Much appreciated Sir 😊 MOSFET drain feedback bias One minute A: Id=k(vd-vt)^2 15-vd/15=0.25(vd-1.5)^2 Too lazy to solve the value of ax2+bx+c=0 vd gm=2k(vgs-vt)^2=2k*(id/k)^1/2=2*(k*id)^1/2 (Id/k)^1/2=vgs-vt B: vo=-u*vi*(rl'/ro+rl') vo/vi=41.2*(3.75/(68.75+3.75))=154.5/71.5=-21.6v/v C: Rin=rg/(1-A)=10/22.6=3.164M ohm Ro=ro//rd//RL//(rg/(1-1/av))=~
10MEG resistor is a pull-up resistor. Since the gate has no path to ground for DC you can think of it as an open circuit, where the gate gets pulled up to Vd
Va is the Early voltage. Analyzing the ID and VDE characteristic graph, the point of intersection from all the relationship curves correspond to some Early trans-conductance which is ID/VA where VA is the value of VDE at the point of intersection.