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That Killer Cage Has A Total Of 170?!! 

Cracking The Cryptic
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** TODAY'S PUZZLE **
A debut on the channel today for SamuPiano and their puzzle Global Ocean. This has several odd looking cages and one that seems bonkers. There is some stunning logic at play here though but it takes some thinking to crack :)
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Rules:
This is a 9x9 map of the ocean - there are ocean cells and island cells. Normal sudoku rules apply. Digits in cages must sum to the small clue in the top left corner of the cage. Digits cannot repeat within a cage with nine or fewer cells. Cells separated by an X must contain digits summing to 10. Not all Xs are given. HOWEVER, 18 cells - two in each box, row and column -are 'island' cells - these do not count toward the cage totals. Only 'ocean' cells count towards cage totals. There can be as many island cells as needed in any cage.
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5 авг 2024

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Комментарии : 219   
@SamuPiano088
@SamuPiano088 Год назад
SamuPiano (pronunciation ambiguous) here - thank you so much for featuring my puzzle and I'm glad you enjoyed!
@trisha2584
@trisha2584 Год назад
Great puzzle. Hope you will produce more soon
@SomethingWellesian
@SomethingWellesian Год назад
Ah I knew I recognised your name! I just did your six by six Islands puzzle a couple of days ago! Love this ruleset. The 9x9s were a bit too hard for me but I think I made a respectable start on the first one all the same😊 Really looking forward to this video now.
@falloutfan2502
@falloutfan2502 Год назад
Masterful!
@wuorson5111
@wuorson5111 Год назад
Hi friend, does Island Cell count towards X totals? (I know they don’t count for killer totals)
@SamuPiano088
@SamuPiano088 Год назад
​@@wuorson5111yes! The rules only state that islands do not count for CAGE totals, but nothing else. Therefore the X clue may include an island.
@MartinFindon
@MartinFindon Год назад
Glad Simon is colouring the sea blue, especially after the grey bushes earlier this week.
@provence8917
@provence8917 Год назад
Has happened before where the sea was orange and the islands blue.
@MartinFindon
@MartinFindon Год назад
@@provence8917 Good Lord!
@AndyeKAA
@AndyeKAA Год назад
​@@provence8917that one was a funny one 😂😂😂
@davidmiller9485
@davidmiller9485 Год назад
Not all of us have a green thumb! ;P
@justinwhite2725
@justinwhite2725 Год назад
The sea is a wall therefore it should be Grey.
@sjm6280
@sjm6280 Год назад
By the 21 cage, he may conclude the degree of freedom from the 170 cage is spent in either box 3 or box 6, so the cage contents in the remaining boxes must be maximized
@kilimanjarocruz660
@kilimanjarocruz660 Год назад
That was the key for my solve as well.
@blcmd
@blcmd Год назад
I was wondering during most of the solve whether he would discover this. It would have saved him a lot of time.
@user-kt9vr1wj6y
@user-kt9vr1wj6y Год назад
The same here
@petergerlagh9858
@petergerlagh9858 Год назад
@@blcmd me too
@ashnikchauhan9103
@ashnikchauhan9103 Год назад
Yess, Though I did do the whole maths thing of finding 29, working on the 21 cage was the key break in. Though I love long CTC video this could have been a lot shorter.
@minorasimulator
@minorasimulator Год назад
Travis said he forgot to tell you where we were - but we're in Australia so this actually came out on my birthday! Thank you for reading the shout out :) On being part of the household - he doesn't watch you guys, but every now and then I forget to bring my headphones to his place and so I listen out loud. He can tell you guys apart by voice, and no longer turns around when I scream at the screen about where to look next in the puzzle - depending on what I'm shouting, sometimes he can tell you apart when I'm wearing headphones 😅
@olliollioxinfree
@olliollioxinfree Год назад
I’m not very good at these difficult puzzles but I love following along. It’s also great for my self esteem when I’m able to see things that Simon (who I hold in rather high regard) does not , even though alas it is most often sudoku logic. But when it isn’t, I feel even smarter 😊
@Riqu213
@Riqu213 Год назад
Simon, that was my longest scream to date. LOL. At around 0:24:00 you note that r3c9 and r6c8 had to be both an 8 or 9 and the same number. You had already noted the 1 degree of freedom in the cage. Almost 62 minutes later, you found it again. Now I have no idea if the handful of 8s and 9s that produced would have made the solve any quicker, but it couldn't have hurt. Maybe tomorrow I'll try a little louder. 😃
@hrbattenfeld
@hrbattenfeld Год назад
Longest smile to date for me, because it made me say: "Well done, brain." :)
@fatman3762
@fatman3762 Год назад
Having both be 8 would have only brought down the degree of freedom by 1. The 8 being in r3c9 brings it down by 1, but then that allows the cells in the box beneath to be 9876, with 8 in r6c8. So no, that wouldn't have been enough to conclude that those cells had to be 9.
@Riqu213
@Riqu213 Год назад
@@fatman3762 *tips hat* When I'm wrong I'm wrong. Man, I even rechecked against the 21 cage when the islands in box 6 were revealed but going back over them now, they work the other way also.
@hrbattenfeld
@hrbattenfeld Год назад
@@fatman3762 Hm... wasn't one degree of freedom all that was needed in the 170 cage?
@iancastro2414
@iancastro2414 Год назад
After sum the cages(376) and realizing that the sum of the islands is 29, you have two degrees of freedom. However, if you use 9 ones, 8 twos, and 1 four (or 8 ones, 9 twos, and 1 three), it becomes impossible to place two islands in each row, column, and box. Therefore, you need 9 ones, 7 twos, and 2 threes. With this in box 4, the maximum number of cells you can remove is 4 (the 1 and 3), not 5 as Simon was considering.
@jaeusa160
@jaeusa160 Год назад
Ah that's cute. Because if there were 8 x 2 Islands, since the Islands follow sudoku rules, the 9th non-1 Island would also go where the 9th 2 goes.
@petergerlagh9858
@petergerlagh9858 Год назад
indeed
@stephenmor66
@stephenmor66 Год назад
I got the islands sum to 29. Which means at most 11 in any three boxes. The 8 cage and the two 9 cages must have at least 11 in islands, if you minimise the digits and subtract 8+9+9. So we know this is the case. We can place 123 in the 9 cage in box 1 of which two are islands. And 1234567 in the 8 and 9 cages in box 4 of which two are islands, and place 12 in the 9 cage in box 7 both of which are islands. In every other box the islands are 1 and 2.
@SamuPiano088
@SamuPiano088 Год назад
SamuPiano here - actually, an early version of the puzzle utilized this fact! That deduction I eventually deemed to be too obscure for the solve which would detract from the experience.
@asbjrnfossmo1589
@asbjrnfossmo1589 Год назад
@@stephenmor66 Yeah, that was my way in as well.
@inspiringsand123
@inspiringsand123 Год назад
Rules: 09:30 Let's Get Cracking: 11:41 Simon's time: 1h17m52s Puzzle Solved: 1:29:33 What about this video's Top Tier Simarkisms?! The Secret: 6x (13:22, 13:39, 13:53, 45:33, 53:47, 1:03:34) Bobbins: 2x (46:14, 46:14) Maverick: 2x (37:17, 37:17) Cooking with Gas: 1x (41:06) And how about this video's Simarkisms?! Ah: 27x (03:13, 15:03, 21:56, 24:31, 24:31, 24:31, 25:43, 25:50, 25:58, 31:08, 31:08, 34:56, 42:51, 44:07, 49:31, 49:55, 51:35, 51:38, 59:23, 1:09:43, 1:10:06, 1:10:08, 1:14:58, 1:16:13, 1:19:41, 1:21:11, 1:25:16) Hang On: 23x (03:09, 14:41, 15:45, 29:01, 51:38, 51:38, 51:38, 51:48, 51:48, 51:48, 1:08:07, 1:08:07, 1:09:18, 1:11:20, 1:11:30, 1:13:28, 1:13:39, 1:14:03, 1:14:30, 1:18:49, 1:22:56) Sorry: 13x (01:57, 06:33, 21:42, 33:08, 33:48, 43:03, 57:53, 58:27, 1:00:01, 1:07:29, 1:10:58, 1:12:00, 1:13:12) By Sudoku: 6x (1:09:22, 1:12:43, 1:22:48, 1:26:47, 1:27:16) In Fact: 5x (31:53, 53:12, 55:04, 1:02:37, 1:20:31) Obviously: 5x (04:42, 18:35, 21:53, 45:23, 1:26:25) What a Puzzle: 3x (1:21:02, 1:29:24, 1:29:32) Lovely: 3x (06:00, 06:11, 1:26:41) Beautiful: 2x (1:26:30, 1:26:30) Incredible: 2x (01:50, 01:55) Deadly Pattern: 2x (1:14:18, 1:14:21) Puzzling: 2x (01:39, 05:37) We Can Do Better Than That: 2x (12:36, 1:17:48) That's Huge: 2x (20:51, 20:52) Cake!: 2x (05:52, 07:02) Naked Single: 1x (1:25:58) The Answer is: 1x (1:11:26) Clever: 1x (1:29:43) Stuck: 1x (32:38) Brilliant: 1x (1:30:49) Ridiculous: 1x (27:45) Astonishing: 1x (04:04) Come on Simon: 1x (1:21:00) Shenanigans: 1x (23:50) Surely: 1x (27:30) Marries Up: 1x (49:35) Wow: 1x (1:05:43) Sting in the Tail: 1x (1:21:09) Fabulous: 1x (03:52) Most popular number(>9), digit and colour this video: Ten (24 mentions) One (160 mentions) Blue (10 mentions) Antithesis Battles: High (3) - Low (2) Even (5) - Odd (0) Column (12) - Row (10) FAQ: Q1: You missed something! A1: That could very well be the case! Human speech can be hard to understand for computers like me! Point out the ones that I missed and maybe I'll learn! Q2: Can you do this for another channel? A2: I've been thinking about that and wrote some code to make that possible. Let me know which channel you think would be a good fit!
@philipnitschko9093
@philipnitschko9093 Год назад
The Moment when Simon recounts all the cage totals to make sure he didn't made a mistake and murmurs the sums, as suddenly he hears Maverick flying by and like a reaction from his spine he has to mention him. Its hilarious ^^ Gosh I just love to watch you solve puzzles
@stevieinselby
@stevieinselby Год назад
For someone who loves Star Battle 🌠 so much, Simon spent a lot of time _not_ looking at which rows, columns and boxes already had their two island cells 🏝 ... would have been a lot quicker if he had added up all the cages 🧮 at the start and found that the islands totalled 29 across 18 cells, giving very little freedom (which is quite appropriate ... if you are in a cage on a desert island, you have very little freedom!)
@Anne_Mahoney
@Anne_Mahoney Год назад
Yeah: Star Battle was clearly in the background here, though with no restrictions on putting stars/islands next to each other.
@57thorns
@57thorns Год назад
yes, even if it was towards the end with the 9 cage in box 1 I basically lost where Simon was heading when the solution was right there in the colouring.
@Cthulhus_Mum
@Cthulhus_Mum 11 месяцев назад
My immediate response to this was to work out there were 29 islands (so at least 8 each of the 1s and the 2s, with the last two either being a 2 and a 3 or a 1 and a 4). Still really early in the video, though. He's messing with the 170 box and I'm smiling :-)
@AugustoValentini
@AugustoValentini Год назад
I always need to watch Simon explaining the rules and fiddling for a bit with killer sudokus before I can try them myself, I'm really terrible at finding where to start. After Simon did the min/max calculation for the 170 cage and found out there only was 1 degree of freedom, I stopped watching and started doing the puzzle alone. I managed to finish it in about 40 minutes then. I didn't do it all by myself but I'm still proud for having finished it.
@user-ox9oo6wp6d
@user-ox9oo6wp6d Год назад
I was thrilled with the length of the video and I was nearly not trying this puzzle. But turns out it only took me around 39 minutes to solve. Edit: I think Simon was confused about the 29 for the island cells. Actually the easier way to continue at around 46:14 is to do Sudoku on box 2, and notice r1c45 can only be 345 by Sudoku, and they are both in 6-cell 36 cage. Then by "the secret", the 3 missing cells have to sum up to 9, but if those 3 cells are either 234 or 135, r1c45 will be double 5 or double 4, so the only thing left is to miss out 126. Then by Sudoku again, using the 67 pair in box 2, 6 in box 1 is on row 2, which forces 6 in box 3 on r1c9, remove the 6 in the quarduple in box 6, which remove the freedom in the 170 cage. From there, the puzzle just flowed like water!
@jensschmidt
@jensschmidt Год назад
But… wouldn’t that have required Simon to do Sudoku in a Sudoku puzzle? 😂
@user-ox9oo6wp6d
@user-ox9oo6wp6d Год назад
@@jensschmidt Yes, that's why it's hard for Simon 🤣
@Jermo484
@Jermo484 Год назад
I also summed up boxes 5,6,7,8,9 plus the 89 pair in box 3 (242 total) compared to the total cages in those boxes (227 total) to realize that the islands in boxes 5-9 all needed to be 1/2 pairs.
@QuarkTwain
@QuarkTwain Год назад
Ah yes, that's clever! The "6-cell 36 cage" means the 6 cells from the 36 cage which still count after the island is removed. And the "3 missing cells" are the three digits not used in the 36 sum.
@johnh2052
@johnh2052 Год назад
I'd basically just posted something similar. (Delete that.) Simon got really stuck on the last missing islands. But after being led from one cage to the next by the setter, I didn't spend any time on that and instead looked at the options for the now-restricted 32- and 36-cages. This led reasonably quickly to forcing a 6 into the 32-cage in box 1, which put a 6 in R1C9. This immediately meant the degree of freedom was used up in box 6, and the rest went relatively smoothly, as you say. I suspect this was the path the setter meant to be followed.
@ellaser93
@ellaser93 Год назад
This Sudoku Puzzle has more "Nun Counting" than a Catholic Census.
@najinsky
@najinsky Год назад
I'm not convinced removing the 3 from the islands in box 7 was earned around 1:08:00 (even tho it was right). All Simon had proved at that point was that the islands in boxes 1, 4 and 7 had to total 11, but not how they did so, so the island in box 7 still could have included a 3 at that point in the solve. The way I worked it out was by noticing that the totals of boxes 3, 5, 6, 7, 8 & 9 was 270 by Sudoku but 252 by Ocean with the 6 island pairs in those boxes accounting for the difference of 18 (1+2 = 3 , * 6), meaning the islands in box 7 had to be 1 & 2. Still, a great puzzle and as usual an entertaining solve by Simon. Love the channel.
@chalfo
@chalfo Год назад
I do wish Simon would apply his revelations of forgotten rules (in this case 2 islands per r,c,b) to the rest of the grid before fumbling about for 5 minutes trying to use it for the one occasion he's noticed.
@RoderickEtheria
@RoderickEtheria Год назад
It occurred to me to note the secret of a sudoku board, 405, and then sum the cages to 376, which leaves 29 on islands which have an average for rows, columns, or boxes of 3 remainder 2.
@jimdavis2683
@jimdavis2683 Год назад
O frabjous day! Callooh! Callay! I've been following the channel for years now and this might be the first time I've ever truly stolen a march on Simon. 32:10 solve time for me. Started right away by adding up all of the box totals and realized the extreme limitations on the islands, then worked through the logic on the 8/9 cages. Never even looked at the 170 cage, it just fell out at the end. 1 W 999 L vs. Simon times, but I'm sure I'm starting a streak! (Of course I think this is mostly about Simon being mesmerized by the 170 cage up front, I'm guessing many others will have a similar experience.)
@cjmatthews4246
@cjmatthews4246 Год назад
Surprised to see an ambiguous amphibian reference here haha
@RichSmith77
@RichSmith77 Год назад
Quite pleased with a 64 minute time on this. Helped that I started by summing all the cages and getting my break-in in box 4 with the 8,9 cages needeing to use the degrees of freedom. I also seem to remember deducing early that there had to be 2 islands in the 8 cage, and it used one or two of the degrees of freedom. (I never thought to look at the maximum for the 170 cage, as Simon did. Fortunately, I didn't seem to need to.)
@dralthoff1
@dralthoff1 Год назад
This was me too! Getting the sum of 29 islands was incredibly powerful and immediately I ran into the trouble of the 8 cage in box 4 and trying to make the math work out. From that the 9 cage next door leaps out as extremely constrained and everything builds from there. I think that Simon stubbed his toe badly in looking at the 170 cage!
@RichSmith77
@RichSmith77 Год назад
@@dralthoff1 Although, reading the comments from others, I see it was possible to use the 21 cage to pin down the one degree of freedom for the 170 cage to box 3 or 6, which would have helped Simon a lot. So I guess there were two ways to approach it. But yes, summing all the cages was my first thought (followed by, "do I have to" and "I guess I better" 🙂)
@awebmate
@awebmate Год назад
Box 4 definitely does the trick. Looking at the 8 cage and both of the 9 cages together solves it all. The rest is quite easy after that.
@Swisswavey
@Swisswavey Год назад
It took me 72 minutes and was one of the most enjoyable puzzles I've done in weeks. Absolutely loved it, thanks for sharing it.
@iceberg54321
@iceberg54321 Год назад
You did it the hard way by not seeing the 170 single degree of freedom was used up in box 3 or 6. If you put an 8 in r3c9, then you used it up, and if you put a nine in it, then you needed to use the six in the 21 cage, and used it up. Then you would have had most of the 12 islands and the maximum values in the rest of the blue 170 cages, which would have made things a lot easier.
@maavinkayi
@maavinkayi Год назад
This
@murkbaccafett2187
@murkbaccafett2187 Год назад
Wow, that does make it much easier. Nice one!
@HCR2_Actuary
@HCR2_Actuary Год назад
I usually don’t attempt puzzles where the video is over an hour, but I love killer cages so gave it ago. Finished in 51 min. Feel like I found the intended path by doing the math and realizing I only get two degree of freedom on island values, then focusing on the interplay of the 8 and 9 cage in box 4. Basically moved around the grid after that as each cage was filled in.
@jaega4247
@jaega4247 Год назад
Really beautiful puzzle by SamuPiano! And a somewhat confusing, but still very clever solve by Simon! I'm a little confused myself about my own break in, after watching SImon's solve, and wonder if I just got lucky: I started immediately with the global sum of all cages, figured that I needed all 1's and most 2's on the islands, which pointed me to the 8-cage, as I couldn't figure any way to have less than 2 islands in it. This then kept pushing islands around the grid, before I even started looking at the 170 cage. What I failed to appreciate was Simon's theory of one island with a 4, or one 1 going in the ocean. I just couldn't make it work as I looked at the 8-cage, and claimed the islands had to be 9 1's, 7 2's and 2 3's, but in hindsight it makes me wonder...
@FryGuy1013
@FryGuy1013 Год назад
I've never seen a more different solve path from my own and Simon's. I started on the fact that was discovered about 50 minutes in that there were 29 worth of non-counting cells in the grid. Then combined with the small cages in box 4 and box 1 adding up to 26 but having a minimum sum of 34, which means they need to use 8 worth of non-counting cells and given that it's in two of the boxes, that uses up the two degrees of freedom and proves all the other non-counting digits not in boxes 1 and 2 are 1/2. And then I basically completely ignored the 170 cage since I thought it wasn't useful at that point. So my grid started filling in in box 4 and went around the grid, but Simon started in box 6 and went the other way. Although, I think I would've solved it much faster by at least considering the 170 cage because it seemed pretty profitable to know that the digits in its cage were near-maximal. Kind of amusingly I thought that the 1/2 non-counting digits in the 30 cage box 3 would force the 6/7/8/9 in box 2, but ended up proving that the box 2 was 6/7/8/9, thereby forcing the 1/2 non-counting. And Simon proves it the way I thought it was supposed to be really early in the solve!
@sanabas1
@sanabas1 Год назад
I did this when first published, and I'm surprised by the video length. I've only skimmed the video, but it seems Simon hasn't thought to apply basic arithmetic to the puzzle as a whole, and has also missed box 4 as the breakin. Which is a shame, because it was a really good breakin. Add all the cage totals, apply the secret, the 18 islands must add to 29. Look at just box 4 + the two 9 cages that protrude from it. They must add to at least 45 + 6 + 3 = 54. The most r4c23 can be is 17, so the 8/9/9 cages must add to at least 37 when the islands are included. The most the islands can add to is if all the box 147 islands are in those cells, and all of the other boxes have 12 pairs as their islands, leaving 11 for the islands in box 147. 11 for the islands + 26 for ocean in the 8/9/9 cages = 37, so now that is forced. r7c23 is a 12 pair, and island. r3c123 is a 123 triple, with 2 islands. r4c23 is an 89 pair & ocean, and r3c2 is 1 or 2. So now r56c3 are ocean, r3c3 is island, r4c1 is ocean, and the 8 cage has 2 islands. A quick look at the possibilities for the r3 islands: 23 means 8 in r4c1, that's impossible. 12 means ocean 3 in r3c1, 6 in r4c1, so now the 9 ocean in c3 is 45, the ocean in the 8 cage must be 17, the islands must be 23, but that means 3 islands in c2 and only 1 in c1, so that's broken. So the islands in r3 are 13, r4c1 is 7, the islands in box 4 are also 13, the 8 ocean must be 26, leaving 45 for r56c3. And then the rest of the puzzle is very easy, and flows really well. Easy because every cage now reaches its total without using 1 or 2, so islands get quickly forced. e.g. if the 32 cage only has 1 island, its minimum sum is 345689 = 35, so it has 2 islands, and only 2 spots for them. 1289 are already in the cage, 3 can't be in it, the remaining 3 cells add to 15, so must be 456, and so on. edit: Simon does half the breakin at 1:05:00, and then the other half at 1:16:30. If he started there, it would have been a 30 minute video. ;)
@JeffreyLByrd
@JeffreyLByrd Год назад
I took a look at this puzzle and knew that I wouldn’t be able to solve, and after watch it I know that it’s because I’ve never been any good at counting nuns.
@stevieinselby
@stevieinselby Год назад
I can't even count them as far as 1 ... I just get stuck on "nun" 🤣
@ianoz1
@ianoz1 Год назад
My break-in. Cage totals = 376... subtract from 405 gives the number of "silent" cells = 29 within 9 boxes. If all silent cells were min (1+2), total silent would be 27. Gives only two degrees of freedom across ALL silent cells. Gives either 2 boxes with silent 1+3... OR... 1 box with silent 1+4 or 2+3. All other boxes have silent 1+2. Looked immediately at Box 4.
@MrGibbonaben
@MrGibbonaben Год назад
Same approach here.
@aere481
@aere481 Год назад
There is a subtlety of cage placement that I really enjoyed.
@crystalgehrt8861
@crystalgehrt8861 Год назад
I really enjoyed solving this one. The logic is fascinating and unique. Watching Simon was a joy as well. Thank you.
@ServantOfSatania
@ServantOfSatania Год назад
53:31 This was a fun puzzle, finding where to trim the fat off the 170 cage was quite a treat, and I definitely liked the surprise near the end
@katarinasmith5288
@katarinasmith5288 Год назад
When he says I like comments especially when they are kind makes me sad cause it implies sometimes there's people putting unkind comments on these videos 😭 I hope they are very rare. I love these videos even though I don't often watch them, keep up the good work. :)
@raysouth1952
@raysouth1952 Год назад
I wasn't going to watch this but there was a pile of washing up to do so I set my iPad up above the sink and watched as I washed. Glad I did. What a puzzle, and so brilliantly solve.
@debrabowen4276
@debrabowen4276 Год назад
Ninety-minute sudoku variant videos with Simon light up my life!
@neilok17847
@neilok17847 Год назад
Love that you explain your logic. So fun to watch thank you!
@amysteele2488
@amysteele2488 Год назад
Wow, what a puzzle indeed! (That 6 in the corner was absolutely mighty)
@Coyotek4
@Coyotek4 Год назад
49:10 ... I stunned myself on this one, finishing in under an hour. Thank you, math! Incredible puzzle!
@davidellis4031
@davidellis4031 Год назад
Just under 50 min for me - glad I tried it as it's a lovely puzzle with the interaction between the cages in boxes 3 and 6 taking away the last degree of freedom from the 170 cage.
@jakobskog6453
@jakobskog6453 Год назад
I love watching the brilliancy of the solves, while also slowly dying inside because of the x clue haveing to be made of two counting cells. You got there, but seeing that you need two numbers to make 10 would have been a big help and saved about 20 min i believe ;)
@Bonar09
@Bonar09 Год назад
I think I did most of the logic Simon found near the end at the very beginning - after summing everything we notice that there's 2 degrees of freedom on islands, so neither 8 nor 9 can be 3 cells large! 125 means the lowest islands are 3/4, 134 2/5, 234 1/5, 126 3/4 and 135 2/4, all of which are bigger than the two degrees above 3 we're allowed. In that case - box 4 has two islands in 8 (the rest is ocean), box 7 has two islands in the 9 cage (the rest is ocean), X has to be ocean as one cell can't be 10, meaning that islands in box 1 are on position 7 and 9. That was my start to this puzzle, apart from noting that all islands had to be from 1/2/3/4 and were extremely constrained.
@changjsc
@changjsc Год назад
Very enjoyable solve! I have taken to solving alongside Simon while he solves these days while trying to sneak ahead. Early on, you can use the other cages (aside from 170) to prove that there are no degrees of freedom for the 170 cage. In box 6, in order to satisfy the 21 cage it must take at least a counting 6, even with an 8 or 9 in r3c8, so the 170 cage must be 5789. From there, the logic cascades to the other cages as well. It quickens the solve just a bit, but mainly just at the end, since you can maximize all cells in the 170 cage. For example, you know 89 needs to go in r12c6, which forces 89 in the 36 cage to box 1, forcing r4c23 to be 89, accelerating the logic there.
@martincollins11
@martincollins11 Год назад
Fantastic puzzle. Absolutely loved it 😊
@falloutfan2502
@falloutfan2502 Год назад
Wow, that was worth staying up for! Great solve!
@Urutsini
@Urutsini Год назад
Simon said it so much that I started to consider the logistics of counting nuns . . .
@michielgerretzen9777
@michielgerretzen9777 Год назад
And very fair to say, that I would never have been able to do the deduction in box 1,4 and 7 as Simon did around 1h06m into orbit................. Chapeau!
@mojoface
@mojoface Год назад
this is a beautiful and sad rule set and i love it. thank you
@Treasier
@Treasier Год назад
I simply love Simon making super hard deductions and forget it's a sudoku puzzle. There was way easier breakthrough from box 2 if you simply did bit of sudoku and puzzle was flowing quite nicely. I actually did the part which Simon used for breakthrough last. 62mins for me, could have been even faster but I forgot some maths I did earlier in the puzzle and when I used the 1 degree of freedom in a 170 cage it took me like 20 minutes to realise I had already used it.
@felis_timon
@felis_timon Год назад
I want to join the Discord Server but when I tried it told me to do some stuff I didn't quite understand. Could someone please tell me what to do?
@lylecampbell8288
@lylecampbell8288 11 месяцев назад
The very first thing I did was sum the cages and compare it to the sum of the whole grid. This gives some constraints which I thought were important but which you did without for long time, about 45 minutes.
@devangoad
@devangoad Год назад
Amazing puzzle! I can’t believe the structure honestly
@Miniman2408
@Miniman2408 Год назад
At 1:07:58, was Simon's removal of the 3 from box 7 premature? He says that the highlighted cells (which includes those highlighted in box 7) need to include both degrees of freedom, but then discounts the silent digits in box 7?
@khoozu7802
@khoozu7802 Год назад
The highlight cells do not include the orange cells in box 7 because the orange cells in box 7 do not contribute the sum(45) to box 4
@khoozu7802
@khoozu7802 Год назад
Box 4 (45)+3 cells in box 1(6)= minimum 51 9+17+8+9+island cells(maximum 8)=51 Minimum=maximum tells us everything must fixed, so we already got 2 more degree of freedom of island cells in those highlighted cells
@FrancisFjordCupola
@FrancisFjordCupola Год назад
"Not all X's are given..." sounds like something a divorce lawyer would say.
@SkillZgetKillZ
@SkillZgetKillZ Год назад
spoiler for 1:05:00 my break past that point was a bit different I focused on the 32 cage and the 36 cage, and after going through all the ways to get 32 in 5 digits and 36 in 6, I concluded that: 1. 6 was forced to be in the 32 cage 2: because 8 and 9 were also forced into the lower 3rd of the 32 cage by their inclusion in the 36 cage 6 had to be forced in the center domino of box 1 and the corner of box 3! this ate my only degree of freedom in the 170 cage because i could no longer use 6 in the box 6 portion of it. I kinda wish i thought to calculate the 18 island maximum, although I did have 16 of the islands placed at this point and (without starting over to prove it) I don't think that would've helped me
@johnh2052
@johnh2052 Год назад
At 38:00, Simon makes a small logic error. The 32 (or 31) totals in boxes 5 and 8 only force a 9 into them. They could be 97654 (where the loss of 1 degree of freedom occurs), with the 8 joining the 2 in the 10-cage. It doesn't end up mattering, of course, because the degree of freedom is lost elsewhere.
@karlneff
@karlneff Год назад
I believe sudoku solving is typically very convergent, so it is interesting to me that Simon didn't get my first digit within his first ten.
@titusadduxas
@titusadduxas Год назад
Wow! What an amazing puzzle. I worked out most of the 170 cage straight away but made the fatal error of assuming that R3C8 was a 9! Of course that didn’t then work and took me over an hour to work out why! Finally completed it in 2:36:32!
@J7Handle
@J7Handle Год назад
Funny, I did exactly what you did and made the potential error of assuming R3C9 was a 9. I got lucky without realizing it until after the solve.
@Poet13xRatedRKO
@Poet13xRatedRKO Год назад
80 minutes for me. I spent over half an hour for the break-in which had to be the 170, of course, I was too slow. Let me explain: sum(cages)=376 which is 405-29, so the island cells have 2 degrees of freedom (27+2=29), so the maximum value for an island cell is 4. The 170 cage has a maximum ocean cells of 9+30+42+32+32+26=171 so there is one degree of freedom which disappears by combining it with the 21 cage. After that, you can color a lot of ocean cells and the rest is easy. Thanks for the great puzzle despite there was no 3 in the corner!
@mrsawiggins
@mrsawiggins Год назад
I love how Simon only shares the secret of sudoku with his favorite people...every. Single. Video.
@Gonzalo_Garcia_
@Gonzalo_Garcia_ Год назад
24:07 for me. What an awesome puzzle, loved it!!
@Hans_Robert
@Hans_Robert 10 месяцев назад
gotta love how Simons relies its global Suduku rules 44:35 into the puzzle in a sudoku named Global Ocean
@Novellous210
@Novellous210 Год назад
At 48:07 you included maveric into your calculations which as a long time fan of the channel made me laugh
@mattlafy
@mattlafy Год назад
I'm pretty sure the 8 corner marks in box 5 at 38 minutes is unfounded. The ten cage being 82 rather than 46 would use up the 1 degree of freedom by forcing the islands to 13, but wouldn't break yet.
@ashnikchauhan9103
@ashnikchauhan9103 Год назад
[Mild SPOILERS] If only Simon had spent a bit more time on the 21 and 170 cages, this would have gone a lot smoother. Though I admire his patience and resilience in the face of daunting puzzles because due to some quick faulty logic in box 1, I had to redo all the logic from scratch and the mistake I made was - I just assumed that 89 pair goes in r1c1 and r2c1 as it was seeing the 89 pair in r1c6 and r2c6. (1:21:55 see simon tackle it correctly) So solvers beware this ocean island sudoku is not that easy so tread carefully and don't pencil mark it to the brim. Keep on cracking.
@Kinada
@Kinada Год назад
Something about that puzzle made me screw it up multiple times in stupid ways and I had to redo stuff. I guess seeing the opener really quickly had me go too fast. The 170 cage was the right place to look, you just overlooked how the 21 cage removes the degree of freedom and lets you max out the rest of the cage.
@blocksy6772
@blocksy6772 Год назад
Nice debut Samu!
@SamuPiano088
@SamuPiano088 Год назад
Thank you Blocksy! :)
@TomMalufe
@TomMalufe Год назад
I didn't attempt this puzzle, but I did see a better way to start looking for islands at least. I just added up all the cages (376) and subtracted that from 45x9 (405) to get 29. So we know the 18 islands only add up to 29 which means they have to be mostly 1s and 2s.
@neokart2660
@neokart2660 Год назад
Nice puzzle and very good video. Excuse my English, but I will explain part of my solving path. I started by analyzing boxes 5,6,7,8 and 9 (total sum: 5x45=225); together with cages 10,16,10,21 and 170 (oceanic sum (os): 10+16+10+21+170=227). So: the oceanic sum of boxes 5,6,7,8 and 9 is: OS(box5to9)=227- os(r3c8;r3c9), but also: OS(box5to9)=225-(islands U [r7c2;r7c3 ;r4c4;r4c7]) So: os(r3c8;r3c9)=2+(islands U [r7c2;r7c3;r4c4;r4c7]) The left part is max. 9+8=17. The right part is minimal when [r7c2;r7c3;r4c4;r4c7] is included in the set of islands and they have minimum values: 2+(1+2)x5=17. BINGO. Equality will hold only under those conditions. This not only immediately concludes that r7c2;r7c3;r4c5;r4c7 are islands, but that each of the islands in boxes 5,6,7,8, and 9 contains only the digit 1 or 2.
@andrewmccullough2091
@andrewmccullough2091 Год назад
7:13 Happy Birthday to Heather, Holly and Hope Newbury! Hope y’all are doing well. It’s such a small world to hear about people you went to high school with from someone across the pond. Tell Hope that sudoku variants are not only great fun but also help people our age keep our brains stimulated. Although, fortunately some of us get to wait a year for the big 5-0.😉🎉 Andy
@champioz
@champioz Год назад
Oh god, I solved this the other day and it never even occurred to me to do the global sum step. As soon as you said "Oh no..." I was like wait...CRAP
@OtjPlateo
@OtjPlateo Год назад
at 34:57 you put an 89 in the cage that sums up to 21. This removes the option of the 89 next to it (the one in the top of the 170 cell) to be an 8 (it would take at least 2 degrees of freedom, we only have 1). I believe the puzzle was supposed to be started from there.
@stevieinselby
@stevieinselby Год назад
Putting an 8 in r3c9 only removes one degree of freedom from the 170 cage, not 2, because it doesn't restrict what goes into the cage in box 6 ... it can still be maximum of 6-7-8-9 totalling 30, whether the caged cell in box 3 is an 8 or a 9.
@JimOMoore
@JimOMoore Год назад
@@stevieinselby No, because you must have 789 in the cage within box 6, so as soon as you put an 8 in r3c9 you would have to put 8 into r6c8, and you have now used 2 degrees of separation. Ergo they must both be 9s.
@AndreasKungl
@AndreasKungl Год назад
Very hard for me, but I cracked it! [...and I didn't even realize that you are supposed to calculate the sum of island cells; somehow never thought about the bleedin' obvious...]
@MateoMusic
@MateoMusic Год назад
4:56 PLEASE record a video of you solving the 100x100 crossword. Or do a live stream! It could be one of those eight-hour livestream marathons for charity! PLEASE.
@kaiwen338
@kaiwen338 Год назад
Nice solve. Large cage totals are not too fun, but this was a well-crafted puzzle.
@Foxyjosh
@Foxyjosh Год назад
All those 1s and 2s on islands make me think of the song "One" "One is the loneliest number that you'll ever do Two can be as bad as one, it's the loneliest number since the number one"
@dannstarrjp
@dannstarrjp Год назад
37:50 I don’t think I understand why we have to have 8 and 9 in c5 box 5. I think the orange cells in box5 have to be 13 or 12 pair (because of 1 degree of freedom) but in case they are 13 pair doesn’t it mean we can still have a 82 in the 10 cage?
@tunamonkey
@tunamonkey Год назад
If R3C9 and R6C8 are the same and we only have 1 degree of freedom in the 170 cage can we not say at least 1 (and thus both) must be 9? I feel like I'm overlooking some obvious reason that doesn't work
@jakejarvis6683
@jakejarvis6683 Год назад
I'm just intelligent enough to follow Simon's logic, and just dumb enough to not be able to discover it on my own.
@thezanycat
@thezanycat Год назад
Took me 2.5 hours, one of the hardest I've done on this channel tbh
@emirspahic2886
@emirspahic2886 Год назад
Hope someone reads this and can answer; if Simon was able to put the 2 by the X clue in by simply having to put the 7 and the 2 as the maximum value for their cage, how come the X Clue is nececary at all? he didnt need the 10-sum at all to resolve it, how is it required in the puzzle then? i am sure i am missing something....
@psymar
@psymar Год назад
I somehow got this in half the time. For me the key was looking at combinations of the 170 cage with other cages that would help fill in the rest of a box or row. I finally computed that, taken together, the 170, 25, 21, and two 10 cages have a total of 236, while comprising 7-9 cells in each of 5 boxes (thus having a max of 42 each) and a max of 3+4+5+6+8 in the lower-left box -- which, as it turns out, works out to 26+5*42 = 236. Meaning there's absolutely no degrees of freedom for any of that, giving most of the ones and twos. And, as it turns out, you can also do this without the 25 cage, because once the 1 and 2 are ruled out, the 25 cage has to be 3-4-5-6-7. Then I got carried away with some maths and I think my first digit was actually the top-right cell!
@yans7397
@yans7397 Год назад
1:07:59 I do not understand why there has to be a 12 pair in box 7 and it can not be a 13 pair. Is the degree of freedom already used up somewhere else in the 170 cage at this point? Could someone explain?:)
@RichSmith77
@RichSmith77 Год назад
From 1:03:35, Simon is using the minimum value for the cells highlighted as being 45 (box 4) + (1+2) (box 7) + (1+2+3) (box 1) = 54. The only way 54 works is with an 8+9 pair in r4c2-3 and using the two degrees of freedom available in non-counting islands (8+9+9 (cages) + 17 + 11 = 54). None of those can be increased. So 54 is also the maximum for the set of cells. Since maximum (54) equals the minimum (54), they're forced to be what he first hypothesised to reach his minimum total, i.e. a 123 triple in r3c1-3, and a 12 pair in r7c2-3. I had to pause the video to understand that point myself. It wasn't immediately obvious to me.
@khoozu7802
@khoozu7802 Год назад
The highlight cells do not include the orange cells in box 7 because the orange cells in box 7 do not contribute the sum(45) to box 4
@khoozu7802
@khoozu7802 Год назад
Box 4 (45)+3 cells in box 1(6)= minimum 51 9+17+8+9+island cells(maximum 8)=51 Minimum=maximum tells us everything must fixed, so we already got 2 more degree of freedom of island cells in those highlighted cells
@RichSmith77
@RichSmith77 Год назад
@@khoozu7802 ? Look at timestamp 1:03:30. Simon has selected a region containing 14 cells. Those ARE the highlighted cells, the ones Simon is talking about, and it very much includes the orange cells in box 7. 🙂 They're part of the 9 cage, needed in the calculation of the maximum of 54, using two available degrees of freedom in uncounted cells, for the 14 cell region. Minimum for uncounted cells in three boxes is 3*(1+2)=9. So maximum uncounted cells, using two degrees of freedom, is 9+2=11. The maximum in r4c2-3 is 8+9=17. Cages sum to 8+9+9=26. So the maximum overall is 11+17+26=54. This is the same as the minimum, when the orange cells in box 7 are 1,2 and the three cells in box 1 are 1,2,3. I'm just explaining Simon's logic used in his solve. Maybe there's another way to do it, but Simon's way works.
@RichSmith77
@RichSmith77 Год назад
@@khoozu7802 (Isn't one of your 9s in "9+17+8+9+island cells" from the 9 cage that includes the orange cells in box 7?) Edit: Nevermind. Orange cells are already known to be uncounted cells. That's why you can treat the 9 cage as if it were only in box 4. Your way works too.
@Raven-Creations
@Raven-Creations Год назад
The easiest way to think about the totals in boxes 5 and 8 are that the 10 cage plus two islands of 12 account for 13, therefore the maximum contribution to the 170 cage is 32 from each box. In box 7, the maximum is 45-16-3=26. It all adds up to an annoying 171. However, in box 6, if we use 6789 in the 170, we only have 15 to use on the rest, which, if it includes two islands of 12, there is just twelve left for the 21 cage, which would require a 9 in box 3 (using up the degree of freedom). This means the degree of freedom is entirely used up in boxes 3 and 6. This is the crucial deduction you missed, which would have saved you an awful lot of time. We know the degree of freedom is used up either by making R3C9=9, with the 170 cells in box 6 being 5789, or by R3C9 being 8, with the cells of the 170 cage in box 6 being 6789. This means all of the island cells in boxes containing part of the 170 cage must be 12s. We can place 12s in R4C4, R6C6, R4C7, R7C2/3, and we can put a blue 89 pair in R3C8/9. This forces the 25 cage in box 3 to be all counting 3-7, putting island 12s in the 30 cage, forcing it to be 6789. @ 29:58 "Maybe I can prove this is an island" - that's easy. You can't afford to have two more islands in the 21 cage or you'd never make the total. I found the 376 cage total was quite useful, because it stopped me running away with the idea that all islands were 12s. I was able to place most 12s, and whilst I knew most were islands, it was tempting to think they all were, which would have been a mistake. Knowing that not all 12s were islands alerted me to be careful. It was also useful, because it meant there couldn't be a non-counting 9 in the 8 or 9 cages. @ 1:13:22 - considering where the islands are in box 1 - if the 3 were not an island, you'd have 12s as islands in both boxes 1 and 4, which would break your degrees of freedom. The 3 therefore has to be island, with a 1, so there must also be a 13 island pair in box 4. Because I spotted the restriction with the 21 cage using up the degree of freedom, I found this considerably easier, however it was still no pushover. It was definitely a very nicely set puzzle, and using the 21 cage logic, it had quite a nice flow (e.g. the 89 pair in box 3 forcing the 25 cage, which in turn forced the 30 cage in box 2). What an auspicious debut puzzle.
@nad2040
@nad2040 Год назад
1:17:09 if the 1 and 2 in box 1 are both islands, that means the 1 and 2 in box 4 both become islands. That is impossible. So, the 3 in box 1 is an island.
@themiddleones11
@themiddleones11 Год назад
36:25 for me Found out those degrees of freedom breakins earlier Also added up everything in boxes 5-9 plus r3c8&9 to realize all of those were 1s and 2s
@honestyy1354
@honestyy1354 Год назад
cannot believe he found a second way to see the 2 island cells in column 7 without actually seeing them. that was so irritating
@michielgerretzen9777
@michielgerretzen9777 Год назад
So funny. For once in a life time, I came 45 minutes earlier than Simon to the observation that the sum of all cages + non counting cells = 405, hence ..... (non counting cells not adding up to 27 but to a bit higher sum). This will never happen to me again :-)
@Rach881101
@Rach881101 Год назад
100:09 for me. Marvelous puzzle!
@longwaytotipperary
@longwaytotipperary Год назад
Amazing!
@HalcyonAcorn
@HalcyonAcorn Год назад
So Simon, when will we see you tackle the crossword?!! I expect it should only take you a couple videos!!
@einarkringlebottenolsen9610
Great video, I think the trouble you had in box 4 came from the fact that you made them green, you would have seen it faster if you left them uncolored I bet
@andybenedict9633
@andybenedict9633 Год назад
I just realized that the first deduction I made on this puzzle might have been very, very premature and only ended up being correct by accident :( . I marked both cells on the X as counting, but after re-reading the rules, I realize that it says the non-counting cells don't count toward cage totals, but doesn't mention them not counting toward the X...
@jellevm
@jellevm Год назад
Remarkably, this one took me almost exactly 170 minutes!
@Askovsende
@Askovsende Год назад
One degree of freedom - c9r3 & c7r6 are the same... Well then you can't make both 8, that would use 2 degrees of freedom... Yelling for an hour :D Love it :)
@BOTHLine
@BOTHLine Год назад
I thought the same for quite some time.. but actually if it was an 8 in the 3rd box, it would just move the 9 in the 6th box to the right column.. which wouldn't use up the other degree of freedom. You had 8 + 9 in box 6 anyway, no matter if the other digit was a 9 or an 8.
@LifelineSoF
@LifelineSoF Год назад
That is not true. If both are 8 you can still put 6,7,8,9 in box 6 inside the 170 cage. Therefore making both an 8 only reduces the total by 1.
@asliceofjackie91
@asliceofjackie91 Год назад
You could've much more easily proven R4C1/2/3 by noting that R4C1 couldn't be an 8 or a 9. A 9 would break the cage total since we know there's another counting cell, and an 8 would require a 1 to it which we already know is a non-counting cell. Thus only 6/7 were left as options, making the other two the 8/9 pair we're looking for.
@badrunna-im
@badrunna-im Год назад
After getting the total of the island cells, I ignored the 170 cage, focused on box 4, which completely restricted the islands in the other columns and spiralled out from there. Much simpler arithmetic that could've halved Simon's time.
@rdesmarais2
@rdesmarais2 Год назад
Funny 45:50 that is the first thing I thought of. Not that I could complete it without help even knowing that.
@srikanthsharma7551
@srikanthsharma7551 Год назад
63:08 of pure joy!!
@MeNanWazaHowitzer
@MeNanWazaHowitzer 10 месяцев назад
Left it so long to spot the second island in box 6 🤦‍♂️, not that i would have got that far
@DLH208
@DLH208 Год назад
Where am I going wrong? There is one degree of freedom in the 170 cage. The 21 cage and the 170 cage have an 89 pair at the top. The 89 pair must repeat in r6c8. The 89 pair at the top of the 21 cage (r3c8) looks at both the other pairs. Doesn't that mean that the two members of the 170 cage are either both eight or both nine? If so, they must both be 9 because otherwise we loose two degrees of freedom, not one! If true, this is available fairly soon. And yes this is a kind remark, if not very kind. 😍
@przemekmajewski1
@przemekmajewski1 11 месяцев назад
46:20 if the sum of all the islands was 21, then all boxes in the 170 cage would be maximized and then the 170 cage would be 171... good the sum was 29... :)
@HunterJE
@HunterJE Год назад
Wait, BLUE water? How absurd!
@titusadduxas
@titusadduxas Год назад
I very quickly worked out the 170 cage and was flying along until I got to the 36 cage! I just couldn’t resolve it despite everything appearing to be forced up til that point! Very frustrating.
@MattYDdraig
@MattYDdraig Год назад
With the 36 cage, once the 1 and 2 are eliminated from being in the cage it is clear that 6 must be the other "missing digit" which quickly resolves r1c9 and opens up a lot.
@titusadduxas
@titusadduxas Год назад
@@MattYDdraig Yes - I’d made made the wrong assumption that R3 C8 was the 9 - I subsequently realised that couldn’t be the case as it made the 170 cage add up to 169!
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