Sir, please advice.. when we replace a force/F with a force couple system, then that couple's moment is free vector, which means we can place that couple anywhere on the system , just that its magnitude should remain the Fd, where d is distance of shift of original force... is that means Fd magnitude need same say 100 N was original force and 1 m is shift of force , so now we can have these combinations as well , 50N-2m or 25N -4m force couples ? ... i was looking for force couple equivalent videos but could not find, please advice. thank you much ..
I’m not sure what you’re asking. If you replace a force with a force couple system (at a different point), then be sure that the sum of the forces is the same for both cases. And the moment(s) about the point caused by force*distance would be the couple. And your force is now going straight through your point so there’s now Fd anymore. Sorry I don’t teach equivalent force couple systems.
@@engineeringdeciphered thank you Sir. Sorry for not drafting question properly. My question is moment of couple in this situation will be free vector as well ? And we can shift moment anywhere else as well ? Thank you much.
@@shailkumarjain no, these moments that are created by a force are not couples. They are not free vectors. The moment would be different if you calculated it about a different point. Only moments caused by a couple (two forces equal in magnitude and opposite in direction) are free vectors. I think I do have one video on couples.
roc and rod are different vectors, and that determinant will have some different numbers inside of it, but the final answer will be the same. As long as the r goes from anywhere on the axis to anywhere on the force, you'll get the same answer. It's pretty cool to try a few different r's and sometimes you can see why they'll give you the same answer.
