Hello Friends Please watch the updated version here - ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-GI2GvpXidDg.html Watch complete video series of subject Strength of Materials only on Ekeeda Application. Download Ekeeda application to get 1000 Studycoins and use it to access free courses. Steps to follow:- 1. Download Ekeeda application from the link given below. 2. Sign up or Log in to your account. 3. You will get 1000 Studycoins worth Rs 1000. 4. Add the courses to your cart. 5. Select Study coins option to get free access. Android App : play.google.com/store/apps/details/?id=student.ekeeda.com.ekeeda_student iOS App : apps.apple.com/in/app/ekeeda/id1442131224
A Great THANKS to you sir with your explanation i had pass this SOM with 20marks. I am commenting on your video after seeing my results immediately. Saw multi times until you understand practice well, practice to do it fast because it takes much time. A Good thanks to you sir. GOD BLESS YOU SIR
The way You Taught Me In Macaulay Method Solving technique Was Very Good. Day After Tomorrow is my exam And I did not prepare this topic numericals. But Now After watching This Video I understood How to do this Numerical Thank you Sir.
We are happy that our content is helpful to you and it motivates us to keep focusing on the content. Download Ekeeda App where you will get courses with all the concepts from basics, practice problems and doubt asking facility from top educators. Download App - ekeeda.com/download.html
Hello AASIF Thank you for your valuable feedback. Please download Ekeeda Application to access more videos.We are providing one month free access to our app. Steps to follow :- 1. Download the application from the link given below. 2. Sign up or Log in to your account. 3. Add the courses to your cart. 4. Apply the Coupon code AICTE to get free access. Android App : play.google.com/store/apps/details/?id=student.ekeeda.com.ekeeda_student iOS App : apps.apple.com/in/app/ekeeda/id1442131224
Thankyou.Hope this video was about what you excatly wanted to learn.To make it more easier to conversate with us and learn about different topics you can go on this given link bit.ly/353lpP2 and download the Ekeeda -Learning App.We will surely help you.
Fantastic Video Sir....Wish to know more but it is quite unfortunate the Ekeeda app is not in my dear country, Ghana..I know it is going to be a great app when I start using it and which of course I will gladly recommend to my friends.....Counting on your cooperation.
"""Thankyou so much for valuing our video.We feel very glad to hear this blessing. I would like to request you to go through the following link bit.ly/353lpP2 and download the Ekeeda-Learning Application so that you can experience much better learning,you can also recommend this to you friends. Could I please request you to share your comments on the Google playstore/App store and Google reviews. In case you come up with any dificulties in this process you can contact me through Whatsapp-9372390148(Deepika)
We are happy that our content is helpful to you and it motivates us to keep focusing on the content. Download Ekeeda App where you will get courses with all the concepts from basics, practice problems and doubt asking facility from top educators. Download App - ekeeda.com/download.html
We are happy that our content is helpful to you and it motivates us to keep focusing on the content. Download Ekeeda App where you will get courses with all the concepts from basics, practice problems and doubt asking facility from top educators. Download App - ekeeda.com/download.html
Thankyou.Hope this video was about what you excatly wanted to learn.To make it more easier to conversate with us and learn about different topics you can go on this given link bit.ly/353lpP2 and download the Ekeeda -Learning App.We will surely help you.
The method of solving this question using the double integration method involves finding moment equations for 3 cross sections. Find the displacement and slope equations using double integration and integration of momentum equations. Using the principle of continuity and boundary conditions, find the constants, which in this case would be 6 constants. Substitute the respective constants in the slope and displacement equations of the middle section and then substitute 4.5 in the place of x to find the displacement and slope at the middle of the beam. I don't understand in the video how only the momentum equation of the third cross section is used to represent the momentum equation for the whole beam as done by you. Can you please clarify?
We are happy that our content is helpful to you and it motivates us to keep focusing on the content. Download Ekeeda App where you will get courses with all the concepts from basics, practice problems and doubt asking facility from top educators. Download App - ekeeda.com/download.html
We are happy that our content is helpful to you and it motivates us to keep focusing on the content. Download Ekeeda App where you will get courses with all the concepts from basics, practice problems and doubt asking facility from top educators. Download App - ekeeda.com/download.html
Thankyou for the appreciation and hope this video has helped you. For much easier learning I would suggest you to go through this link bit.ly/353lpP2 and download the Ekeeda-The Learning Application.You can also share this with your family and friends.
We are happy that our content is helpful to you and it motivates us to keep focusing on the content. Download Ekeeda App where you will get courses with all the concepts from basics, practice problems and doubt asking facility from top educators. Download App - ekeeda.com/download.html
Thanks, There is more to explore for you on our Ekeeda Application where you can get access to concepts from basic, practice problems to keep track of your progress, live doubt asking facility from top educators and much more. Download App - ekeeda.com/download.html
Dear kishan patel, We are glad to know your curiosity about new video content. To access all videos on all other topics visit our site www.ekeeda.com Also give us your worthy reviews as it will enable us to create more enriching videos in future. Click on following link and then on WRITE REVIEW to record your experience with Ekeeda www.google.com/search?q=Ekeeda&ludocid=0x3be7cef39a0bcb1f:0x695389d0b57989f4
Thanks u sir your way of teaching is very good But sir i have little confusion my teacher teaches that when we put x=0 then we have to consider only first section not the whole section but in this while you finding slope you put value of x=0 in all the sections Plz plz plz reply me sir my semester is coming near plz sir
As per macaulay's method, you have to take the expressions zero whenever the negative or zero occurs in any expression. but here, while calculating deflection you didn't take into this considerations which gives wrong answer. please clarify this. Thanks.
Thanks, There is more to explore for you on our Ekeeda Application where you can get access to concepts from basic, practice problems to keep track of your progress, live doubt asking facility from top educators and much more. Download App - ekeeda.com/download.html
We are happy that our content is helpful to you and it motivates us to keep focusing on the content. Download Ekeeda App where you will get courses with all the concepts from basics, practice problems and doubt asking facility from top educators. Download App - ekeeda.com/download.html
Dear chakshu motta, Thank you very much. We request you to share our work with your College friends and family because your Love gives us the power to produce more and more good content to spread the quality education. You can Subscribe by clicking on below link ru-vid.com #chakshu motta #Ekeeda #OnlineVideoLectures #EkeedaOnlineLectures #EkeedaVideoLectures #EkeedaVideoTutorial You can follow and Like us on following social media. Website - ekeeda.com Facebook - facebook.com/ekeeda Twitter - twitter.com/Ekeeda_Video LinkedIn- www.linkedin.com/company-beta/13222723/ Instgram - instagram.com/ekeeda_/ Pinterest - in.pinterest.com/ekeedavideo Below is the link to provide Google Reviews and ratings about Ekeeda www.google.com/search?q=Ekeeda&ludocid=0x3be7cef39a0bcb1f:0x695389d0b57989f4 You can reach us on care@ekeeda.com Happy Learning : )
i am a little bit confuse , is it allright to only cut one time ? since my lecterur taught me to cut into a few section .she said that cut only one section is for Macaulay only, cant u please explain to me ?
Thankyou very much for the comment.We are glad to hear that you are happy with explaination of the video. However for better learning I would recommend you to download the Ekeeda-The Learning Application by using this given link bit.ly/353lpP2. You can also share this with your family and friends.
Dear gopi kanchapogu, Thank you very much. We request you to share our work with your College friends and family because your Love gives us the power to produce more and more good content to spread the quality education. You can Subscribe by clicking on below link ru-vid.com #gopi kanchapogu #Ekeeda #OnlineVideoLectures #EkeedaOnlineLectures #EkeedaVideoLectures #EkeedaVideoTutorial You can follow and Like us on following social media. Website - ekeeda.com Facebook - facebook.com/ekeeda Twitter - twitter.com/Ekeeda_Video LinkedIn- www.linkedin.com/company-beta/13222723/ Instgram - instagram.com/ekeeda_/ Pinterest - in.pinterest.com/ekeedavideo Below is the link to provide Google Reviews and ratings about Ekeeda www.google.com/search?q=Ekeeda&ludocid=0x3be7cef39a0bcb1f:0x695389d0b57989f4 You can reach us on care@ekeeda.com Happy Learning : )
Thanks, There is more to explore for you on our Ekeeda Application where you can get access to concepts from basic, practice problems to keep track of your progress, live doubt asking facility from top educators and much more. Download App - ekeeda.com/download.html
Kieran Butroid 26x is the total weight due to UDL upto distance x.. Also centriod of UDL is at half of the length which means total load due to UDL acts at x/2 Thus Moment due to UDL = (Total load due to UDL) x (Distance of centroidal point of UDL from the point about which moment is to be found) = (26x . x/2) = 26x² /2
Sir udl Ko point load mei convert krne k liye , purey span ka square krke usko divided by 2 krna hota hai , aur usko multiplied by self weight. Fir yaha self weight ko sidha multiplied kyu Kia span length se?
Its our motto to make your studies easy! Download Ekeeda Application and use coupon code 'FIRSTTIME' and you will be able to watch any one subject free for one month Android:- play.google.com/store/apps/details?id=student.ekeeda.com.ekeeda_student&hl=en iOS:- itunes.apple.com/tt/app/ekeeda/id1442131224
Dear Kantesh Bondla, Thank you very much. We request you to share our work with your College friends and family because your Love gives us the power to produce more and more good content to spread the quality education. You can Subscribe by clicking on below link ru-vid.com #Kantesh Bondla #Ekeeda #OnlineVideoLectures #EkeedaOnlineLectures #EkeedaVideoLectures #EkeedaVideoTutorial You can follow and Like us on following social media. Website - ekeeda.com Facebook - facebook.com/ekeeda Twitter - twitter.com/Ekeeda_Video LinkedIn- www.linkedin.com/company-beta/13222723/ Instgram - instagram.com/ekeeda_/ Pinterest - in.pinterest.com/ekeedavideo Below is the link to provide Google Reviews and ratings about Ekeeda www.google.com/search?q=Ekeeda&ludocid=0x3be7cef39a0bcb1f:0x695389d0b57989f4 You can reach us on care@ekeeda.com Happy Learning : )
Dear Phillip Zikhali, Thank you very much. We request you to share our work with your College friends and family because your Love gives us the power to produce more and more good content to spread the quality education. You can Subscribe by clicking on below link ru-vid.com #Phillip Zikhali #Ekeeda #OnlineVideoLectures #EkeedaOnlineLectures #EkeedaVideoLectures #EkeedaVideoTutorial You can follow and Like us on following social media. Website - ekeeda.com Facebook - facebook.com/ekeeda Twitter - twitter.com/Ekeeda_Video LinkedIn- www.linkedin.com/company-beta/13222723/ Instgram - instagram.com/ekeeda_/ Pinterest - in.pinterest.com/ekeedavideo Below is the link to provide Google Reviews and ratings about Ekeeda www.google.com/search?q=Ekeeda&ludocid=0x3be7cef39a0bcb1f:0x695389d0b57989f4 You can reach us on care@ekeeda.com Happy Learning : )
Dear Karan Banga, Thank you very much. We request you to share our work with your College friends and family because your Love gives us the power to produce more and more good content to spread the quality education. You can Subscribe by clicking on below link ru-vid.com #Karan Banga #Ekeeda #OnlineVideoLectures #EkeedaOnlineLectures #EkeedaVideoLectures #EkeedaVideoTutorial You can follow and Like us on following social media. Website - ekeeda.com Facebook - facebook.com/ekeeda Twitter - twitter.com/Ekeeda_Video LinkedIn- www.linkedin.com/company-beta/13222723/ Instgram - instagram.com/ekeeda_/ Pinterest - in.pinterest.com/ekeedavideo Below is the link to provide Google Reviews and ratings about Ekeeda www.google.com/search?q=Ekeeda&ludocid=0x3be7cef39a0bcb1f:0x695389d0b57989f4 You can reach us on care@ekeeda.com Happy Learning : )
We are always happy to help you! Use Coupon Code "NEWUSER" and access any one Subject free for 3 days! Download Ekeeda Application and take advantage of this offer. Android:- play.google.com/store/apps/details?id=student.ekeeda.com.ekeeda_student&hl=en iOS:- itunes.apple.com/tt/app/ekeeda/id1442131224
Dear Its Fake, We are thankful to you for watching our videos. We are happy to know your interest in new video content. To access all videos on all other topics visit our site www.ekeeda.com Also, give us your worthy reviews as it will enable us to create more enriching videos in future. Click on following link and then on WRITE REVIEW to record your experience with Ekeeda www.google.com/search?q=Ekeeda&ludocid=0x3be7cef39a0bcb1f:0x695389d0b57989f4
Nadine Hossam Because in simply supported beam slope and deflection is zero at the ends . And also we are neglecting the parts that is (-ve) so if u apply the Conditions for all the equation again u will get the same value.
You are always welcome! We are giving any one subject free for one month, If you want to access the free subject just download the Ekeeda app and use coupon code ''FIRSTTIME" (This offer is valid through app only) Download Ekeeda Application and take advantage of this offer. Android:- play.google.com/store/apps/details?id=student.ekeeda.com.ekeeda_student&hl=en iOS:- itunes.apple.com/tt/app/ekeeda/id1442131224
sir when we calculate slope at zero according to Macaulay's brackets we not consider negitive sign.but here ( x-2)² negitive distance because we consider (x-2) whole plzz explain ..sir
Dear Reshmith Ramesh , Thanks for your feedback. Kindly appreciate our work and please give us some feedback about channel. Please review your comments on below links 1) www.google.com/search?q=Ekeeda&ludocid=0x3be7cef39a0bcb1f:0x695389d0b57989f4 2) facebook.com/pg/Ekeeda/reviews/ And for more information regarding to subject please visit ekeeda.com/ Else you can contact on 9821842103
sir in this i have confusion that while finding slope i.e max slope at x=0 i.e at point A...u have taken the whole slope=q for finding slope at point A.......but in RK Rajput book they are taking the section up to the distance........i.e if same question i would solve according to d book it whould be......at point A x=0......they take d slope =q till d section A -C i.e (322÷2)x^2 - 2160.86 and that gives d complete differt answer
sir plzz do comment and another question from my side is......if in d same question if they asked to find d max . deflection i.e( at what section and at what distance from A)how do we solve
Dear Kalal Rishabh, We are glad to know your curiosity about new video content. To access all videos on all other topics visit our site www.ekeeda.com Also give us your worthy reviews as it will enable us to create more enriching videos in future. Click on following link and then on WRITE REVIEW to record your experience with Ekeeda www.google.com/search?q=Ekeeda&ludocid=0x3be7cef39a0bcb1f:0x695389d0b57989f4
Hlo Sir In this question you have taken boundary condition as the initial point x=0 and x=9.So i want to ask, it is neceassary to take the initial and final values of x.Or any mid point can be taken??.Plz ans. Sir
We are more than happy to solve your queries.However for this you will have to download the Ekeeda-Learning Application by going through this link bit.ly/353lpP2 ,because we don't answer any technical queries on youtube for this we have a dedicated team.
What will be the effect of C1&C2 if we will not write the moment eq. in the same manner. As C1 & C2 can be written any where in that case the same value of C1 & C2 is not same as u have written
Ok i will definitely help you with the problem.However for this you will have to download the Ekeeda-Learning Application by going through this link bit.ly/353lpP2 because we don't answer any technical queries on youtube for this we have a dedicated team. You can also share this with your family and friends.
Sir while cutting section we ignored the moment caused by reaction at support B. Can you please tell me the reason why can't we consider that moment for this question? Because for deflection we have to consider all moments caused by all foces and reactions
Dear varma penmetsa, Thank you very much. We request you to share our work with your College friends and family because your Love gives us the power to produce more and more good content to spread the quality education. You can Subscribe by clicking on below link ru-vid.com #varma penmetsa #Ekeeda #OnlineVideoLectures #EkeedaOnlineLectures #EkeedaVideoLectures #EkeedaVideoTutorial You can follow and Like us on following social media. Website - ekeeda.com Facebook - facebook.com/ekeeda Twitter - twitter.com/Ekeeda_Video LinkedIn- www.linkedin.com/company-beta/13222723/ Instgram - instagram.com/ekeeda_/ Pinterest - in.pinterest.com/ekeedavideo Below is the link to provide Google Reviews and ratings about Ekeeda www.google.com/search?q=Ekeeda&ludocid=0x3be7cef39a0bcb1f:0x695389d0b57989f4 You can reach us on care@ekeeda.com Happy Learning : )
Thank you for you Appreciation! We are giving any one subject free for one month, If you want to access the free subject just download the Ekeeda app and use coupon code ''FIRSTTIME" (This offer is valid through app only) Download Ekeeda Application and take advantage of this offer. Android:- play.google.com/store/apps/details?id=student.ekeeda.com.ekeeda_student&hl=en iOS:- itunes.apple.com/tt/app/ekeeda/id1442131224
