STL std::list | Modern Cpp Series Ep. 118 

I've never had a use for linked lists (yet), but I have a soft spot for them. It was while learning python and creating my own linked list class, that programming finally "clicked" for me. Instead of needing to look at the tutorial and just copy/paste, I could actually create every method on my own. 🙂

Keep up the good work Mr Mike this video has been very helpful. Your teaching method is one of the best I have seen on the internet

@24:10, i think in the 'merge' operation of a std::list, nodes from one list ( 'other' in this context) are reorganized into another list (list). This is done by adjusting the next and previous pointers of the nodes, rather than moving or copying the data they contain. This makes the merge operation more efficient than similar operations on other data structures, like arrays or vectors. After the merge operation, ' other' no longer contains any nodes. Its internal pointer to its first node (i.e., its "head") is set to nullptr, giving the impression that the list is now empty. In essence, 'other' as a standalone list no longer contains any elements. However, it's important to note that the nodes from 'other' have not been destroyed or removed. Instead, they've been linked into list. This is the beauty of the linked list data structure and the merge operation: it can reorganize data efficiently by manipulating pointers, without the need to physically move or copy the data. That's my understanding of merge in std::list. Thanks for the great video Mike! 👏 I am watching the whole STL series for the second time and learning new thingS.

Just a heads uo; Splice can also be used to move an element within a list. Details in cppreference std::list::splice.

Amazing tutorials about STL, very handy!

youre one of the different teacher sir, please show us something that others don't share , like u did in this video

Helpful and informative, thanks for continuing the series. How about having light theme over dark for tutorials.

@4:16 When you say as long as we have iterator , this also mean we are having O(i) if i is the position of the list in the std::list object right? it wouldn't be O(1) if we calculate iterator part too.

Thanks much!

keep going dont stop mate

Great video

You're so cool, thanks again