It is a real pleasure to watch and listen to your explanation. At first I didn't quite understand what you meant by a surogate weak link. But when you went out, it hit me like a lightning strike. Both a strong link behaves the same as a weak link if A is true. Then B is wrong. This also applies to a weak link. Hence the word “surogate”. I get it. Thank you very much for your clear explanation!
Fantastic. Yes, a Strong Link can provide a Weak Inference. Once you understand this principle, all Chaining becomes clear. I appreciate your comments!
In proper English, we would say, "You explain much more clearly than most ... ." Saying "... much more clearer than most" indicates low education and low class.
I have been out of sudoku for several months; as a result, I am having to start over with your lessons. On the positive side, I can better understand the concepts you are teaching.
It’s so cool to have the language to understand the tricks I’ve developed over years of being self taught, and understand the principles that make them true. I’m astonished I was able to chain together so many links without this language.
Mallorca! I have been to Cartuja. I made a special trip because of my love for Chopin's music. I stayed on the north shore of the island, right by the sea, at Michael Douglas' estate in Valldemossa, and one day drove to Palma. Great experience.
@@SudokuSwami : I am glad you liked my beautiful island. Thanks again for your extremely useful tutorials. I would like to comment something else. In the distopic idiot sheepy society we live nowdays, LOGIC is despised, it is not appreciated, so your videos are targeted to a very small minority of people.
I feel like you excessively kicked a dead horse, tbh. I feel as though it was only really necessary to point out 2-3 examples. Nonetheless, I understand the concepts really well now so thank you :)
The # of links L between N candidates is calculated like this: L = N * (N-1) / 2. So 5 candidates, N = 5, gives # of links L like this: L = 5 * (N-1) / 2 = 5 * 4 / 2 = 20 / 2 = 10. 5 candidates gives 10 weak links!
I'm enjoying learning but i find the example of strong links with 7 funny only because through the quad in the middle columns you can figure out that 7 is the only choice on left.
Hello Shalimar. Because you did not specify the "time" in the Video, I have no idea what you are talking about. But you are missing the point. The examples in these Lessons are for DEMONSTRATION PURPOSES ONLY. I am not trying to SOLVE these positions. I am trying to demonstrate various principles, so you can use them when you are solving REAL Puzzles. :-))
Ron, you could grab ANY TWO of those 7's and make a Weak Link between them. I understand that English is not your first language, but to understand my Tutorials, YOU MUST LISTEN TO WHAT I AM SAYING. I just picked the two outside 7's for an EXAMPLE. You could make a Weak Link between ANY TWO 7's in Row 2 at 12:00 of the Video.
ihav e a question at 14 minutes why do you know that R2K2 and R5K2 is a weak link? why do you know that R5K2 and R8K2 and R4K2 and R9K2 is a weak link? why are the numbers on the inside not a weak link?
Hello Ron, in the example at 14:00 we are looking at all the Candidate 3's in Column 2. The definition of a Weak Link, is: If A is True then B is False. That definition will apply to ANY TWO Candidate 3's in that Column. If ANY of those Candidate 3's are True, then ALL the others would be False. But you must remember, this is only a SUPPOSITION. It is a Conditional Statement. But this still means that if you suppose ANY ONE of the Candidate 3's in that Column to be True, then any OTHER 3 in that Column that you pick, would have to be False, which further means you could make a Weak Link between them. In my narration, I just chose a couple of RANDOM SETS of 3's to say there was a Weak Link between them. If you listen carefully to what I said there, I said that there is a Weak Link between ANY TWO Candidate 3's in that Column, because if any one of them were True, then the other would be False. This follows the definition of a Weak Link.
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Nothing. Cypriot, you must understand that this is merely a DEMONSTRATION. I am demonstrating that when there are only two instances of a particular Candidate within a House, there is a Strong Link between them. As it turns out, there cannot be a 6 in R4C9. That Cell will eventually be solved for 1. But you are right....we don't know that yet, at this point of the puzzle. I made this Video a long time ago, and I apparently removed the 6 in R4C9, so I could make a very simple point. Please try to focus on the point I am trying to make. Cheers. Good luck.! :-))
