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Комментарии : 13

@davidmalerich8469 8 дней назад

Calculating x^3 and multiplying that by x^4 would have been simpler than squaring x^4 and having to do division. Just saying.

@mirandak3273 7 дней назад

Yes! And x^3 is easy to do. It’s just multiplying both sides of x^2=x+3 by x. Now: x^2*x = (x+3)*x =>x^2*x^1=x*x + 3*x =>x^(2+1)=x^2 + 3x =>x^3= (x+3)+3x =>x^3=4x+3

@musicsubicandcebu1774 4 дня назад

Hold left click button down to speed up video.

@GlendonMasters 2 дня назад

Where are you arriving with the baauyrea and basura

@shrikrishnagokhale3557 7 дней назад

Oh shit ! I found my mistake myself .I took x=(√3+1)/2 but it should be (√13+1)/2.Sorry! You are correct.Thanks a lot.We will meet again.GN.

@shrikrishnagokhale3557 7 дней назад

My answer is (71+41√3)/16 Is it wrong?I found the value of x=(√3+1)/2 as per your method,but then I found the value of x^2=(2+√3)/2 Then x^3=x*x^2=(5+3√3)/4 Then x^4=(x^2)^2=(7+4√3)/4and finally x^7=(x^3)(x^4)=(71+41√3)/16 Is anything wrong?

@superacademy247 7 дней назад

You went wrong somewhere in the process of manipulation

@СветланаТравка-л6е 7 дней назад

Вот бумаги- то человеку не жалко!

@maherom1 8 дней назад

Please résolve this équation sqrt (x-1) +4 sqrt(y-4) = (x+y)/2 thanks

@superacademy247 8 дней назад

I'm sure it's for integer solutions.Isn't it?

@johnjohnny-m5z 8 дней назад

simplify further root 3 is 1.74

@key_board_x 8 дней назад

[√39 + √3)/√12] = [√(3 * 13) + √3]/√(4 * 3) [√39 + √3)/√12] = [(√3 * √13) + √3]/(√4 * √3) [√39 + √3)/√12] = [(√3 * √13) + √3]/(2 * √3) [√39 + √3)/√12] = [√3 * (√13 + 1)]/(2 * √3) [√39 + √3)/√12] = (√13 + 1)/2 [√39 + √3)/√12] = (1 + √13)/2 [√39 + √3)/√12]² = [(1 + √13)/2]² [√39 + √3)/√12]² = (1 + √13)²/4 [√39 + √3)/√12]² = (1 + 2√13 + 13)/4 [√39 + √3)/√12]² = (14 + 2√13)/4 [√39 + √3)/√12]² = 2.(7 + √13)/4 [√39 + √3)/√12]² = (7 + √13)/2 [√39 + √3)/√12]³ = [√39 + √3)/√12]².[√39 + √3)/√12] [√39 + √3)/√12]³ = [(7 + √13)/2].[(1 + √13)/2] [√39 + √3)/√12]³ = (7 + √13).(1 + √13)/4 [√39 + √3)/√12]³ = (7 + 7√13 + √13 + 13)/4 [√39 + √3)/√12]³ = (20 + 8√13)/4 [√39 + √3)/√12]³ = 4.(5 + 2√13)/4 [√39 + √3)/√12]³ = 5 + 2√13 [√39 + √3)/√12]⁶ = { [√39 + √3)/√12]³ }² [√39 + √3)/√12]⁶ = { 5 + 2√13 }² [√39 + √3)/√12]⁶ = 25 + 20√13 + 52 [√39 + √3)/√12]⁶ = 77 + 20√13 [√39 + √3)/√12]⁷ = [√39 + √3)/√12]⁶.[√39 + √3)/√12] [√39 + √3)/√12]⁷ = [77 + 20√13].[(1 + √13)/2] [√39 + √3)/√12]⁷ = (77 + 20√13).(1 + √13)/2 [√39 + √3)/√12]⁷ = (77 + 77√13 + 20√13 + 260)/2 [√39 + √3)/√12]⁷ = (337 + 97√13)/2