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Solving An Incredibly Hard Problem From Australia 

MindYourDecisions
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This problem stumped me! But it has a pretty nice solution. Thanks to all patrons! Special thanks this month to Kyle, Michael Anvari, Richard Ohnemus, Shrihari Puranik.
Source
Emailed to me about 2 years ago, traced to the Australian Intermediate Olympiad given in 2013.
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3 июн 2019

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Комментарии : 2,5 тыс.   
@MindYourDecisions
@MindYourDecisions 5 лет назад
By the way, the official solution listed 3 methods--all fairly similar--and the video is based on method 2 which is where I learned of the rectangle idea. It's fun to see the range of attitudes, from those who found the answer without valid proofs (so I think would earn 0 points on an Olympiad) to those that want a more formal proof (this is from the official solution!). In a RU-vid video, like all math and science channels, we strike a balance to engage as many people as possible. For those serious about the math, I suggest to get Olympiad books with real competitions and official solutions. You'll see the standard for proofs is fairly high, and you'll learn many problem solving techniques along the way!
@ArchNemesis314
@ArchNemesis314 5 лет назад
Ah, yeah... I'll "limit" myself to geometry and algebra...
@AntizombiRUS
@AntizombiRUS 5 лет назад
If I was asked this question in 15 years I would say "Yes"
@adamchan4194
@adamchan4194 3 года назад
I thought of it as: b and c are used twice and multiplied together, let's make those as big as possible. Making a = d = 1 leaves 61 to satisfy the sum. And then split that to get 30 and 31
@PGCTalha
@PGCTalha 3 года назад
Who just divided 63 by 3
@firdavsnasriddinov5898
@firdavsnasriddinov5898 5 лет назад
No joke I actually solved this before watching it. I feel so proud.
@tieswestendorp9830
@tieswestendorp9830 3 года назад
"Remarkably" 30 and 31 give the same answer? The problem is highly symmetric: b and c can be exchanged and a and d can be exchanged by virtue of the picture you drew, and the equation in the original question. You're still using calculus in your answer too, despite noting it should not be used in this case.
@DrZaius3141
@DrZaius3141 5 лет назад
Easy to find, easy to argue, hard to proof. It's a classical Olympiad problem in that regard.
@sitasin6545
@sitasin6545 3 года назад
I would have had 0 issues solving this as a 15 year old, all it takes is look and see that b and c are used twice and the others are used once, so make them as big as possible. I wouldn't know how to verify it other than checking some other numbers, but I'd have no problem getting 991
@vadendev
@vadendev 5 лет назад
I'm 14 so I don't have to worry about it now
@juangarcia1046
@juangarcia1046 5 лет назад
Im still picking pieces of my brain from the floor :'v
@elyakimlev
@elyakimlev 3 года назад
It took me less than a minute to realize the values of B and C must be as big as possible, while being as close as possible (30 and 31 or 31 and 30).
@ShaharSigal515
@ShaharSigal515 4 года назад
I solved this problem with a different approach:
@khanhphaminh1175
@khanhphaminh1175 4 года назад
Mathematic students in high school should follow this channel. Wow. I mean, I'm 26 years old and still get excited with every questions and the way is solved.
@jhoelious8634
@jhoelious8634 3 года назад
I, as a 15 yo, would just sit and cry on my desk hahaha but thanks for the video, I definitely learned a lot ^^
@dominickmeisner8752
@dominickmeisner8752 5 лет назад
Imagine being the people that have to think up the math problems
@joris8032
@joris8032 5 лет назад
Finally got 1 through logic. since b and c are present 2 times in the equation they have to be the highest possible integer (30 and 31) while a and d need to be the lowest possible integer (1 and 1) which results in 991
@lemanuelneuro
@lemanuelneuro Год назад
This is the work of a brilliant mind. That was a splendid approach.
@vjekokolic9057
@vjekokolic9057 3 года назад
Presh: Let's limit our selves to geometry. No calculus. (Than starts to talk about rectangles)
@utkarsh0509sharma
@utkarsh0509sharma 5 лет назад
Took him two years to solve it.... Kid would be 17 now
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