Squeeze/Sandwich Theorem 

There was a "typo" in the last two lines on your chalkboard. You left out the "x^2" term. Nevertheless, the answer to the original limit is correct. As an aside, could you do one more squeeze theorem example? Thanks!

Ive never seen someone discover peoples sandwich preferences while doing math. Love the explanation though!

For the first time I understood the squeeze theorem. Thank you!

Literally the best math RU-vidr out there fr

Got hungry after this masterpiece

Omg I finally understand how to construct the squeeze theorem inequality to solve the limit. Thanks a lot

The analogy is really crazy , great video. Very well explain thanks man

You really make my day, now, I have understood squeeze theory

Amazing. As someone who has not taken calculus yet, this makes so much sense to me. Thank you from Canada.

Thy voice is interesting, it is calm and enthusiastic simultaneously. Great video, fam!

I am a 9th grader & really love math......... I was pretty much onto calculus, but only this was what was troubling me, even when I understood Jacobian........ Thank you so much sir for explaining this topic 😊

Thanks a bunch!! I almost completly forgot about it.

Indeed you are powerful, thank you very much you have made the understand easy

Thank you ❤

Never stop learning ❤❤

Wow I love math so much ❤❤❤

2:32 This is unintentionally really funny.

Oxford Mathematic will be call you one day for lectures. AL PAZA

One small remark. When wrote the second inequality (with e) you said you did not have to change the inequality signs because e to x is positive. The real reason is not that but the fact that e to x is a growing function. Also e to negative x is always positive but it is a diminishing function, and in that case you would need to change the inequality signs.

Take the natural log of this expression: limit as x→0 of 2*ln(x)+sin(1/x) is -∞ since |sin(1/x)|≤1. Thus, e^(-∞)=0, so the limit of x^2*e^sin(1/x) t as x→0 is 0.

You are a master who gives easy explanations ❤

What would change if it was x insted of x^2 ?

In Tenet there was a temporal pincer movement, this is mathematical pincer movement

Hello, I am a student from Jordan. I liked your explanation, but I would like to ask if you can explain Advance Calculus??

great calc 1 video as always! i don’t think i can ever eat your sandwiches though 😅

In the last steps x^2 was omitted from x^2 * e^sin (1/x). Was this by accident?

Cool thrm

Or, the theorem of two polices! 😀😉

Sir I have a doubt that if we put a value near 0 like 0.000001 for x and see we find that the graph of x^2 approaches very fast towards 0 and the value of e^ sin (1/x) is always finite because we can use the thita braking method of 90 multiple and adding the rest part thus in this way we can find the value of it as 0 easily

For exp(sin(1/x)) is bounded and x^2 converges to 0 as x -> 0. Therefore, the limit of the product is 0 as x -> 0. For -1

I like weep cream on my sandwich 😅

You have forgot it x^2 to the e^[sin(1/x)]! 😀😉

4:52 some people are vegetarians....

Solution: one function is bounded, the other approaches zero. Hence so does the product of the two functions. All these words and equations are unnecessary. Learning math is, in part, learning to be concise.