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Solving SQL Interview Problem with MULTIPLE solutions | Practice SQL Queries 

techTFQ
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11 сен 2024

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Комментарии : 70   
@sanjeetsignh
@sanjeetsignh 6 месяцев назад
Amazing.. I had another approach. select parent_id , case when (sum(case when status = 'Active' then 1 else 0 end)) = 0 then 'Inactive' else 'Active' end as status from parent_child_status group by parent_id
@Mayank-jw9yy
@Mayank-jw9yy Месяц назад
Now I can watch your videos on loop all the time, thanks thoufiq, you can make anyone fall in love with SQL.
@F_A_R_man
@F_A_R_man 7 месяцев назад
Thanks for exercises 😍 And below is one of my solutions↓ select distinct parent_id, case when sum(case when status = 'Active' then 1 else 0 end) over(partition by parent_id) = 0 then 'InActive' else 'Active' end as status from parent_child_status;
@naveenkalyan4700
@naveenkalyan4700 7 месяцев назад
May I know why you used the aggregate function in a case statement and how it actually works in a case statement? I have been trying to understand this but I couldn't 😢. Hope you will be helpful 😊
@F_A_R_man
@F_A_R_man 7 месяцев назад
@@naveenkalyan4700 I`m happy to help) There are 2 case statements. First one I put in analytic function "SUM(1st case statement) OVER(partition by parent_id)" and then comes 2nd case statement which include that sum analytic function. If you need more detailed explanation then let me know )
@Mrlegacy1_
@Mrlegacy1_ 7 месяцев назад
Your solution is tricky but simple when you do understand it, I like it👏
@F_A_R_man
@F_A_R_man 7 месяцев назад
@@Mrlegacy1_ Glad that you like it ) In comments I saw "CTE" solution of what I did. You can see it below↓ with cte as( select parent_id, sum(case when status = 'Active' then 1 else 0 end) as act_unact_flag from parent_child_status group by parent_id) select parent_id, case when act_unact_flag > 0 then 'Active' else 'Inactive' end as status from cte; I felt curious about which of this 2 will be faster in performance. Did 4 cross joins and COST difference was 234, CTE was faster. FYI: To look for COST (for Oracle sql) you can highlight query and press F10 or highlight query→right click→Explain...→Explain plan
@Mrlegacy1_
@Mrlegacy1_ 7 месяцев назад
What more can I say...your videos are just self explanatory, I love this so much....I just finished solving the 22 SQL problems you posted earlier on the painters dataset, it just feels amazing. I'm always waiting for your videos to drop, I do learn a lot from them♥️♥️♥️
@suchitaachari6615
@suchitaachari6615 6 месяцев назад
Thanks a ton for your SQL videos 👏👏 . Your way of presenting the SQL contents is on another level. No bakwas, detailed explanation👏 I am here with another solution for the same. with c1 as (select distinct p_id,sum(case when status='Active' then 1 else 0 end) as flag from dup group by 1 ) select distinct p_id,case when flag=0 then 'InActive' else 'Active' end as status from c1
@geet_lol
@geet_lol 7 месяцев назад
Hi Toufiq, i m so glad to find ur channel. Ur way of explaining things is soooooo good. Wish I had found ur channel long before. Never stop doing what u r doing!
@swapnilpatil3329
@swapnilpatil3329 7 месяцев назад
Thank you for the amazing explanation with multiple solutions. Always loved to watch your videos.
@nambidasan6314
@nambidasan6314 7 месяцев назад
Thank you Tfq. I am really happy that you have made a video of my question which I have sent over an email to you.
@thaheers
@thaheers 7 месяцев назад
Really appreciate your preparation and efforts to make the videos straight to the point and easily understandable. Keep doing the great work Thoufiq.
@elvemoon
@elvemoon 7 месяцев назад
would use QUALIFY if your database support it
@pragatiaggarwal8103
@pragatiaggarwal8103 3 месяца назад
Your explanations are just wow 🤟
@shaonimitra1949
@shaonimitra1949 7 месяцев назад
You videos are a gem... Very informative and well explained.. Please make some videos on SQL Date format and SQL String Functions.
@avi8016
@avi8016 7 месяцев назад
Just wow!! Each solution was different from the other 💯 Thankyou sir 🙏
@gocrow23
@gocrow23 7 месяцев назад
Wonderfully explained, thank you! Please explore KQL also and start making similar tutorials if possible, it's very powerful too.
@082SRIRAMDR
@082SRIRAMDR 7 месяцев назад
Your videos are truly incredible, and they have proven to be exceptionally helpful in enhancing my understanding of SQL concepts. I appreciate the effort and clarity you bring to your content, making it easier for me to grasp complex ideas. Thank you for providing such valuable resources!✨✨
@sirishaPamisetty-k9o
@sirishaPamisetty-k9o 7 месяцев назад
Hi sir I saw your video learn how to write SQL queries it's very useful video for all MySQL developers thank you so much and as parllel which course is required for MySQL
@ParthaMukherjee-x8k
@ParthaMukherjee-x8k 7 месяцев назад
I have also Tried in following way - With Cte_parent_child_status (Parent_Id, Sts) as ( Select Parent_Id, LISTAGG(Status, ',') Within Group(Order By Parent_Id) Sts From parent_child_status Group By Parent_Id ) Select Parent_Id, Case when REGEXP_INSTR(REPLACE(STS,'InActive','No'), 'Active')>0 then 'Active' Else 'InActive' End Status from Cte_parent_child_status Order By Parent_Id;
@whooaaapppp
@whooaaapppp 6 месяцев назад
I really learned a lot from this video!
@kiransheikh8536
@kiransheikh8536 7 месяцев назад
Dear duty time 20:00 to 8:00 tak hai or check in out k table me 2 column hy empid or checktime or expected output Date-timein-timeout-late-early-dutyhour Is tarha chahiye Slove problem
@aimanansarmomin4542
@aimanansarmomin4542 7 месяцев назад
Please make a video on date function. And create a table with time column and show how to insert the time
@safyan_yaqoob
@safyan_yaqoob 7 месяцев назад
Thank you so much for the easy explanation, your videos are amazing.
@benlong1062
@benlong1062 Месяц назад
In solution 1, why did you need to use group by in active but not in inactive?
@jkumar8590
@jkumar8590 7 месяцев назад
Hello, what should be the front end tool for developing forms? How to develop reports? Are you covering them in your courses?
@jdisunil
@jdisunil 7 месяцев назад
you made my day, I learnt it.
@abhishekgarg9029
@abhishekgarg9029 7 месяцев назад
SOLUTION 7 : with cte as( select parent_id, sum(case when status = 'Active' then 1 else 0 end) as act_unact_flag from parent_child_status group by parent_id) select parent_id, case when act_unact_flag > 0 then 'Active' else 'Inactive' end as status from cte
@arthiques2577
@arthiques2577 7 месяцев назад
with cte as( select *,sum(case when status='Active' then 1 else 0 end )over(partition by parent_id)as flag from parent_child_status) select distinct parent_Id,case when flag>0 then 'Active' else ' inactive' end as status from cte;
@petermugo9204
@petermugo9204 7 месяцев назад
Same output thanks with cte as( select *, sum( case when status='Active' then 1 else 0 end )over(partition by parent_id)as flag from parent_child_status) select distinct parent_Id,case when flag =0 then 'InActive' else 'Active' end as status from cte Order by parent_id;
@user-ur8ph9lj6f
@user-ur8ph9lj6f 7 месяцев назад
Can you share the important SQL must do questions from platforms like leetcode, stratascratch, data lemur etc in one video to watch before every interview
@user-yp5tj2ce3s
@user-yp5tj2ce3s 7 месяцев назад
Really THANK YOU SOOOO... MUCH🙂🙂🙂
@fahimfaysalall
@fahimfaysalall 7 месяцев назад
Need more this type of video
@nandan7755
@nandan7755 7 месяцев назад
Thanks 👍 explanation is really amazing ❤
@sonysingh-vw6qu
@sonysingh-vw6qu 7 месяцев назад
Hello sir, Can you please provide the query for the below question to fetch the information: 1.Find all the databases we have in SF non prod account. 2.Find how many tables we have in each databases 3.find total record count in each tables in each databases 4.find last access date by anyone of every table in each databases for all of the above steps, consider only those table which is active or in use 5.find each table size in GB in every databases 6. how to find the storage cost in sf for any Please help me with this
@kevinwtao5321
@kevinwtao5321 7 месяцев назад
Amazing.... thanks!
@vikaskumar-qr5tj
@vikaskumar-qr5tj 7 месяцев назад
Amazing..
@kkrkk1113
@kkrkk1113 7 месяцев назад
Hello sir I have one doubt,in there are are 2nd solution has where rn=1,what is the meaning rn
@gourav.barkle
@gourav.barkle 7 месяцев назад
Please do this type of video. thansk
@abhishekgowda1776
@abhishekgowda1776 7 месяцев назад
Thank you 😊
@user-yt7ok5fy8i
@user-yt7ok5fy8i 7 месяцев назад
good!
@MarioTorres736
@MarioTorres736 7 месяцев назад
I want to work as data analyst before I start my masters in data science and machine learning. Problem is : I have graduated recently from biomedical Science
@btkshamsu561
@btkshamsu561 7 месяцев назад
sir, as a beginner i have a doubt...how do we connect postgre sql server to microsoft excel
@akifahmed9610
@akifahmed9610 7 месяцев назад
I want to practise SQL, can you suggest some sites where I can practise SQL (not for Data Science purpose)?
@rajareddy3848
@rajareddy3848 7 месяцев назад
when will start new sql batch ?
@Alexpudow
@Alexpudow 7 месяцев назад
select parent_id, case when sum(case status when 'Active' then 1 else 0 end) >=1 then 'Active' else 'Inactive' end status from parent_child_status group by parent_id
@sagarmagdum7407
@sagarmagdum7407 7 месяцев назад
SQL king I like it
@gcpchannelforbegineers7080
@gcpchannelforbegineers7080 7 месяцев назад
select parent_id,min(status) as status from table group by parent_id ;
@ekpenkovictor2638
@ekpenkovictor2638 7 месяцев назад
Please help me solve this..write a query to get the least accounts that had the least amount sold in the month of December 2015.. thanks
@vishalsonawane.8905
@vishalsonawane.8905 7 месяцев назад
Done
@gazart8557
@gazart8557 7 месяцев назад
How can you apply min or max to a string type column ? I am referring to status column
@Mrlegacy1_
@Mrlegacy1_ 7 месяцев назад
But you saw that it worked right?
@anudeepreddy5559
@anudeepreddy5559 7 месяцев назад
❤❤🔥 💯
@kishorl7190
@kishorl7190 7 месяцев назад
😅i have a doubt to your last solution min(status) . what if the table has 1 inactive and 2 active then the min(status) will be inactive .
@rupeshkumarrk5315
@rupeshkumarrk5315 7 месяцев назад
Min doesn’t work that way, when we do min(status) on a string it will give the lowest character string value. As active starts with A, it is the lowest string value. It will still return active in your case
@HARSHRAJ-wz2rp
@HARSHRAJ-wz2rp Месяц назад
with cte as( select parent_id, COUNT(CASE when status="Active" THEN 1 ELSE NULL END) as "active_count" FROM parent_child_status GROUP BY parent_id ) select parent_id, CASE when active_count>0 THEN "active" ELSE "inactive" END AS "status" FROM cte;
@subhranshuchaulia
@subhranshuchaulia 7 месяцев назад
Hi TFQ
@anchal7876
@anchal7876 7 месяцев назад
with cte as (select parent_id,max(case when status='Active' then status else null end) as Active, max(case when status='Inactive' then status else null end) as Inactive from parent_child_status group by parent_id) select parent_id,active from cte where Active is not null union all select parent_id,inactive from cte where Active is null order by parent_id
@monasanthosh9208
@monasanthosh9208 4 месяца назад
With CTE as (Select Parent_id,group_concat(Child_id), Count(Case when status="Active" then 1 end) as S_Count from Parent_child_Status group by Parent_id) Select Parent_id, Case When S_count>=1 then "Active" else "Inactive" end as Status from CTE;
@babag5324
@babag5324 7 месяцев назад
Python new batch start date plz
@user-we3cu9sy8i
@user-we3cu9sy8i 7 месяцев назад
select *from parent_child_status; with cte as ( select *, rank() over(partition by parent_id order by cnt desc)as rnk from( select parent_id,status,sum(marks)as cnt from( select *, (case when status = 'Active' then 1 else 0 end)as marks from parent_child_status)as x group by parent_id,status order by parent_id)) select parent_id,status from cte where rnk=1;
@sateeshkumar2698
@sateeshkumar2698 7 месяцев назад
Can anyone let me know in which editor code was running?
@Gauravop101
@Gauravop101 7 месяцев назад
His is using pgadmin with dark theme.
@sateeshkumar2698
@sateeshkumar2698 7 месяцев назад
@@Gauravop101 ok, thanks for replying
@arjundev4908
@arjundev4908 7 месяцев назад
WITH CTE AS(SELECT *, CASE WHEN PARENT_ID IN(SELECT PARENT_ID FROM PARENT_CHILD_STATUS WHERE STATUS = "ACTIVE") THEN "ACTIVE" ELSE "INACTIVE" END AS NEW_STATUS FROM PARENT_CHILD_STATUS) SELECT PARENT_ID, NEW_STATUS AS STATUS FROM CTE GROUP BY 1;
@abhinavkumar2662
@abhinavkumar2662 7 месяцев назад
We can use here foreign key
@vinaytekkur
@vinaytekkur 7 месяцев назад
WITH get_active_inactive_status AS( SELECT parent_id, SUM(CASE WHEN status='Active' THEN 1 ELSE 0 END) AS active_status, SUM(CASE WHEN status='InActive' THEN 1 ELSE 0 END) AS inactive_status FROM parent_child_status GROUP BY parent_id) SELECT parent_id, CASE WHEN active_status > 0 THEN 'Active' ELSE 'InActive' END AS final_status FROM get_active_inactive_status;
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