SSC CGL 2024 | SSC CGL Maths | SSC CGL Classes 2024 | Number System Remainder Theorem | Ravinder Sir

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29 окт 2024

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Комментарии : 76

@SSCWallahPW 2 месяца назад

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@JyotiJha-zf2gn 2 месяца назад

Homework Answer Option A) 4 Thank you for great session sir❤

@abhishekprasad8039 2 месяца назад

Homework..Ans.A.4 Thank u sir best explaining class

@delhifamilyvlogs1 2 месяца назад

Explain..

@abhishekprasad8039 2 месяца назад

@@delhifamilyvlogs1 51^203/7=2^203/7=(2^3)^67×2^2/7=8^67×4/7=1^67×4=1×4=4ans

@abhishekprasad8039 2 месяца назад

@@delhifamilyvlogs1 (51^203/7)=(2^203/7)=[(2^3)^67×2^2]/7=(8^67×4)/7=1^67×4=1×4=4ans

@_Minakshi_ 2 месяца назад

Ans 4 Nice session sir thanks a lot sir itna ache session provide krne k liye 🙏🙏

@manyamishra5350 2 месяца назад

Very nice class sir 👍👍👍❤❤❤🙏🙏🙏 Homework answer is = 4

@Rishabhdev729 2 месяца назад

ANSWER.A ✅️.......🎉🎉.NICE SESSION .....THANKS ♥️(".")

@praveensingh8975 2 месяца назад

Homework Answer --- 4 Sir Session is Amazing 😍😍 I want you to know that your hard work, dedication, and passion for teaching are truly appreciated. Thank you Sir ☺️☺️🙏🙏🙏♥️♥️♥️♥️

@pritysingh2617 2 месяца назад

Homework answer is C (1) Thank you sir for this superb session 🎉🎉❤❤❤😊😊

@AdityaKumar-tk3pj Месяц назад

Thanks Sir for teaching❤❤❤❤

@sumanduchaniya5686 2 месяца назад

Home work - A (4)

@meetuonline1 Месяц назад

51²⁰³/7 51/7=49+2 (2³)⁶⁷*2²/7 (1)67*4 1*4 4

@LopamudraSahoo-wc9wz 2 месяца назад

Homework ans ,option:A(4) Nice class sir aaj mera late hogya ☹️☹️

@ANNANYA-s3j 2 месяца назад

Home work Option A 4

@SciPhy_Anurag 2 месяца назад

Sir, Option a, Remainder = 4

@poonamrao9735 2 месяца назад

👍

@surajgautam43 2 дня назад

Super ❤

@lost_zoro110 2 месяца назад

A 4

@poonamrao9735 2 месяца назад

H.W. - Option A) 4

@snehpreetkaurhora5179 2 месяца назад

Hi poonam

@muskanafrin0508 2 месяца назад

Thank you for best explanation ❤

@RachnaSrivastava-c8s 2 месяца назад

Sir aap sach me by god bahut acha padhate h 🙏🙏

@anjalikashyap1144 2 месяца назад

Sir ek request h please sir hw ko nxt class m bta diya kriye

@JuniorBharti-z9o 2 месяца назад

Sir aaj ki class bahut hi acha tha aap aise hi pdhate rhiye ❤❤❤❤🎉🎉🎉

@anandtiwari9002 2 месяца назад

Bahut achhi sir

@Mamtapalpal6 2 месяца назад

Home work (a) thanks you so much sir

@TheRitikDongre 2 месяца назад

Thanks a lot sir❤

@BHAKTI_WITH_BHAJAN 2 месяца назад

Home work question answer 4

@Archita-l7f 2 месяца назад

Useful class ❤

@KavitaSaini-ti7yl 2 месяца назад

Very nice class sir

@amrishbarman327 2 месяца назад

Thankyou sir ❤

@anjalikashyap1144 2 месяца назад

Home work ans is 4 Explanation ----- ( 2³)^67 *2² 1* 4 = 4 ans . ❤

@snehpreetkaurhora5179 2 месяца назад

Ek doubt pouchu?

@anjalikashyap1144 2 месяца назад

@@snehpreetkaurhora5179 yes ofcourse

@vipintiwari1423 2 месяца назад

Very nice 👍 class sir ji ❤❤❤

@durgeshwaripathak8027 2 месяца назад

Thank you sir 🙏🙏

@KartikDouchaniya 2 месяца назад

Homework Wale question ka answer 4 hai ,sir ❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤ Class bhut mast thi sir ,mja aa gya ,, sab chamak gya sir

@sushilkumarsethi4494 2 месяца назад

Bhai kaise kya wo bhi explain karde please

@KuldeepKumar-zj3xr 2 месяца назад

(51)^203/7 diya hai ,isme 51 ko 7 se divide krte hai toh reminder 2 bachta hai . Ab isko hum (2)^203/7 likh skte hai . Ab hum 2 ^203/7 ko {(2^3)^66*2^5 }/7 likh skte hai . 2^3 =8 hoti hai . Tb 8 ko 7 se divide krenge toh reminder 1 bachta hai . अतः{ (1)^66*2^5}/7 =(2^5)/7=(2^3*2^2)/7 Ab yha 2^3=8 ko 7 se divide krenge toh reminder 1bchega . अतः (1*2^2)/7=4/7 me remainder 4 hai , Kyoki 4/7= 7*0+4