The EASY WAY to do a Timber Post Calculation 

✅Get the timber tables here: geni.us/timbercalculation

Well explained. Thank you Robin, you r doing a great job. Please keep posting more video. You are a mentor to me. 🙂

Thank you so much for sharing!

Well explained…👌👍🏻

Hi Robin many thanks for the video, I’m doing a similar design for a friend but wondered if I need to take in to consideration the bending caused by the loading from the front (horizontal) beam?

Thank you sir, what about internal chords ? How to determine them ?

Thanks for posting Robin. Could you help me understand what factors were used to produce a compressive strength value of 7.9 N/mm2,for C24 down from 21 N/mm^2 from the BS EN 338 table. I suppose material factor, load duration factor etc will come into play however I seem to be missing something

Hi Robin, thank you very much for this very clear explanation. Do you have a video that will help me with the following. I am retired and a volunteer at a local farmland museum. We would like to build a capony over a pair of dounble doors to make the entrance to the cafe more attractive. Unfortunately the building is clad i asbestos, which i want to avoid fixing to. My plan is to build the canopy on gallows brackets mounted on posts either side of the entrance. the posts will be 1.8Mtrs apart and the highest point i can affixe them to the wall is 1.2 mtrs before i meet the asbestos. The height to the top of the brackets will be in he order of 2.2 Mtrs. How do I calculate the size of he posts to minimise the deflection of the posts under the weight of the canopy (pitched roof canopy) to prevent a permanent gap appearing between canopy and asbestos wall. I intend using a flexible sealant between.

Hi... can you explain why the answer is different using Pcr=pi^2*EI/L^2 ? Should they be the same?

in relation to tensile tension do you explain? and that I am doing a work on tensile stress in wooden structures, and this complicated to find know where I can find an example with the calculation?

Great video. Can you please post the link to the chart you used.

When you have to watch a bunch of other videos just to understand half of what this video said 😂

Thank you very much for the video. Im planning a storage floor type of construction for my workshop, which is why i wanted to calculate the maximum allowable weight i could store up there.I study mechanical engineering so i dont have much to do with wood. I had a look at the german version of en 338 and under "Druck in Faserrichtung" (compression parallel to grain, f(c,0,k)) it sais 21N/mm^2, which is obviously much more than the value you used. Is there something im missing here? What is the reason for this huge discrepancy? This is especially confusing because the youngs modulus values are very similar. In the 2016 version of the german en 338 the mean youngs modulus for c24 timber is 11 kN/mm^2 and the minimum is 7,4kn/mm^2. Do your allowable stress values already have a safety factor included in them?

Great video. The link does not appear to work. Can you please check please, thank you in advance

what does C24 mean technically .

Although I know what you mean, your phrasing is open to interpretation. 9025 mm squared is 81,450,625 square mm. Saying 9025 square mm for an area , cannot be confused

De John? Dutch..