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Solving x^4-16=0 

bprp math basics
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Here we will solve the 4th-degree polynomial equation x^4=16 by factoring. We will use the difference of two squares factoring formula twice, along with complex numbers! I will also show you how a geometric proof of why A^2-B^2=(A-B)(A+B). Note the first step to solve a high-degree polynomial equation is to make the polynomial = 0. I posted this question on my Instagram and it currently has over 11,000 likes. www.instagram....
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#math #algebra #mathbasics

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28 сен 2024

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Комментарии : 110   
@bprpmathbasics
@bprpmathbasics 7 месяцев назад
Solve x^3=8 ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-7ac4fp7M4t0.html
@ampleman602
@ampleman602 7 месяцев назад
Bprp please solve x^1/(x+1)=127^1/127
@0ned
@0ned 7 месяцев назад
ί told π, "be rational!" π told ί, "get real!"
@0ned
@0ned 7 месяцев назад
"irrational" numbers are irrational to integers, but may express ratio, as in the case of π, the ratio of a circle's circumference to its diameter.
@Brid727
@Brid727 7 месяцев назад
e told both of them, "get on me and we all can make a rational and real number"
@cyrusyeung8096
@cyrusyeung8096 7 месяцев назад
However, i is also not rational, so it is not qualified for blaming π as being not rational. P.S. It is also wrong to say that i is irrational
@huhbooh
@huhbooh 7 месяцев назад
​@@cyrusyeung8096 can't "i" be expressed as i/1?
@cyrusyeung8096
@cyrusyeung8096 7 месяцев назад
@@huhbooh π can also be expressed as π / 1, but π is clearly not rational. Moreover, rational numbers is a subset of real numbers, which means that a rational number must be a real number. Since i is not real, we cannot say it is rational.
@PoppySuzumi1223
@PoppySuzumi1223 7 месяцев назад
How about using the rule of *Difference of (4th) power* ? x⁴-y⁴ = (x-y)(x³+x²y+xy²+y³) If the equation must be solved in this way , then what should we do further?
@nickronca1562
@nickronca1562 7 месяцев назад
Never knew x³+x²y+xy²+y³ = (x+y)(x²+y²) but yeah you're right it works out
@ZipplyZane
@ZipplyZane 7 месяцев назад
You could then factor the cubic by grouping: x³+x²y+xy²+y³ = x³+xy²+x²y+y³ = (x³+xy²) + (x²y+y³) = x(x²+y²) + y(x²+y²) =(x+y)(x²+y²) Thus x⁴-y⁴ = (x-y)(x+y)(x²+y²) From there, you still have to factor x²+y². I would still use the difference of two squares: x²+y² = x² - (-1)(y²) = x² - (i²)(y²) = x² - (yi)² = (x+yi)(x-yi) Thus x⁴-y⁴ = (x-y)(x+y)(x+yi)(x-yi)
@keescanalfp5143
@keescanalfp5143 7 месяцев назад
​@@ZipplyZane, thank you, it's absolutely amazing. and - that is a beautiful but long way to Tipperary , isn't it .
@coolskeletondude5902
@coolskeletondude5902 7 месяцев назад
x^4 - y^4 = (x^2 + y^2)(x ^2- y^2) = (x + y)(x - y)(x + yi)(x - yi) where i is the imaginary sqrt(-1)
@nickronca1562
@nickronca1562 7 месяцев назад
@@coolskeletondude5902 That's what I would have done too
@g_vost
@g_vost 7 месяцев назад
there are n valid roots to a radical of degree n. the main one we think of, the principal root, tends to be the positive root for real number inputs, but for complex inputs the principal root is the one with 1/nth the angle with the positive real axis compared to the input. if you look at some stuff about "roots of unity" youll see these roots are equally spaced in the complex plane, and are all of the same magnitude. we want the fourth roots of 16, so there are four roots that divide the complex plane into four. the principal root is positive because the input is real, which means the others must also land on axes, and one could tell reasonably that 16 is the fourth power of 2, as its an important sequence. so altogether we can deduce that the solutions are 2, 2i, -2, and -2i in that order. all can be multiplied by themselves four times to reach 16, as expected.
@MatewParraPerez
@MatewParraPerez 7 месяцев назад
I did not know that a^2 + b^2 = (a + bi)(a - bi), thanks!!
@lornacy
@lornacy 7 месяцев назад
Curious why you don't factor that with your "tic tac toe" method? You will quite easily get the conjugates and the formula just factoring without memorizing the difference of squares.
@keescanalfp5143
@keescanalfp5143 7 месяцев назад
the geometric ‘square minus a smaller square’ in between was a very nice fresh-up , or don't you think .
@lornacy
@lornacy 7 месяцев назад
@@keescanalfp5143 Yes, that was definitely a neat explanation. It's nice to have a variety of different explanations for the same thing in my toolbox!
@thespontaneoustomato2676
@thespontaneoustomato2676 7 месяцев назад
2
@iamgooning
@iamgooning 29 дней назад
I thought x was 2 until I realised this ain't algebra
@nedal1alex123
@nedal1alex123 6 месяцев назад
Can't you just simplify it to x^2=4 then x=+-2?
@dthornto31
@dthornto31 6 месяцев назад
You are making this way more complicated than it needs to be
@zachansen8293
@zachansen8293 7 месяцев назад
I think you posted this to the wrong channel since you're taking us to the imaginary world.
@walterengler5709
@walterengler5709 7 месяцев назад
If we stand defiantly claiming only rational solutions matter what do we get? LOL.
@JubeiKibagamiFez
@JubeiKibagamiFez 7 месяцев назад
I still don't understand why it's equal to zero... Doesn't that make the whole equation pointless?
@ShDynasty_Comma_To_The_Top
@ShDynasty_Comma_To_The_Top 7 месяцев назад
If two factors multiply to 0, then that means at least one of them equals 0.
@darranrowe174
@darranrowe174 7 месяцев назад
This is a common thing. What you are doing when you are finding solutions is actually figuring out where the equation crosses the x axis. If everyone is on the same page, then you can skip right to just writing the equation equal to zero. I would imagine that most of the people that watch this channel knows enough algebra to realise this. But you can imagine that this is a shortcut for: y + 16 = x^4 Find solution for x when y = 0 0 + 16 = x^4 16 = x^4
@telanis9
@telanis9 7 месяцев назад
No, zero vs. nonzero has no relation to something having a "point". Math can be applied for a purpose, but math itself has no inherent purpose; it is a broad, generalized, abstract tool. Math can be used to model physics (much of which involves equilibria, so things balancing out to a net zero effect) just as easily as it can be used to describe something with no known counterpart in the universe. In standard axiomatic math, 0 is useful because it is the additive identity (x+0=x) and has the multiplicative zero property (x*0=0). The latter is made use of here, as Brutongaster707 says.
@garrettbates2639
@garrettbates2639 7 месяцев назад
By isolating zero on one side of a factored polynomial, you can easily find the roots of the polynomial (where the graph of the polynomial intersects the x axis), by using the zero property. The zero property states: If ab = 0, then a = 0 or b = 0 We can consider the two factors in isolation, because the product of zero with a non-zero factor is still zero. Or, in other words: If (x + a)(x + b) = 0, then either: x + a = 0 Or x + b = 0 So x = -a, or x = -b results in a result of 0.
@JubeiKibagamiFez
@JubeiKibagamiFez 7 месяцев назад
@@garrettbates2639 That makes sense... I was going to just take your word for it, but that whole explanation took a little longer to click.... Can you tell I'm bad at maths?
@Nako3
@Nako3 7 месяцев назад
5:33 how did you do that!
@nickronca1562
@nickronca1562 7 месяцев назад
Editing
@Chickenballs10
@Chickenballs10 7 месяцев назад
@@nickronca1562no magic
@lucifer_morningstar..
@lucifer_morningstar.. 6 месяцев назад
did what
@ZipplyZane
@ZipplyZane 7 месяцев назад
Am I the only person who watched math videos of things I already know how to do, because he finds it kinda comforting?
@SuryaBudimansyah
@SuryaBudimansyah 7 месяцев назад
I am a person who watched math videos of things I actually don't know how to do, with the same reason as you
@Mike__B
@Mike__B 7 месяцев назад
I don't know about the only person, but I often will watch just to make sure what I remember on how to do it still is true. For instance here my thought was complex plane, find the real roots, then the imaginary ones make up verticies of a regular n-sided polygon, in this case for n=4 simply rotate the real axis 90 degrees and the corresponding imaginary numbers are also the answer.
@zachansen8293
@zachansen8293 7 месяцев назад
I've found that watching this videos has turned them into things I do know.
@Gremriel
@Gremriel 7 месяцев назад
You had me until i
@jamescollier3
@jamescollier3 7 месяцев назад
2 real solutions. Or, for the more advanced, 2 real and two complex aka imaginary
@taito404
@taito404 7 месяцев назад
Until you what? /j
@Pope_Protein
@Pope_Protein 7 месяцев назад
​@@taito404 I don't like you
@CookingMath
@CookingMath 7 месяцев назад
root of(minus 1) = i@@taito404
@ProtossOP
@ProtossOP 7 месяцев назад
⁠@@jamescollier3complex number consists of real and imaginary parts, so you’re wrong on terminology
@kazruiz
@kazruiz 7 месяцев назад
I don't remember if I learned this method but my first thought was square rooting both sides by four which I would only get two from.
@garrettbates2639
@garrettbates2639 7 месяцев назад
If you take the square root approach, I would do this: x^4 = 16 √x^4 = ±4 x^2 = ±4 √x^2 = ±√±4 This gives you ±2 for the positive branch under the radical, and ±2i for the negative branch under the radical.
@bengt-goranpersson5125
@bengt-goranpersson5125 7 месяцев назад
Would this be an acceptable answer? x=±√(±√(16))
@carultch
@carultch 7 месяцев назад
Usually, you apply subscripts to tell apart independent instances of the +/- operator. You see this, when you look at the quartic formula. The +/- operator appearing twice without subscripts to tell them apart, implies that they are both simultaneously the same sign. The flipped -/+ operator, implies that the flipped sign is opposite the primary sign. You would also want to know, what exactly this number is? As in, where do I find it on the complex plane? Leaving it as irreducible radicals doesn't help answer that question.
@MaxEU
@MaxEU 7 месяцев назад
You can also do it with substitution: x⁴ = 16 Let z ≔ x²: z² = 16 z = ±4 Resubstitution: 4 = x² ⇒ x = ±2 and -4 = x² ⇒ x = ±2i
@josephcote6120
@josephcote6120 7 месяцев назад
It might be interesting to talk about how in a simple situation like this, all the answers are equally spaced points on a circle. This had helped my get a handle on what the answers ought to look like, and sanity check for the range of values expected.
@bprpmathbasics
@bprpmathbasics 7 месяцев назад
If you came from my IG 👇
@Chessplayer81837
@Chessplayer81837 7 месяцев назад
I came from your ig
@mickelsantiagoquispenamuch4961
@mickelsantiagoquispenamuch4961 7 месяцев назад
i came for you
@Aramlyric
@Aramlyric 7 месяцев назад
The WHOLE solution is easier. Just Take the 4th root from each side and you get 2😂
@tomspoors768
@tomspoors768 7 месяцев назад
I was wondering if I'd read it wrong! Why the rigmarole? From 2 to all the others in a second
@La_sagne
@La_sagne 7 месяцев назад
no. the 4throot will only give you 2 as an answer. if you need to find 1 answer, then its fine.. if you find all answers, its not.
@omdano6432
@omdano6432 7 месяцев назад
mashallah the brother does not know how math works, and he wonders why he cant eat the π at his wife and boyfriends wedding
@CookingMath
@CookingMath 7 месяцев назад
bro what @@omdano6432
@telanis9
@telanis9 7 месяцев назад
@@tomspoors768 If you are unable to show your work for something so simple, then you are certainly incapable of solving complex problems where intermediate steps are actually required. This problem is being set for students early in algebra to learn, not for people to point out that easy problems are easy like that makes them superior.
@TV-em9vb
@TV-em9vb 7 месяцев назад
You inspire me and make me love math even more.
@HWPlays
@HWPlays 7 месяцев назад
x^4=16 x=16^1/4 x=4√16 x=±2
@WaranaSJ
@WaranaSJ 7 месяцев назад
i know nothing of maths compared to this
@matei_woold_wewu
@matei_woold_wewu 28 дней назад
x1=±2 x2=±2i
@ZackBlackwood97
@ZackBlackwood97 7 месяцев назад
This is one of those math questions where I knew the answer. But don't ask me how I knew. I can't explain 'i'. All the parentheses confused me. I just know the answer
@J_PIK
@J_PIK 6 месяцев назад
Yeah once you started adding i’s, this is where i get it wrong. I never learned adding i’s.
@andrebullitt7212
@andrebullitt7212 Месяц назад
Wow! I never thought of it that way.❤😊
@jamescollier3
@jamescollier3 7 месяцев назад
imagine that
@lornacy
@lornacy 7 месяцев назад
😂
@Sonicgott
@Sonicgott 7 месяцев назад
Imaginary numbers are weird, but they calculate the negative space within a square or cube. It’s essentially what is missing.
@Mike__B
@Mike__B 7 месяцев назад
Me : I only want answers that matter, so I'm tossing out any imaginary solutions, and even negative solutions because I'm using this equation to represent the real world and everything I care about is to the right of the origin. Punches number into calculator uses the "x-root" button (or raise to power of 1/4) calls it a day.
@afjer
@afjer 7 месяцев назад
Step 1: Be familiar enough with binary to already know the answer at a glance.
@DaveScottAggie
@DaveScottAggie 7 месяцев назад
I like using the geometry to explain it. I did not originally learn that trick.
@ryankarim7141
@ryankarim7141 7 месяцев назад
You can also use demoivres to make sure you never forget abt the complex numbers
@_ksaz
@_ksaz 7 месяцев назад
Why can I watch this video in PiP mode? I didn't even know this existed
@wildfire_
@wildfire_ 7 месяцев назад
He’s brought i to math basics ono
@martocode18
@martocode18 7 месяцев назад
Do you guys know who is dat in photo frame?
@mrmimi807
@mrmimi807 7 месяцев назад
Smash x next question
@aerialjolt_ns2762
@aerialjolt_ns2762 7 месяцев назад
first comment!love ur videos.
@boredomgotmehere
@boredomgotmehere 7 месяцев назад
Cool!
@zachansen8293
@zachansen8293 7 месяцев назад
Why aren't there an infinite number of solutions?
@pixelhy
@pixelhy 7 месяцев назад
Because the degree of the polynomial is 4. The degree of a polynomial states the number of solutions it has (usually). So for a polynomial like x^2 = 16, there's 2 answers, i.e. 4 and -4
@keescanalfp5143
@keescanalfp5143 7 месяцев назад
​@@pixelhy, yeah x = 4 and x = -4 ?
@pixelhy
@pixelhy 7 месяцев назад
@@keescanalfp5143 my bad lmfao I forgor
@OrenLikes
@OrenLikes 7 месяцев назад
What happened at the end? Why the sad, dismayed, face?!? Is everything okay?
@MrMinusMic
@MrMinusMic 7 месяцев назад
@@GordonSimpson-hr4yfreally? What the
@OurLastStand
@OurLastStand 7 месяцев назад
From (X²)² - (4)² = 0 could you just add (4)² to each side and take the square root and get to the same answer faster without factoring?
@nickronca1562
@nickronca1562 7 месяцев назад
No, sqrt(4) will only give you the positive solution. Not the negative solution and definitely not the imaginary solution.
@ZipplyZane
@ZipplyZane 7 месяцев назад
You can instead take the square root twice, yes, but you need to make sure you add the ± each time, and then handle each case. It goes like this: x⁴ = 16 √(x⁴) = ±√(16) x² = ±4 case 1: x² = 4 √(x²) = ±√(4) x = ±2 case 2: x² = -4 √(x²) = ±√(-4) x = ±√(-1)√(4) x = ±2i Thus, combining both cases: x ∈ {-2, 2, -2i, 2i}
@burhanplayz6131
@burhanplayz6131 7 месяцев назад
Woah, I know this topic but somehow u made it way more confusing than it needs to be? e.g. (a - b) (a + b) =a^2 - b^2 because: (a - b) (a + b) = a(a - b) + b(a - b) (a - b) (a + b) = a^2 - ab + ab -b^2 (a - b) (a + b) = a^2 - b^2 Simple as that, the square explanation was way too confusing for me atleast
@richizzle39
@richizzle39 7 месяцев назад
Can you explain how you got to your first step?
@m.h.6470
@m.h.6470 7 месяцев назад
Solution: x⁴ = 16 (x²)² = 16 |√ |x²| = 4 Two cases: x² ≥ 0 and x² < 0 Case x² ≥ 0: x² = 4 |√ |x| = 2 Two cases: x ≥ 0 and x < 0 x₁ = 2 -x₂ = 2 → x₂ = -2 Case x² < 0: -x² = 4 |*-1 x² = -4 |√ |x| = 2i Two cases: x ≥ 0 and x < 0 x₃ = 2i -x₄ = 2i → x₄ = -2i Therefore x ∈ {-2, 2, -2i, 2i}
@ermlerml7925
@ermlerml7925 7 месяцев назад
Finally somebody who uses readable notation and not 500 arrows and brackets everywhere
@kerbereal934
@kerbereal934 7 месяцев назад
√2 , next question
@telanis9
@telanis9 7 месяцев назад
wrong
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