All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us. Your positive comments motivates me and person like me get boosted by my students feedback. Thanks and welcome 🙏
Your Appreciations, care and share matters a lot to me. #EnginneringLove. All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us. Your positive comments motivates me and person like me get boosted by my students feedback. Thanks and welcome 🙏
Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
Your positive comments motivates me, my goal is to create largest community of engineers in entire globe, so please help me for that by sharing this lecture series(playlist) with your friends in social media (watsapp, telegram etc). Thanks and welcome 🙏
When you making Input impedance real why you did not multiplied with Zo here ????? Purposely??? Or you forgot to multiply???? ByTheWay Thank you to My favourite Virtual Teacher ❤❤ keep Going Sir....
Hope you are fine. What I understand of this, it's the following: First, you found the Z_L and in that point you stretch the right line. Now you found the wavelength toward generator and it's 0.162lambda Now, you are moving toward the generator, right? Until where? Until V_max. And where's V_max? Vmax it's in the horizontal real part, try try to locate yourself by seeing 0.25. So,Mathematically speaking you could calculate the location the V_max in this way: 0.25 lambda - 0.162 lambda = 0.088 lambda. Now, doing this for V_min: V_min it's opposite to V_max Then, it's possible to do this: 0.50lambda -0.162lambda= 0.338 lambda Hope you understand! :)
Hello, Sir. I'm really grateful you with your job. I just wanted to say Thank so much. Besides that, I have noticed a mistake in this. When you find the Input Impedance, you said that it's 2.8, but it's 2.6 since the chart smith over there goes from 2 in 2 by line. Hope you are fine, and I'll be waiting you answer.
@@EngineeringFunda Oh, well, I'm sorry then. I thought that the line that was before the 3 is 2.8, and the one that is before the 2.8 is 2.6, which is where the interception point is in the video.
Hello, Liran Cohen. Hope you are fine. What I understand of this, it's the following: First, you found the Z_L and in that point you stretch the right line. Now you found the wavelength toward generator and it's 0.162lambda Now, you are moving toward the generator, right? Until where? Until V_max. And where's V_max? Vmax it's in the horizontal real part, try try to locate yourself by seeing 0.25. So,Mathematically speaking you could calculate the location the V_max in this way: 0.25 lambda - 0.162 lambda = 0.088 lambda. Now, doing this for V_min: V_min it's opposite to V_max Then, it's possible to do this: 0.50lambda -0.162lambda= 0.338 lambda Hope you understand! :)
Towards the generator means clockwise rotation. See the question in which it is given that move by 0.1Lambda from the load. Here from the load means towards the generator.
Hello, Pseudo Hawk1. Hope you are fine. What I understand of this, it's the following: First, you found the Z_L and in that point you stretch the right line. Now you found the wavelength toward generator and it's 0.162lambda Now, you are moving toward the generator, right? Until where? Until V_max. And where's V_max? Vmax it's in the horizontal real part, try try to locate yourself by seeing 0.25. So,Mathematically speaking you could calculate the location the V_max in this way: 0.25 lambda - 0.162 lambda = 0.088 lambda. Now, doing this for V_min: V_min it's opposite to V_max Then, it's possible to do this: 0.50lambda -0.162lambda= 0.338 lambda Hope you understand! :)
