Single Slit Diffraction - Physics Problems

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This physics video tutorial provides a basic introduction into single slit diffraction. It explains how to calculate the width of the central bright fringe and the angular width in degrees given the separation distance of the single slit, the wavelength of light used, and the distance between the slit and the screen.
Ray Diagrams:
• Ray Diagrams
The Huygens Principle:
• Huygens Principle - Ph...
Young's Double Slit Experiment:
• Young's Double Slit Ex...
Single Slit Diffraction:
• Single Slit Diffractio...
Diffraction Grating Problems:
• Diffraction Grating Pr...
Polarization of Light Problems:
• Polarization of light ...
____________________________
Brewster's Angle:
• Brewster's Angle, Pola...
Planck's Constant and Blackbody Radiation:
• Planck's Constant and ...
Photon Momentum and Effective Mass:
• Photon Momentum and Ef...
Wien's Law:
• Blackbody Radiation an...
Compton Effect & Wavelength:
• Compton Effect and Com...
Physics 2 Final Exam Review:
• Physics 2 Final Exam R...
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Опубликовано:

11 янв 2018

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Комментарии : 74

@TheOrganicChemistryTutor 6 месяцев назад

Final Exams and Video Playlists: www.video-tutor.net/

@DudeWhoSaysDeez 3 года назад

You have a video for every topic that I am ever stuck on. Thank you 🙏🏻

@anjani3652 3 года назад

You are saving my whole degree ✌

@sudukikellington3594 6 лет назад

Thank u. You are amazing!

@minimarsed 2 года назад

english isnt even my native language but this is what im resorting to because i have no clue what my teacher is saying, thank you for this man

@elishi6805 3 года назад

you should make a video on thin film diffraction !

@daliaalshawi9907 5 лет назад

Thank you you are amazing

@__ICT__1288 Год назад

U taught this topic better than my actual teacher, thanks

@SquatSimp 3 года назад

You are awesome thank you

@katlegokokoana3476 5 лет назад

God bless you bro... you just made prepared for the physics test.

@mojo6112 5 лет назад

So how'd you do?

@joeramirez9042 5 лет назад

Mark Wahlberg gonna help m get this A

@AghahaseebullahkhanSindhi 2 года назад

Please answer 🙏 Consider a slit of width a producing a diffraction pattern, if 'm' is either positive or negative integer than diffraction minima occur under the conditions 1- M-lamda = a sin 2- 2M lambda = a sin 3- m lambda = 2 a sin 4- (2m+1) lambda = 2 a sin

@ramaghalayini8282 3 года назад

Thanks ! This helped me a lot🤩

@mojo6112 5 лет назад

10:38 that's physics for ya.

@TwistedKrizZ33 Год назад

Thank you so much

@kuttygundalchannel5455 4 года назад

Thank you

@richardrivaldo6941 4 года назад

hello how about phasor and I-y diagram for 4 slits interference?

@pikachu5188 2 года назад

At 9:31 The angle (Theta1) should be in degrees and not meters.

@thai27 2 года назад

yes boy

@TheLover6731 6 лет назад

I thought since the angle is bigger than 10 degrees then we cannot use the formula y1= Ltan(theta) because it may be used for small angles. Therefore, wouldn’t we use the formula y=L(m+0.5)lambda/d to find y1? If so, then the distance of the central maximum would be equal to 1.43m.

@casbox2667 Год назад

I think n+0.5 is what I've learned in class as well

@aaryansrivastava7835 2 года назад

thank you :)

@luckyprosperity6408 3 года назад

thanks!

@randychong8770 3 года назад

Thanks

@amnaumar7803 2 года назад

for dark fringe, shouldn't m be a decimal value like 0.5, 1.5, 2.5 etc?

@vladimirsheydorov3776 Год назад

This what I am confused about, in some book examples I saw m being an integer for destructive interference and in some for constructive??? So annoying...

@vladimirsheydorov3776 Год назад

Never mind, for single slit destructive interference m is integer and for multi-slit constructive interference m is integer

@manuelsojan9093 6 лет назад

At 9:33 why is the angle in meters??

@kamfei4774 6 лет назад

You are right, why is that angle in meter? hahaha maybe it's some careless mistake up there...

@RaneMatthew 6 лет назад

You're correct, it should have been in degrees. The value itself though, is correct :)

@MegaTiffanym 3 года назад

Why didn't you convert the 1.6 cm to meters to be consistent with the rest of the units?

@xXishibashiX 6 лет назад

This video gives me but a "whiff" of hope

@piglink10 5 лет назад

0:43 For double slit, wont the bright fringes all have the same intensity? (Same amplitude). The one which you drew isnt it for single slit ?

@raajkumar8039 4 года назад

Yup

@nirelleksenasitchoa7652 4 дня назад

When you say to use the second formula if theta is really small, what range would you suggest for theta? (anything less the 5 degrees?)

@ethanhope9935 2 года назад

why does destructive interference happen on single slit?

@isaitalvarado5727 2 года назад

what does theta need to be smaller than in order to be small enough to use the (y)(d)=(L)(m)(lamda)?

@RelevantDad 8 месяцев назад

Because of how that equation is derived. It is created by assuming that sin(theta) equals tan(theta), which is a close approximation for very small angles.

@alainfabrice5094 Год назад

I almost left without liking the video 😅👍

@mashanatanzon557 Год назад

On question one, shouldn;t the answer be 0.952m? We know that theta = lambda/slit width. And that lambda is = opposite over adjacent, making (680x10^-9)/(2x10^-6)=(W/2)/1.4. Resulting in width = 0.952m. Thank you for clarifying this!

@estherguberman6710 Год назад

I got the same answer

@BlazinblaiserVods 3 месяца назад

Why do we do this is Radians and not Degrees when finding the angle?

@schenzur 5 лет назад

9:33 why aren't we multiplying theta by 2

@fauzansyauqi2815 4 года назад

why must?

@jackwilson4710 4 года назад

He didn't need to because he halfed the width to get y1

@blackart2539 3 года назад

Sir how to relate wavelength and intensity in single slit

@husnaadibah5924 3 года назад

I guess it's something related to interference?

@thai27 2 года назад

In example 2, why m is 1 sir

@lilianawong4819 5 лет назад

can we assume that sin(theta) is = to y/L? For the first problem I paused the video and solved for y first and got a completely different answer. Isolating y I got: y= (m*lambda*L)/d = 476m ? Or can I only assume that with double slits? please anyone respond T.T

@boofmonkey5455 3 года назад

maybe

@olympichigh9014 2 года назад

resolution questions?

@Benjicmm 4 месяца назад

10:15 theta = 0.122 meters? shouldn't it be in degrees?

@nemuirostorageroom Год назад

spent 4 hours watching my prof's lecture, and I feel like I have a brain fog. Literally 1 minute into the video (the part where he says the amplitude of the bright fringe decreases progressively), I went "OHHHHHHHH".

@samb.7395 8 месяцев назад

@9:35 it should be degrees not meters

@derekliu4917 4 года назад

9:40 your theta should be in degrees

@oscarobioha595 4 года назад

ahh thank u!. I was scrolling to look for someone who caught it

@matthewkoob7600 Год назад

what a god

@rushvi1611 5 лет назад

i thought as it's a minumun it would be sinø = ((mlamda)/2)/d

@oscarobioha595 4 года назад

single slit is different

@macavmoudbhawanxutra876 6 лет назад

Can you solve jee advance paper?

@lojfiojo4725 5 лет назад

Isn’t theta 22?

@souvikdeyiipcmbi1496 3 года назад

man my teachers say that intensity remains constant for ydse but u are saying different plx help

@nabiha5772 2 года назад

intensity does not remain constant in a single slit diffraction, that's experimentally proven that the bright fringe in the centre is the brightest and the farther you go fringes/light get dimmer. You can have a rough observation on that in a dark room with partially closed door and bright light outside