Want to know how to solve simultaneous equations by substitution? Look no further! In this video we learn how to solve simultaneous equations using the substitution method. I hope you find this video helpful in one way or another!
Literally me, my teacher couldn’t explain it right to me, and I have a test tomorrow I started tearing up since I couldn’t understand anything but this video made me understand it this guy does a great job explaining
@@pieceofpiiyo ur teaching is sooooo good do you not post or teach anymore cus your PowerPoint's and explanations are extremely helpful I'm in year 8 and my teacher is not good at all and has an accent that can't understand well, if you can post year 8 stuff it would really help so I could tell my class about your channel 😅
Bismillah hir rahman nir raheem . Substitution equation 1) make an equation from either eq1 or eq2 ,don't forget to make y subject ( y=) 2) put y's value to either eq1 or eq2 to find x's value 3) now put x,s value to chosen equation to find y .
Good question! It does not matter which method you use, they will give you the same answer. However, some people find one method easier than the other, and also, some questions are more suited to one method than the other, so it is helpful to know both, especially if you want to be really good :)
my teacher literally says do it yourself why didn’t you understand when i told you the first time and like after looking through a million videos and found yours and if someone asks me who was the reason you passed math i’m giving them your channel zero credits to my math teacher i hate that guy
No worries, technically you do subtract from both sides (as what you do to one side you must do to the other), however, one side will cancel out so I see why you think the subtracting is only occurring on one side. Don't want to over complicate it though, once you do a problem, you'll get the hang of it quickly :)
7x + 11y = 1 ....... (1) 8x + 13y = 2 ....... (2) Multiplying Equation (1) and Equation (2) by 8 and 7 resepectively, we have 56x + 88y = 8 and 56x + 91y = 14 Subtracting the second equation from the first, we get -3y = -6, i.e., y = 2 From Equation (1), x = 1 − 11 ( y ) 7 = 1 − 11 ( 2 ) 7 = − 3 ∴ x = -3 and y = 2
11x has a coefficient of x, so it can only be added by other numbers with x behind it (coefficient of x). So like 5x+3x=8x. 48 has no x, so 11x doesn't change.
