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Something from Nothing 

Math-life balance
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6 сен 2024

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Комментарии : 16   
@math-life-balance
@math-life-balance Год назад
Isn't it terrific! Please share the video if you also enjoyed it :)
@altan3850
@altan3850 Год назад
This particular piece of visual masterpiece is the closest to being the ultimate mixture of mathematics and art that I've ever seen in my life. The storytelling, the images, the examples, the fact that starting from a fun paradox for primary school 0 = 1 we end up discussing cutting edge research just make watching the video a touching and cosy, yet engaging and satisfying experience ❤❤ Huge congrats to Jeremiah Heller, Ivo and of course Elka! The suspense has more than paid off❤
@math-life-balance
@math-life-balance Год назад
yay! :)
@DMVMedien
@DMVMedien Год назад
Great idea! And so nicely drawn und presented! Thank you! 👌
@effy1219
@effy1219 Год назад
please ignore comments trying to correct your content(why dont they create their video!), we want you to do this for fun! devoting time and putting effort into making video is already not easy, we dont want you to spending more efforts or create any mental stress, you dont have to be perfect and we still love your content!!!
@math-life-balance
@math-life-balance Год назад
correcting math content is totally fine, don't worry!
@PeakMathLandscape
@PeakMathLandscape Год назад
Incredible!
@RohitSingh-nm9wd
@RohitSingh-nm9wd Год назад
Just amazing.
@ligmamale4389
@ligmamale4389 Год назад
This is great
@user-rk2ny4pw1l
@user-rk2ny4pw1l Год назад
Shouldn't R+M be isomorphic to M (rather than R as in the video) for a flasque ring?
@jeremiahheller1908
@jeremiahheller1908 Год назад
Yes, thank you!! R+M is isomorphic to M. The example of interest here has M=R which is the source of the typo.
@matti1610
@matti1610 Год назад
Wow nice!
@JakubWaniek
@JakubWaniek Год назад
Around 4:20, are you assuming that your flasque ring R is commutative? Unless P is a right module and M is a left module, I think we need R commutative for the tensor products to make sense. If I'm correct, then we have only shown that a commutative flasque ring must have vanishing K-theory. This is enough to set up the contradiction in argument that follows, but I thought it was worth pointing out anyway
@jeremiahheller1908
@jeremiahheller1908 Год назад
We only gave an informal description. In the formal definition M is a bimodule which is finitely generated projective as a right module and the isomorphism between M and R+M is a bimodule isomorphism.
@TranquilSeaOfMath
@TranquilSeaOfMath Год назад
I like this approach. It is something nice visually and the lecture is like a fairy tale. 🐉🧮
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