that for those inputs he uses all function values for tau < 0 are 0. They are causal inputs. So h(tau) follows: 2*e^-tau tau >= 0 0 tau < 0
Lycanid is correct. We should have explicitly used multiplication by the unit step function in the descriptions of x(t) and h(t), which would make both functions 0 for t
Were sorry for your confusion, the use of tau here is only a dummy variable. As you can see in the definition of convolution, the tau is integrated out. The tau is simply used to represent the function variable as we slide the "input" in time. I hope this helps! -Andrew
Solving such simple convolution graphicaly is a total waste of time! Just use the step function to define the piecewise function and then calculate the conv integral analytically. It took me 20 seconds exactly...
Since I aready fully understand what is CONVOLUTION . I agree with Your explaination . I SEE 10% FULLY DO NOT KNOW what You are talking about since They are the ABSOLUTE beginner ! I doubt whether 90% understand what You are talking ? without blurr? To Inprove Your teaching ,You should use MOVING PICTURE INSTEAD of STATIC-SNAP SHOT PICTURE ! GOOD try to explain what is CONVOLUTION ! keep it up !
First of all remove that noise in the video beginning...that was irritating... someone wants to study and you are playing this noise in the beginning of your video....
is this guy for real ? At 16:18 he gave the result for an integration over tau and this result still contains tau (his integration variable). Seriously ?? And he even checked it on his so-called calculation that he did beforehand... Does this guy have a degree or teaches grad students ? I hope not....
We apologize for this small error. The variable in question should obviously be a ``t'' not a ``tau''. We do these videos in as few takes as possible so that continuity is preserved. Zac is a wonderfully smart man and even the best of us make mistakes. We believe that his explanation of the Convolution theory and worked example is superb, useful, and far outshines the small error in notation. ~Andrew
Were sorry if there is a problem with our explanation. I assure you that we work very hard on these videos and that those presenting them are qualified to do so. We may prepare solutions beforehand to keep the videos short (as you can see, they get very long) and we are all humans who make mistakes from time to time. If there is something we can do to improve how we present this information, please let us know. We are always open to advice and criticism.
if he would have memorized it then he would never had made a mistake.his approach is clear .the only bad thing was he made some careless human mistakes
