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SLOPE AND DEFLECTION IN SIMPLY SUPPORTED BEAM WITH POINT LOAD BY CONJUGATE BEAM METHOD SOLVED 

CivilSAC
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‪@CivilSAC‬
In this video, we will learn how to use the conjugate beam method to find the slope and deflection in a simply supported beam.
We will find the slopes at supports and deflection under the point loads.
The solution is done in a very easy manner step-by-step.
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Link to other videos -
SLOPE AND DEFLECTION IN A CANTILEVER BEAM BY CONJUGATE BEAM METHOD | POINT LOAD | VARYING SECTION
• SLOPE AND DEFLECTION I...
SLOPE, LOCATION & VALUE OF MAXIMUM DEFLECTION IN SIMPLY SUPPORTED BEAM BY DOUBLE INTEGRATION METHOD
• SLOPE, LOCATION & VALU...

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6 сен 2024

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Комментарии : 13   
@CivilSAC
@CivilSAC 2 года назад
SUBSCRIBE TO OUR CHANNEL FOR MORE USEFUL TUTORIALS!
@abhishekbilwal483
@abhishekbilwal483 Год назад
Sir no words for your explanation, mind-blowing
@CivilSAC
@CivilSAC Год назад
Thanks a lot.
@foysalahmed4466
@foysalahmed4466 4 месяца назад
Thankss
@CivilSAC
@CivilSAC 4 месяца назад
You're welcome!
@techrunner9640
@techrunner9640 Год назад
Easy explanation ty sir
@CivilSAC
@CivilSAC Год назад
Keep watching !
@rohitgawde4217
@rohitgawde4217 Год назад
sir in last triangle we haven't multiplied by 2 the centroid location will be 2/3 *2. Please clarify sir
@chongotripple36
@chongotripple36 Год назад
No actually in last triangle cg is at 1/3 from a which is 1/3×base of last triangle which is 2 ,so cg= 1/3×2 then adding distance from A 6+1/3×2
@knightedits822
@knightedits822 10 месяцев назад
I have questions how to send it plz tell
@iqraabidiqraabid9629
@iqraabidiqraabid9629 2 года назад
190 kese Aya?
@CivilSAC
@CivilSAC 2 года назад
Just add the three values and divide the sum by 8.
@pepitotaloloto8685
@pepitotaloloto8685 3 месяца назад
😂😂😂😂😂😂
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