Q. 92 add 1 in all the terms which we have to find and -3 now we will get a+b+c on Nr which we get common now we have all the values... Put all 10×4/5 - 3 = 5
Sir q) 74. (a²+bc)×a=5a, (b²+ca)×b=-b, (c²+ab)×c=-c so Add three equations a³+b³+c³ + 3abc = 5a-b-c We know a+b+c=0 Replace a³+b³+c³=3abc 3abc+3abc=5a-b-c 6abc=5a-b-c Divide the equation by abc We get 5a-b-c/abc = 6
q. no. 74, multiply all three eqn by a,b and c respectively and add all eqn we will get a3+b3+c3+3abc=5a-b-c it is also given a+b+c=0, then a3+b3+c3=3abc put this value in above eqn 6abc=5a-b-c 6=(5a-b-c)/abc.
sabhi teacher badhiya hain pr sabki approach alag alag hoti hai samjhane ki aur sabka content bhi alag hota hai Smart approach aur Content ke saath ek hi teacher padha sakte hain aur wo hain Rakesh Yadav Sir love from Bihar ❤
Sir question number 80.ko by option bhi kr sakte hai kya abhi thoda thoda idea toh lag hi jata hai ki yeah toh answer ho nahi sakte . By option bhi kr le toh sahi hai kya
Gurudev parnam..... Gurudev Q. 92 me (a, b, c) add krke jo find krna hai usme (+1,-1 ) krke bhi bhut assani se answer aa ja raha hai waise kr sakte hain n gurudev 😊😊😊❤❤❤❤
