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Simple yet 5000 years missed ? 

Mathologer
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Good news! You really can still discover new beautiful maths without being a PhD mathematician.
Stumbled across this one while working on the magic squares video. Another curious discovery by recreational mathematician Lee Sallows. A simple and beautiful and curious fact about triangles that, it appears, was first discovered only 10 years ago. Really quite amazing that this one got overlooked, considering the millennia old history of triangles.
Wiki page dedicated to Lee Sallows
en.wikipedia.o...
His personal homepage
www.leesallows...
The relevant subpage
tinyurl.com/y6t...
t-shirt: www.teepublic....
music: Campagna - Adventure of a Lifetime
Enjoy!
Burkard

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1 окт 2024

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Комментарии : 666   
@asheep7797
@asheep7797 7 месяцев назад
Sometimes you wonder how mathematicians come up with things... Other times, you wonder how mathematicians don't come up with things...
@CheckmateSurvivor
@CheckmateSurvivor 7 месяцев назад
Most modern "science" is full of mathematical nonsense. Like the shape of the Earth. Maths doesn't match reality.
@BritishBeachcomber
@BritishBeachcomber 7 месяцев назад
The best math comes from Side Projects. The things you think about when you should be doing something else.
@robertveith6383
@robertveith6383 7 месяцев назад
They are "discovering" the things.
@mapron1
@mapron1 7 месяцев назад
how you develop 'wonder' thing? I am not wondering at anything
@devalapar7878
@devalapar7878 7 месяцев назад
@@robertveith6383 Not only. They also develop things.
@Just.Kidding
@Just.Kidding 7 месяцев назад
The absurd grammar in that title leads me to believe you are indeed a mathematician.
@Dipanshu111
@Dipanshu111 Месяц назад
😂
@zzzaphod8507
@zzzaphod8507 7 месяцев назад
This is a great length of a Mathologer video, nothing wrong with this! Thanks
@Mathologer
@Mathologer 7 месяцев назад
This short format appears to get the thumbs up from many regulars. Nice :)
@zzzaphod8507
@zzzaphod8507 7 месяцев назад
@@Mathologer Yes, long, short, medium--all good, and a viewer would be foolish to complain about a short video if the alternative is no video at all. Whatever length suits your schedule and the video's content best. Of course it's not ideal to increase the quantity (minutes of videos produced per year, say) at the cost of quality, but I've never noticed that in a Mathologer video, so not an issue in this case!
@Ryan_Thompson
@Ryan_Thompson 7 месяцев назад
@@Mathologer Same here! I don't always have time to sit through a lot of the longer ones unless they're a direct interest of mine, but I'll click on these shorter ones any day of the week.
@Xubono
@Xubono 6 месяцев назад
@@leif1075if you can see the area of the blue triangle is exactly 1/3 of the original triangle, you can use the same reasoning for the red and green triangles. In the latter two, you’ll be using the outer red triangle side and the outer green triangle side, NOT the blue triangle side. Each coloured triangle area is 1/3 total area of the original triangle. They are the same area in all three views (blue, red, green), despite the different bases and heights.
@harvey66616
@harvey66616 6 месяцев назад
@@leif1075He _does_ show that the base of the inner triangle is the same as the outer where that inner triangle is located. _It's the same exact line segment_, so of course it's the exact same length. Each of the three inner triangles are positioned at a different side of the original triangle. So they don't actually have the same base as each other. But they always have the same base as the line segment where their own base is located, hence the bases are always the same. FWIW, your apparent concern -- that the bases aren't all the same length (and again, _all_ the bases aren't all the same length...just when each inner triangle's base is considered with the specific side of the original triangle where that inner triangle is located) -- would also apply to the height of the inner triangle. I.e. the heights are not all the same either; each height of each inner triangle is exactly 1/3 the height of the original triangle when measured from the side that the inner triangle shares, but each of the three inner triangles' heights may well be different as well. The proof in the video demonstrates the equal bases and 1/3 height only for a single inner triangle. You then have to extrapolate the same logic for the other two inner triangles in the diagram. If it helps, make sure you rotate the whole diagram so that both the inner triangle and the original one are oriented with their bases at the bottom of your visualization.
@jonadabtheunsightly
@jonadabtheunsightly 7 месяцев назад
You had me going at the beginning. Because of the particular choice of original triangle, you briefly had me wondering whether the "folded" triangle might be (geometrically similar to) the mirror image of the original. But no, not in the general case.
@opensocietyenjoyer
@opensocietyenjoyer 7 месяцев назад
only in exactly one case, the equilateral, the triangle is the same as it's folded counterpart.
@notEphim
@notEphim 7 месяцев назад
@@opensocietyenjoyer You're wrong! You will also get the similar triangle if centroid coincides with one of the Humpty points (projection of orthocenter onto the median). This is because medians to sides will be in ratio sqrt(3):2. In case of equilateral triangle orthocenter already coincedes with centroid, so it's a simple case
@DavidSartor0
@DavidSartor0 7 месяцев назад
@@notEphim Yay.
@marksteers3424
@marksteers3424 7 месяцев назад
I love the second "simpler" proof. It is intuitive and I can even explain it to members of the family who are not true maths lovers.
@doommustard8818
@doommustard8818 7 месяцев назад
Sometimes when I'm just goofing off with math or science I notice weird things and think "there's no way someone hasn't discovered this yet" and just don't think about documenting my findings. this is what happens when every mathematician on the planet did that for 5000 years straight
@nosy-cat
@nosy-cat 7 месяцев назад
I think I'd honestly prefer the first proof, but I was too busy shouting at the screen about the second proof to enjoy it.
@tanyachou4474
@tanyachou4474 7 месяцев назад
Hahahah very meta 😂
@pyrouscomments
@pyrouscomments 7 месяцев назад
9:48 apparently he could hear us from the past
@tanyachou4474
@tanyachou4474 7 месяцев назад
Meta I meant @czertify’s comment some how remind me of Pierre de Fermat’s comment, I am not sure if it’s intentional to subliminal but it is just somehow made it even funnier for me
@tanyachou4474
@tanyachou4474 7 месяцев назад
Meta I meant @czertify’s comment some how remind me of Pierre de Fermat’s comment, I am not sure if it’s intentional to subliminal but it is just somehow made it even funnier for me
@ilikemitchhedberg
@ilikemitchhedberg 7 месяцев назад
Circle lovers been real quiet since this dropped 🤔🤨
@Mathologer
@Mathologer 7 месяцев назад
:)
@JeanYvesBouguet
@JeanYvesBouguet 7 месяцев назад
The duality relationship between the triangle and its folded form is simply beautiful. As a triangle lover, I absolutely love this video. I cannot believe this was not known.
@savonliquide7677
@savonliquide7677 7 месяцев назад
Please look at the answers i put in the comment of "i l put username later" to link this duallity with the usual midpoint duallity (involving hexagons ABCA'B'C' such that (XY)//(X'Y') \forall X e Y \in {A,B,C} ) This make me wonder if there is not a way to combine opposite triangles and this new duallity in the space of positive triplet that satisfy triangular inequality and that sums is 1 (exept for 000) . The orientation will matter in order to get opposite triangles, we would like to be able to do addition (such that the addition of two opposite gives the emptytriangle (0,0,0)) and a multipplication such that a triangle multiplide with its inverse (defined by the new duality) or maybe the opposite of its inverse gives an equilateral triangle, in such a way that we get a nice structure, why not a field (we will probably get an isomorphism of a well konwns field, I'm thinking about quaternioons because it is the only 3 D field I know and maybe the only one possible, I really don t know much about it lol) Really to many suppositions here so I ll have to stop here not to be ridiculous, but it might be interesting to search something. Note that it is easy to get a tripplet of homogenous coordonates that satisfy triangular inequality (and that are decided equal up to scalar multiplication ) from a triplet of 3 real numbers up to scalar multiplication : take the angles that are obtain with a triangle that vertices are (a,0,0), (0,b,0) and (0,0,c) in the 3-d space. (indeed we get all triangle that angle are all less then pi/2 , which are also triangles s.t. the mesure of angles satisfy the triangular inequality, isnt it nice?^^) I will do a litlle homemade video to talk about this, and I ll give the link^^ Thank you Mathologer for this video and every single other long or short one❤❤❤
@tolkienfan1972
@tolkienfan1972 7 месяцев назад
I like both proofs. They scratch different intuitional itches. 😁 I've always found it satisfying to arrive at the same place by different mathematical routes. I think it helps cement the ideas, and also expands intuition.
@Mathologer
@Mathologer 7 месяцев назад
Same here. I've been obsessing about identifying the "second best proofs" for theorems for a long time :)
@Kram1032
@Kram1032 7 месяцев назад
so this is a kind of duality between two different triangles, neat
@dbalpert
@dbalpert 7 месяцев назад
Yes, I was wondering as I watched the video if the folded triangle would be called the “dual” of the original (as you have wjth polyhedra) or has some other name. And, are there other interesting properties of the dual as relate to the original?
@pauselab5569
@pauselab5569 7 месяцев назад
Well duel is supposed to mean something very different. You put points at the middle of line segments then draw a line between any 2 points that once shared a point.
@TheOneMaddin
@TheOneMaddin 7 месяцев назад
The term "dual" is very general and is used all over mathematics. It means an operation that yields the same type of object (a triangle in this case) and brings you back to the original if applied again. So no, what you describe is not "THE dual", but just "SOME dual".
@Kram1032
@Kram1032 7 месяцев назад
​@@pauselab5569 there are many many kinds of dual in loads of situation. A duality is typically some pair of objects that you can swap between by exchanging some property. And I think this triangle situation can work with that. Duals are typically great because, by proving something about one object, you automatically get an equivalent proof for the other, and sometimes it's very easy to get a proof for one but you care about the other.
@TheOneMaddin
@TheOneMaddin 7 месяцев назад
Thought the same! I wonder what to do with it, what properties are preserved by this type of duality, whether it is the same as some other type of duality, and whether there are analogues of this in higher dimensions!
@bentationfunkiloglio
@bentationfunkiloglio 7 месяцев назад
The dot proof is more emotionally satisfying. :)
@kilianvounckx9904
@kilianvounckx9904 7 месяцев назад
As a color blind person, I didn't like the dot proof as much. I got the idea, but it wasn't as visual for me
@bentationfunkiloglio
@bentationfunkiloglio 7 месяцев назад
@@kilianvounckx9904 Haha. I’m colorblind as well (red/green). I couldn’t tell which dots were which, mostly.
@m4mathematix381
@m4mathematix381 7 месяцев назад
Another gem from Mathologer. It's because of Mathematicians like you out there, Maths is still beautiful and elegant.
@jrbrown1989
@jrbrown1989 7 месяцев назад
Maths would still be elegant and beautiful without him (or anybody for that matter), but he certainly does an excellent job of helping a broader audience appreciate it!
@emilyrln
@emilyrln 7 месяцев назад
@@jrbrown1989my thought exactly! He's brilliant at communicating things in such a way that a broad audience can see their beauty 😊
@WK-5775
@WK-5775 7 месяцев назад
I did a bit of trigonometry to express the six angles with the coloured dots in terms of the angles of the given triangle. Here's what I figured out. (I'm sure this is known to the triangle experts.) With the usual notation, let's call A, B, C the points of the triangle, a, b, c the edges and alf, bet, gam the angles. The median through A divides alf into the angles alf_b and alf_c (to the side of the edges b and c respectively). Similarly, bet=bet_c+bet_a and gam=gam_a+gam_b. With this, one gets: cot alf_b = 2 cot alf + cot gam, cot alf_c = 2 cot alf + cot bet and two similar pairs of equations. (The proof uses the law of sines and the addition formula for cot.) Btw., it can be checked that cot(alf_b+alf_c)=cot(alf). Now the folded triangle has angles alf_F = bet_a + gam_a, bet_F = gam_b + alf_b, gam_F = alf_c + bet_c, and one obtains cot alf_F=(-cot alf + 2 cot bet + 2 cot gam)/3 and two similar expressions for cot bet_F and cot gam_F, i.e. a linear relation between the cotangents of the angles! So, if one forms a 3-vector from the cotangents of the angles, then the folding operation from the video is the multiplication of this vector with the 3×3-matrix M which has -1/3 on the diagonal and +2/3 in all other entries. This matrix satisfies M^2=1, reflecting the fact that folding twice reproduces the triangle up to size.
@deltalima6703
@deltalima6703 7 месяцев назад
α β γ δ ε ζ η θ ι κ λ μ ν ξ π ρ ς σ τ υ φ χ ψ ω ϐ ϑ ϒ ϕ ϖ Ϛ Ϟ Ϡ ϰ ϱ ϲ There is some greek letters for you. You can copy and paste them to tidy up the text if you want. :)
@anon_y_mousse
@anon_y_mousse 7 месяцев назад
I wouldn't say it was missed, but rather everyone who noticed it never bothered to write a paper on it. It's all part of the beautiful symmetry of mathematics in nature.
@deadbeats4894
@deadbeats4894 7 месяцев назад
My thoughts too. I'd be suprised if the pythagoreans, ancient Indians and who knows before didn't know of this.
@CookieTube
@CookieTube 7 месяцев назад
Exactly!
@rv706
@rv706 7 месяцев назад
Very nice theorem! This folding process gives some sort of "sides-medians duality": -The sides of the folded triangle are each 2/3 the length of the corresponding medians of the original triangle; -The _medians_ of the folded triangle are each 1/2 the length of the _sides_ of the original triangle. This proves the 1-time-folded triangle is in general not similar to the original one, but the 2-times-folded one is similar to the original one, with a lengths ratio of (2/3)*(1/2)=1/3.
@jacoblojewski8729
@jacoblojewski8729 7 месяцев назад
My first thought with seeing this was a way of defining a Dual of a triangle (up to scaling), following up with some theorems saying "A triangle has property X iff its dual has property Y". Time to explore.
@DavidBeddard
@DavidBeddard 7 месяцев назад
Cool! I wonder how many mathematicians/geometrists have realised this in the past but either assumed it was already widely known or thought that it was trivial, so never bothered to publish it.
@Mathologer
@Mathologer 7 месяцев назад
Probably quite a few, but possibly/probably never visualised in the way I showed in the video :)
@1cor731
@1cor731 7 месяцев назад
Agreed - it follows easily from the centroid being 1/3 along each median, as demonstrated in this video.
@speedy3749
@speedy3749 7 месяцев назад
Well, if you put a lid on a pot with boiling water, it is pushed up and clacks sometimes. Probably people noticed that quite some thousand years ago. But not seeing it as trivial and going from there to a steam engine took quite a while. The next step towards many inventions was hidden in plain sight and regarded as trivial, until someone took a really close look and pointed out that it's anything but. So I have the deepest respect for people who have an eye for those things and look behind seemingly trivial things.
@clownphabetstrongwoman7305
@clownphabetstrongwoman7305 7 месяцев назад
We were meditating over these principles in 1988, when I was in 7th grade and we demonstrated tons of problems around that. How was this discovered only 10 years ago?
@CookieTube
@CookieTube 7 месяцев назад
Exactly! I am almost 50 years old, and I can distinctly remember playing with these 'folds' in the EXACT same way as shown in the video when I was around 10 years old with my own arts and craft projects at home. In fact, I might still have it laying around somewhere in some boxes at the attic. I suspect when he says _'discovered'_ he actually means either *A)* officially described in some math paper, and/or *B)* a proof was found. Which are VERY different things than _'known/discovered'_ .
@joshuadorsam4619
@joshuadorsam4619 7 месяцев назад
@@CookieTube I'd be interested in seeing those folds!
@LeoStaley
@LeoStaley 7 месяцев назад
It was probably only published by someone 10 years ago. People playing around with triangles ABSOLUTELY have discovered this many times over history.
@thej3799
@thej3799 7 месяцев назад
​@@LeoStaleylet's raise a glass to all those awesome people throughout history that loved the beauty of form and function. May everyone that wants to share in curiosity and wonder.
@CheatOnlyDeath
@CheatOnlyDeath 7 месяцев назад
Some things are so simple that no one who stumbles upon it would have the nerve to publish it.
@kushaldey3003
@kushaldey3003 7 месяцев назад
Second proof is more simple and easy to spot, first proof is a little more complicated but elegant, in my opinion
@cmilkau
@cmilkau 7 месяцев назад
Isn't the double folded triangle exactly the tiling triangle? Both are similar and have 1/9 of the original area
@willemm9356
@willemm9356 7 месяцев назад
Yes it is. This is also a more intuitive way to see the three parts are of equal area: The tiled and then median-cut original consists of 18 triangles, all of which are exactly half of one of the tiles, so they have equal area. And since each of the parts has six half-tiles they are all of the same area. It seems like you should be able to show the rest like this as well, by colouring in the six different types of triangles. (Three median directions to cut a tile, each cutting a tile in half.)
@SwordQuake2
@SwordQuake2 7 месяцев назад
The 2:1 median split is taught in school... And quite early at that.
@Mathologer
@Mathologer 7 месяцев назад
Used to be taught in school. These days at least in Australia hardly any nice geometry is covered in school anymore :(
@SwordQuake2
@SwordQuake2 7 месяцев назад
@@Mathologer really? But that seems like a basic property, not something I'd classify as "nice".
@kamaljain5228
@kamaljain5228 7 месяцев назад
beautiful! thanks!! medians of median-triangle give back the scale-down sides -- i also re-discovered this in middle school, when i tried to compute the formula for median lengths using pythagoras and area formula, and noticed that it was a reversible formula, in the sense that you can apply the same formula to get back the sides, if the median lengths are known, with a scaling factor. now seeing the animation today looks very beautiful.
@user-yw9mw9hv8o
@user-yw9mw9hv8o 7 месяцев назад
Triangles come in pairs that you turn into each other by folding them inside out, lovely! And thinking about the vertex angles: assigning identical angles the same color. an Isosceles triangle (RR, GB, GB) turns into a different isosceles triangle (RG, RG, BB) but only an equilateral triangle actually turns back into itself? edit. Whoops, i got too ahead of myself and wrote this, right before you explained the isosceles
@maxsievers8251
@maxsievers8251 7 месяцев назад
And I thought train spotters were strange. Now I'm aware there are triangle spotters, too.
@BikeArea
@BikeArea 7 месяцев назад
​@qnbitsWhat about ch**trail spotters then? 😮
@davewilson13
@davewilson13 7 месяцев назад
One of the best math channels out there. Your glee is contagious!
@3moirai
@3moirai 7 месяцев назад
Thanks! Lovely reminder why I love elegant mathematics like this.
@ZbynekKonecny-e9h
@ZbynekKonecny-e9h 7 месяцев назад
Very nice geometric proofs. It might be also interesting to look at it a bit more algebraically. Let's say a',b',c' are the big parts (as in 2/3) of the respective medians. From Steiner theorem (or law of cosines) we have a'^2=-a^2/6+b^2/3+c^2/3 and similar equalities hold for b', c'. So if we represent the triangle by the vector (a^2,b^2,c^2), "folding" is just a matrix multiplication (a'^2,b'^2,c'^2)=M*(a^2,b^2,c^2), where M=[[-1/6,1/3,1/3],[1/3,-1/6,1/3],[1/3,1/3,-1/6]]. Since M^2=I/4 (where I is the identity matrix), folding twice means making the squares of sides 4x smaller, i.e. scaling the triangle down by a factor of 2.
@WK-5775
@WK-5775 7 месяцев назад
Nice! So the squares of the sides behave better than the sides themselves. That's sort of a dual version of what I wrote about (the cotangents of) the angles an hour ago.
@N7492
@N7492 7 месяцев назад
Beautiful theorems. Elegant presentation. Bravo!
@Tehom1
@Tehom1 7 месяцев назад
Both proofs have their merits, but I prefer the second one just a tiny bit. On the one hand, when I follow a proof I like to be sure that I haven't missed some tricky step that might undercut the whole proof and that was easier with the first proof by just following the angle dots, but on the other hand the second one is quite short which is a big advantage.
@christymccullough7306
@christymccullough7306 7 месяцев назад
Cool shirt as always doc!
@diddykong3100
@diddykong3100 7 месяцев назад
That was very very awesome, thank you ;^> Also, your (ten minutes in) guess at how some of us would prove the result was exactly spot on; once you told me the result, that's how I had worked out it was right.
@Mathologer
@Mathologer 7 месяцев назад
Glad you enjoyed it!
@Philosophocat
@Philosophocat 7 месяцев назад
Just one line is crossing my mind watching this "It's a kind of magic, MAJIK!!!" ✨
@subinmdr
@subinmdr 7 месяцев назад
11:02 "The proof is elementary." Aha! A true mathematician!
@shrirammaiya9867
@shrirammaiya9867 7 месяцев назад
This theorem was discovered 10 years ago: 😊 This theorem was discovered is 2014: 😲 Can't believe 2014 is 10 years ago
@Mathologer
@Mathologer 7 месяцев назад
Yes, scary. Time seems to fly faster and faster. Probably a reflection of the fact that we are getting old :)
@LeoStaley
@LeoStaley 7 месяцев назад
This is my favorite mathologer video in a while. Quite easy to digest, and beautiful.
@Mathologer
@Mathologer 7 месяцев назад
Glad you liked it!
@NAMITADALAL-pz9wj
@NAMITADALAL-pz9wj 7 месяцев назад
A motivational video for discovering mathematics.
@dg-ov4cf
@dg-ov4cf 7 месяцев назад
go awey
@neg2sode
@neg2sode 7 месяцев назад
Amazing quality kept for another Mathologer video. Thank you so much for spreading glorious mathematics ideas to mathe-maniacs like us, Mathologer!
@maxmn5821
@maxmn5821 7 месяцев назад
What a nice story from the 2D world. Thanks for finding time to share it with us.
@caspermadlener4191
@caspermadlener4191 7 месяцев назад
This seems like it would arise in a special case of an elementary proof of ceva's theorem, that seems like the most natural generalisation, although you do need to scale the triangles. But people are too concerned whether someone else made the same discovery as they did. This is definitely the case with open problems, but presenting mathematics in an accessible way is here just as important, if not more important.
@Mathologer
@Mathologer 7 месяцев назад
Absolutely :)
@francisvaughan7460
@francisvaughan7460 7 месяцев назад
Something I like underpinning the two proofs is the duality of representations of triangles implicit in them. Three sides, or three angles and area. That one proof exists demands that the other one should be there as well. Nice.
@Macrocompassion
@Macrocompassion 7 месяцев назад
Duality is a great way of explaining things that should be used to replace straight single logical proof in certain more complex subjects, such as economics and mechanics. (Axiom: Mankind seeks to satisfy his needs with the least effort:yet mankind''s ambition to meet these needs is unending (Henry George). Action and reaction are equal and opposite (Isaac Newton).
@christopherellis2663
@christopherellis2663 7 месяцев назад
For me, the Dots 😮
@willemvandebeek
@willemvandebeek 7 месяцев назад
@Vihart will love this episode :)
@ubermo1182
@ubermo1182 7 месяцев назад
So beautiful! This is why I LOVE Euclidean geometry and ratios more than numbers. My eyes are moist.....
@hankracette
@hankracette 7 месяцев назад
I've always been weak in Geometry, and I won't pretend to have a ready sense of the correctness of what you're presenting even with the help of your excellent graphics. But, even so, I can tell that you really do the graphics well, and I'm a bit envious of those for whom the graphic presentation is intuitive.
@thej3799
@thej3799 7 месяцев назад
i like the dot proof because i wouldn't have thought of it, and it's very beautiful.
@DoubleCircleBundle
@DoubleCircleBundle 7 месяцев назад
This is a beautiful example of SSS congruence / AA similarity
@Tejas-zx7ie
@Tejas-zx7ie 7 месяцев назад
This is why we should never stop playing with all the subjects.. there's a lot of beauty still hidden! Thank you for the video :)
@jasonleelawlight
@jasonleelawlight 7 месяцев назад
Interesting! Yesterday I just found a generalized version of Geometric Mean Theorem when I was trying to find an easier and more intuitive way to understand the trigonometric addition formula. I believe my finding is too trivial and probably discovered by many a long time ago but I still can’t help commenting because it’s such a coincidence. 😂
@antoniorose2461
@antoniorose2461 7 месяцев назад
Wow! Wonderful discovery! Thanks a lot for the video!!! I like the second proof more, due to its simplicity. But the first proof is also inspiring!
@rv706
@rv706 7 месяцев назад
The first theorem ["Triangles formed by the centroid and the vertices have area 1/3 of that of the whole triangle"] can also be proven easily, though slightly less elementarily, this way: 1) ratios of lengths and ratios of areas are affine invariants; 2) every triangle is affine to an equilateral triangle; 3) the thesis of the theorem is obviously true for equilateral triangles.
@SaturnCanuck
@SaturnCanuck 7 месяцев назад
I prefer the dots proof. If you do the right triangle again do you get the right Triangle? Yes I think you do. Love these videos on a nice Sunday afternoon. Love the shirt btw
@alexeyvorobyov9160
@alexeyvorobyov9160 7 месяцев назад
In fact we were taught this in our correspondence math school in the USSR in the 1970s.
@GabrieleCannata
@GabrieleCannata 7 месяцев назад
I cannot believe we missed this. Does this extend beyond triangles? And is there some nice group theory ramification?
@ricardoguzman5014
@ricardoguzman5014 7 месяцев назад
This is very cool. I do a lot of tessellations and this is related. I've thought for a long time that there are many unknown simple mathematical theorems and proofs yet to be discovered. Math is a science with infinite possibilities so it seems intuitive to think this.
@andrewharrison8436
@andrewharrison8436 7 месяцев назад
Hmm - needs a physical model. Add it to my backlog of woodwork things to make.
@quantumgaming9180
@quantumgaming9180 7 месяцев назад
You know that when Mathologer posts, it will be a good day
@vallietmc9553
@vallietmc9553 6 месяцев назад
Did you notice that there are exactly five squares inside of the equilateral triangle? The top X is inside of a square. There are three complete squares with the last two being the left corner and left central area of the bottom triangle added to it and the same with the right corner and right side of the central bottom triangle.
@aziz0x00
@aziz0x00 7 месяцев назад
Thank you very much!!! I wish you long life!❤
@jedrzejkoszewski4342
@jedrzejkoszewski4342 7 месяцев назад
Pretty sure that I could solve one of the Math exam questions if I used this method. It was so much hassle with counting of right triangles inside the triangle but if I were to turn it inside out it would turn into a one big right triangle.
@JordanMetroidManiac
@JordanMetroidManiac 6 месяцев назад
If right triangles don’t fold into right triangles, then what kinds of triangles do?
@glennjohnson4919
@glennjohnson4919 7 месяцев назад
Kudos to the discoverer of this. A very organized mind.
@Mathologer
@Mathologer 7 месяцев назад
Check out some of his other inventions by following the links in the description :)
@georiashang1120
@georiashang1120 6 месяцев назад
I know that point should be the center of gravity for the triangle.
@yablaker
@yablaker 7 месяцев назад
I want that t-shirt in the shop!!
@Mathologer
@Mathologer 7 месяцев назад
Not my design, but check out the link in the description of this video :)
@cloenobody
@cloenobody 7 месяцев назад
this is amazing! i wonder if there are any interesting properties about the triangles you get when folding right triangles
@edwardmacnab354
@edwardmacnab354 7 месяцев назад
the thing is some of the famous math texts from antiquity have been lost , you can find only references to them
@MusicByNumbersUK
@MusicByNumbersUK 7 месяцев назад
Ohh... What's the ratio of the scaled down triangle compared to the original? :)
@WK-5775
@WK-5775 7 месяцев назад
As to the (once) folded triangle, there is no such ratio in general, since it is not congruent to the original one. As to to the folded folded one, the video explains tha the ratio is 1:3 for the lengths and 1:9 for the area.
@professorcalculus7885
@professorcalculus7885 7 месяцев назад
Extremely nice video, like always. Just few things, we never "prove" every triangle could be tessellated or that the small medians of every small triangle actually form a line on being combined, off course its obvious visually, moreover its is the median that is split in 2:1 ratio not the altitude so you can't directly infer the small triangle's height being 1/3rd of the original. The main point is bit of lack of rigor. Personally I watch your awesome videos to get an intuition but you should still at least mention the places where you lack rigor. Keep up the Excellent Work!!!!
@landsgevaer
@landsgevaer 7 месяцев назад
Left as an exercise for the -reader- viewer...
@stephenresler
@stephenresler 6 месяцев назад
I am impressed. BTW: Straight for the kill.
@jdmarino
@jdmarino 7 месяцев назад
I like the mini-mathologers. They hurt my brain less.
@DeclanMBrennan
@DeclanMBrennan 7 месяцев назад
Both proofs are very beautiful each in their own way and using color and animation is so much more elegant and easy to understand than filling the screen with Greek letters. I wonder does the original theorem generalize to 3 dimensions (and greater) where the "folding" takes place with three pyramids instead of two triangles? And the lines dropped from each apex would cut each other in the ratio 1 to 3.
@DerMarkus1982
@DerMarkus1982 7 месяцев назад
Ah, the infamous "Moebius C. Escher" Monopoly Edition! Love it!
@Mathologer
@Mathologer 7 месяцев назад
Yes, that one :)
@jong4321
@jong4321 7 месяцев назад
Seems to me to be a way to trisect a line - divide any line into three parts - by using the 2 to 1 values of the mediangs with a triangle drawn around the line. Wasn't that an old "unsolvable with a compass & straight edge" problem? Also, 2 proofs are better than 1, so whichever is easiest to understand...
@deltalima6703
@deltalima6703 7 месяцев назад
😳
@crigsbe
@crigsbe 7 месяцев назад
At 0:53 you made a false statement. The 6 little triangles are equal in size !!! All what you presented here did we all discover in the planimetry classes in the secondary school at Büren an der Aare in 1958 ! It was just a fun class of mathematics. No use at all but a lot of satisfaction.
@Mathologer
@Mathologer 7 месяцев назад
Correct, they all have the same area :)
@vanhetgoor
@vanhetgoor 7 месяцев назад
Beautiful, just one word! It must have been such a joy to discover this for the first time.
@dg-ov4cf
@dg-ov4cf 7 месяцев назад
u lied
@peterflom6878
@peterflom6878 7 месяцев назад
Have you ever looked at this curiosity? 1 +2 = 3 4 + 5 + 6 = 7 + 8 9 + 10 + 11 + 12 = 13 + 14 + 15 And so on?
@Mathologer
@Mathologer 7 месяцев назад
Yes, I've got a video about this ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-XR2u7izwZ04.html
@peterflom6878
@peterflom6878 7 месяцев назад
@@Mathologer cool! What a lovely pattern!
@GilCosta1965
@GilCosta1965 7 месяцев назад
do you mean "damn! what a disappointment!" :-)
@Muki1001101
@Muki1001101 7 месяцев назад
Another beautiful video. These geometric proofs are really something for the soul. Thank you.
@ikepigott
@ikepigott 7 месяцев назад
The first one with the dots - the congruence of the colors making ringlets, almost evoked a dna strand.
@JurijFajnberg
@JurijFajnberg 7 месяцев назад
Faszinierend, wie immer, danke! 👏 Die beiden Varianten sind schön, jede auf ihre eigene Weise. Im allgemeinen, ich finde es nur gut, wenn es mehrere unterschiedliche Lösungen gibt.
@Berend-ov8of
@Berend-ov8of 7 месяцев назад
Great video, interesting, entertaining and well made. Your mathematical enthousiasm is contageous. But you don't really believe this was missed the whole world over for 5000 years, do you? Not that I mind. As long as it's nice effective click bait it doesn't bother anyone. 'Love your shirt by the way.
@columbus8myhw
@columbus8myhw 7 месяцев назад
There's a third proof: tessellate the plane by the original triangle and draw all medians. Then a tessellation of the plane made of the "folded" triangle can be made by erasing some lines.
@Mathologer
@Mathologer 7 месяцев назад
:)
@jrbrown1989
@jrbrown1989 7 месяцев назад
Great vid! Are equilateral triangles the only ones that fold into scaled (and/or reflected) copies of themselves? I would guess so, but am struggling to prove it...
@زكريا_حسناوي
@زكريا_حسناوي 7 месяцев назад
لقد استخدمت مبرهنة lee sallows في إثبات صيغة مساحة المثلث بدلالة أطوال متوسطاته
@Macieks300
@Macieks300 7 месяцев назад
FYI The relevant subpage linked in the description links to the wrong subpage.
@ffggddss
@ffggddss 7 месяцев назад
Really neat! Another little geometry gem discovered in "modern" times, that seems as though it should have been discovered in Euclid's time, is this. In any triangle, draw all 3 pairs of angle trisectors, extending each until it intersects another from a neighboring angle. The 3 points of intersection are always the vertices of an equilateral triangle! The surmise is that it didn't appear in ancient times because angle trisection isn't possible with the classical straightedge-and-compass technique, so no one back then even considered it. This fact was mentioned in one of the early _Mathematical Games_ columns by Martin Gardner in Scientific American. Fred
@Mathologer
@Mathologer 7 месяцев назад
I actually did two videos on Morley's miracle early on :)
@ffggddss
@ffggddss 7 месяцев назад
@@Mathologer And I probably saw one or both of them, way back, and forgot :-(
@زكريا_حسناوي
@زكريا_حسناوي 7 месяцев назад
لقد رأيت مقالة lee sallows سابقاً ومن خلاله استلهمت بعض الأشياء عن الطي والقص التي لا أعرف إذا كانت معروفة مسبقاً أم لا، على سبيل المثال يمكن قص الرباعي الدائري من مركز الدائرة المارة برؤوسه إلى منتصفات أضلاعه للحصول على أربع رباعيات دائرية يمكن طيها بطريقة مختلفة للحصول على رباعي دائري جديد مختلف عن الأول ولكن كلاهما يمتلكان دوائر متطابقة، أيضاً يوجد طي وقص مشابه من حيث المبدأ من أجل الرباعي الذي أضلاعه تمس دائرة؛ هذا يجعل الرباعي الثنائي المركز مثير للاهتمام بشكل خاص
@RaRa-eu9mw
@RaRa-eu9mw 7 месяцев назад
Numberphile just won the -1/12 debate.
@Mathologer
@Mathologer 7 месяцев назад
Numberphile (and Numberphile groupies) say that Numberphile wins the -1/12 debate. I'd still maintain that maths wins :)
@PickledHam
@PickledHam 7 месяцев назад
Not sure, but I think you just described mathematically a "cootie catcher".
@shyrealist
@shyrealist 7 месяцев назад
Regardless of which proof people prefer, your explanation is, as usual, on point.
@drumsticksusa
@drumsticksusa 7 месяцев назад
Excellent graphics presentation.
@chriscrystalschell8582
@chriscrystalschell8582 7 месяцев назад
WOW .. Power of the folding Triforce .... ähm Triangle 🙂
@FedorLyudogovskiy
@FedorLyudogovskiy 7 месяцев назад
It's amazing! Thank you so much!
@fcvgarcia
@fcvgarcia 7 месяцев назад
I loved the dotted angles proof!
@inyobill
@inyobill 7 месяцев назад
Makes me wonder what other simple discoveries are waiting out there.
@gonshi9
@gonshi9 7 месяцев назад
Nice video before i get a nice lunch
@DrMikero
@DrMikero 7 месяцев назад
Does anything interesting happen if you take pairs of small triangles that share a *vertex* of the big triangle, instead of pairs of small triangles that share an *edge* of the big triangle?
@rychei5393
@rychei5393 7 месяцев назад
Wow, this is beautiful!
@idolgin776
@idolgin776 7 месяцев назад
Triangles are awesome!
@jitenderkumaryadav6513
@jitenderkumaryadav6513 7 месяцев назад
This just reminds me of the duality between lengths of medians (p, q, r) and length of sides (a, b, c): p*p = 1/4 (- a*a + 2 b*b + 2 c*c) On solving the three equation gives the proportional inverses for sides and medians: (9/16) a*a = 1/4 (- p*p + 2 q*q + 2 r*r) This would mean medians of triangle formed by medians of triangle would be 3/4 of the corresponding sides. Which is also how the last triangle turns to be 1/4 of the original triangle. Amazing!
@HonestOpinionHx23
@HonestOpinionHx23 6 месяцев назад
well well well you have reached 39:56:23 hours of content.. Just 37 seconds to make it 40 hours of content - typical work week content. Keep up the good work. 94M QUALITY views and continuing. BTW - I was wondering if my kid has to start learning advance mathematics where should I start. He is grade 1 and knows fractions additions subtraction now. As an engineering scholar I try to show him all simple math in visual way. I guess he can start with visual infinite series --> and How did Ramanujan solve the STRAND puzzle?
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