Software Testing Tutorial #34 - Equivalence Partitioning in Testing

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In this Software Testing Tutorial, we will learn about equivalence partitioning in software testing. Equivalence partitioning (EP) is a very important black box test design technique which is very widely used in software testing.
In this tutorial we will learn about equivalence partitioning with examples and how you can use equivalence class partitioning effectively in software testing and also explain this question in any software testing interview.
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Опубликовано:

7 дек 2020

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Комментарии : 60

@ammygill9769 10 месяцев назад

I am practicing for ISTQB from syllabus but couldn’t understand properly and through your video i got it,wow very nicely explained. Thank you sir.

@Ane-genius 25 дней назад

I watched many videos to understand … but u don’t until I watch you’re video thank you so much you are the best 🙏🏻🙏🏻🙏🏻

@amalacherukuri8103 2 года назад

Wow.. what an explanation.. just one time for the clear picture.i have been watching your videos since two months. It's been really helpful. Every topic explanation.. u nailed it.. u r a really mentor..Thanks Manish.

@tolentinoaramrhamyrc.6244 2 года назад

Thank you Sir! I can easily understand the EQ!

@hadiquafazal5653 2 года назад

You make the content very easy . Good job

@oxanajarkova7351 7 месяцев назад

Amazing explanation! I am a fan of your channel! Thank you!

@SineQuaNon1 9 месяцев назад

Great video, as always.

@sanchitrahate5803 Год назад

Watch it in 2x

@amardombe308 Год назад

Thank you so much. It means a lot really.

@zahramahdavi9448 Год назад

Im so grateful, you explain sooooooo good

@softwaretestingmentor Год назад

Thank you. Keep watching for more videos and tutorials.

@hiimanengineer9668 Год назад

Thank you so much for explaining this

@softwaretestingmentor Год назад

You're very welcome! Keep watching for more videos and tutorials.

@Scarletteunjilee 5 месяцев назад

Great explanation, thanks!

@softwaretestingmentor 5 месяцев назад

Thank you very much. Keep watching and sharing.

@vishal3288 Год назад

Thank you sir ❤️

@elnino61 2 года назад

Thank you

@user-rw9xq3sf5d 5 месяцев назад

very well explained, thank you

@softwaretestingmentor 5 месяцев назад

Glad you liked it. Keep watching and sharing.

@anastheticss Год назад

loved it

@churafltet1215 3 года назад

Thank u sir it's interesting

@softwaretestingmentor 3 года назад

Always welcome. Keep watching!

@coolpix807 2 года назад

Excellent explanation.

@softwaretestingmentor 2 года назад

Thanks. Keep watching for more videos!

@mohanadadel6749 2 месяца назад

Thank you sir , very helpful❤

@softwaretestingmentor 2 месяца назад

You're welcome 😊 Keep watching and sharing.

@govindasharma8619 Год назад

Sir, regarding Equivalence partition 'example', wouldn't decision table technique more suitable for testing this example?

@P.D.V.Prabhashana 2 месяца назад

Thank you sir

@softwaretestingmentor 2 месяца назад

Welcome keep watching and sharing.

@shubhamprasad8352 Год назад

Beautifully explained !!!

@nigarsultana1739 9 месяцев назад

Awesome sir.

@softwaretestingmentor 9 месяцев назад

Thanks a ton! Keep watching and sharing.

@leonardoescudero8350 2 года назад

What if you add 0, would that be considered invalid even though the problem says you can add whole numbers? It passes the 1 - 100 but 0 is still a whole number but I’m guessing 0 would still be invalid because it passes the input from 1 - 100. But I’m not sure, what do you think?

@user-ly8jb7ex2q 8 месяцев назад

good.

@jennybeko1604 2 года назад

Thank you so much...your tutorials are so well explained and easy to understand. Your son is so cute. He will probably be 6yrs old now. Halo Frands ..Lol... Hello Friends.....Hello cutie.

@krishnak6100 Год назад

Thankyou Sir but,if there is code in discount does that means we have to have seperate test case?

@reginachife5353 Год назад

Thank you. Please can you please help me solve some questions?

@uchennaezeh5456 Год назад

Good

@vidyapnair6516 Год назад

Hi I have one doubt is it possible or is it a right way to divide the valid value 1-100 divided in to 1-50 and 51-100

@yuktasreddy8984 Год назад

what about 1.1? will that also be considered as a valid partition?

@atiyawarsi111 Год назад

Best one

@softwaretestingmentor 11 месяцев назад

Thank you so much. 😊 Keep watching for more videos and tutorials.

@tashikasingh3664 Год назад

Hi sir, You have explained the concept very well. thank you so much for this. Regarding this concept i have a question which i'm unable to understand it properly Q. Postal rates for "light letters" are 25p up to 10g, 35p upto 50g plus an extra 10p for each additional 25g up to 100g. Which test inputs (in grams) would be selcted using equivalence partitioning? A. 8, 42, 82, 102 B. 4, 15, 65, 92, 159 C. 10, 50, 75, 100 D. 5, 20, 40, 60, 80 how to find equivalence partitions in this?

@repackgamers5191 11 месяцев назад

option c would be appropriate

@jordanfernandes4384 Месяц назад

How to check for decimal value above 1 and below 100

@sachinbs984 2 года назад

🔥

@anamikatanwar1954 3 года назад

👏👏

@PRADEEPKASARE-bb2me Год назад

👌👌

@gauravrajpurohit882 Год назад

actually I have doubt that if in an question been ask that a person can drive when his or her age is atleast 18 or no more than 60 then what is the equivalence partition in this case .... should we take 18 as valid or invalid ?? please give answer

@leandrawoods8568 9 месяцев назад

atleast 18 would mean 18 is valid, I guess...

@atiyawarsi111 11 месяцев назад

Hi How could I contact you for taking tuition

@meetsaurabhtiwari 11 месяцев назад

What is the exact purpose of equivalence partition ?

@jeancarlo912 2 года назад

A fitness app measures the number of steps that are walked each day and provides feedback to encourage the user to keep fit. The feedback for different numbers of steps should be: Up to 1000 - Couch Potato! Above 1000, up to 2000 - Lazy Bones! Above 2000, up to 4000 - Getting There! Above 4000, up to 6000 - Not Bad! Above 6000 - Way to Go! Which of the following sets of test inputs would achieve the highest equivalence partition coverage? a) 0, 1000, 2000, 3000, 4000 b) 1000, 2001, 4000, 4001, 6000 c) 123, 2345, 3456, 4567, 5678 d) 666, 999, 2222, 5555, 6666 can somebody answer that question? I know the answer as is part of the ISTQB exam, however, I dont understand the actual way to get to the answer, thank you

@anghelutadragos1898 2 года назад

@Jean Carlo Feoli We will start first by creating the partitions: The first partition is from min to 1000 ( I added min because we don't know the exact value it can be 1 or 0) The second partition is from 1001 to 2000 The third partition is from 2001 to 4000 The forth partition is from 4001 to 6000 The fifth partition is from 6001 to Max ( I added max because we don't know the exact value where the application will stop counting the steps) Conclusion: We have identified 5 partitions After this let's look at the answer provied and wich partition do they cover: a) 0 (covers partition 1), 1000 (covers partiton 1), 2000 (covers partion 2), 3000 ( covers partion 3), 4000 (covers partition 3) - in total this set of input values covers 3 partitions b) 1000(covers partition 1), 2001(covers partion 3), 4000 (covers partion 3), 4001(covers partion 4) , 6000 (covers partion 4) - in total this set of input values covers 3 partitions c) 123(covers partion 1), 2345(covers partion 3), 3456(covers partion 3), 4567(covers partion 4), 5678 (covers partion 4) - in total this set of input values covers 3 partitions d) 666(covers partition 1), 999(covers partion 1), 2222(covers partion 3), 5555(covers partiton 4), 6666 (covers partion 5) - in total this set of input values covers 4 partitions The correct answer in this case is d because it covers the most partitions. I hope this helps you, if something is not clear, tell me and I will try to explain it to you.